Aptitude - Decimal Fraction - Discussion
Discussion Forum : Decimal Fraction - General Questions (Q.No. 9)
9.
| (0.1667)(0.8333)(0.3333) | is approximately equal to: |
| (0.2222)(0.6667)(0.1250) |
Answer: Option
Explanation:
| Given expression |
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| = 2.50 |
Discussion:
43 comments Page 2 of 5.
Samreen said:
9 years ago
It's given as 0.1667, not as 0.166666. So how can you take as 0.16 bar.
Rajeshdharamdasani said:
9 years ago
How 0.1250 = 1/8? Please explain me.
Ramesh said:
9 years ago
Here is the thing.
x = .8333 can be converted as 100x = 83.3333 and 10X = 8.3333, and why so because we need to focus on how many decimals are recurring here it's just one(3) and so we need to remove that.
Always put recurring part behind the decimal (here by multiplying with 10) .and this way the result comes out to be 83 - 8/90 = 75/90 = 5/6 and 0.1250 = 125/1000 = 1/8.
x = .8333 can be converted as 100x = 83.3333 and 10X = 8.3333, and why so because we need to focus on how many decimals are recurring here it's just one(3) and so we need to remove that.
Always put recurring part behind the decimal (here by multiplying with 10) .and this way the result comes out to be 83 - 8/90 = 75/90 = 5/6 and 0.1250 = 125/1000 = 1/8.
Ramesh said:
9 years ago
In simple words for recurring decimals keep recurring values behind the decimals and assume it as your starting point.
X=.83333 so let's assume Z= 8.3333 and you know Z=10X ,and now solve Z and you will get Z = 75/9.
And later you can solve for X which will be 10X = 7.5/9 or X = 75/90.
X=.83333 so let's assume Z= 8.3333 and you know Z=10X ,and now solve Z and you will get Z = 75/9.
And later you can solve for X which will be 10X = 7.5/9 or X = 75/90.
Abchamp said:
9 years ago
Thank you @Brk.
Sai Manohar said:
9 years ago
Cant we solve using round off method like
(2 * 8 * 3)/(2 * 7 * 1) = 3.4.
Am I right?
(2 * 8 * 3)/(2 * 7 * 1) = 3.4.
Am I right?
Leul said:
8 years ago
Any other simple method?
Varsha said:
7 years ago
Thanks @Sai Manohar.
Satish said:
1 decade ago
0.1667 can be treated as 0.16666 since they are asking for approximate values.
Shubham said:
7 years ago
I am not getting the solution of this. Please, anyone explain me clearly.
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