Aptitude - Decimal Fraction - Discussion

Thanks @Deepak.

These type of problems can be solved by Cross Multiplication principle.

I will try to explain with the present problem scenario

Consider (1/3) and (2/5)

STEP 1: Multiply numerator of 1st with denominator of 2nd
Multiply denominator of 1st with numerator of 2nd

STEP 2: The result is (1*5) and (3*2)
i.e.., 5 and 6
Now Check which number is greater of the two.
In this case 6>5
STEP 3: Check which fraction's numerator is part of the product
that results in greater number(6)

In this case 6 has numerator of 2nd fraction (2/5)
So we can say that (2/5) >(1/3)

SO ON WITH THE NEXT FRACTIONS ALSO

If the numerator is increasing by a constant number the smaller the numerator the smaller the fraction.

@All.

A B and C options start with 1/3.

This means they are in ascending order
only D starts with 6/7,
This is arranged in descending order.
So, D is the answer.

In the first three numbers, the difference between the numerator and the denominator are same and the denominator is greater than numerator if there is a condition like this, then if the numerator is lesser, the value is lesser.

For the first three option take the 1st and last digit, then compare the two digit.

For option a), b)and c)
1/3=0.3333 and 6/7=0.8571, now we can see that 1st one is smaller then last one.

So they are not in descending order.

Hence answer is the rest means option D).

Easy trick for solving this type of question 1st take difference of numerator and denominator and arrange them according to there acceding and descending order and respective fraction is answer of question if deference is common between 2 fraction then select greater base between them is higher value fraction.

6/7*5/6 cross multiplication.

36, 35 (6/7 = 36, 5/6 = 35).

6/7 > 5/6.

@Umesh.

Your trick is not applicable for all types of questions.

It will work only when difference between the given numerator is equal.

It is very easy. Among all option check out the last and first number you will get answer.