Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 7)
7.
At what time between 5.30 and 6 will the hands of a clock be at right angles?
Answer: Option
Explanation:
At 5 o'clock, the hands are 25 min. spaces apart.
To be at right angles and that too between 5.30 and 6, the minute hand has to gain (25 + 15) = 40 min. spaces.
55 min. spaces are gained in 60 min.
| 40 min. spaces are gained in |  |
60 | x 40 |  min |
= | 43 | 7 | min. |
| 55 | 11 |
 Required time = 43 |
7 | min. past 5. |
| 11 |
Discussion:
76 comments Page 7 of 8.
Dinesh said:
1 decade ago
Thank you Reddilavan.
Naresh said:
1 decade ago
@red
You are great
You are great
Deepika said:
1 decade ago
There is a direct formula for it...
30xH + 11/2xM where H is for hours and M is minutes..
for e.g. in 4.20 pm....
H= 4
M= 20
30xH + 11/2xM where H is for hours and M is minutes..
for e.g. in 4.20 pm....
H= 4
M= 20
Abhiram said:
1 decade ago
@Akki, The given question is hands must be in right angles so 90 degrees is taken.
@Shree, You can take any f the formula but take care not to get a -ve theta if it comes -ve then take another formula ts as simple as such.
@Shree, You can take any f the formula but take care not to get a -ve theta if it comes -ve then take another formula ts as simple as such.
Siri said:
1 decade ago
Acc to formula in 60 min we gain 55 spaces
So, for 1min = ?
60min=55 gains
1min=?
so by cross multiplicatn
we get
60/1x55=60/55
So, for 1min = ?
60min=55 gains
1min=?
so by cross multiplicatn
we get
60/1x55=60/55
Madhu said:
1 decade ago
A right angle is an angle that bisects the angle formed by two halves of a straight line is called right angle and the angle between the two halves is 90 degrees. In the given problem handles of clock are in right angle so we take 90 degrees angle.
Akki said:
1 decade ago
@Reddilavan how you got 90degree angle
Shree said:
1 decade ago
Hey in some prob we are using theta=30h-11m/2 and here reddilavan has mentioned theta=11m/2-30h. How we knew in which prob which formula must be used na? Can any one explain me.
Chandra shekar said:
1 decade ago
How did you get the fraction 60/55 in the above the calculation ?
Abhishek said:
1 decade ago
@Reddilavan
It seriously a gud formula... we would be obligeed if we have more such formulae from your end.
It seriously a gud formula... we would be obligeed if we have more such formulae from your end.
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