Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 7)
7.
At what time between 5.30 and 6 will the hands of a clock be at right angles?
43 5 min. past 5
11
43 7 min. past 5
11
40 min. past 5
45 min. past 5
Answer: Option
Explanation:

At 5 o'clock, the hands are 25 min. spaces apart.

To be at right angles and that too between 5.30 and 6, the minute hand has to gain (25 + 15) = 40 min. spaces.

55 min. spaces are gained in 60 min.

40 min. spaces are gained in 60 x 40 min = 43 7 min.
55 11

Required time = 43 7 min. past 5.
11

Discussion:
76 comments Page 5 of 8.

Krish said:   1 decade ago
I have the same doubt as @Margaret said. Please anyone explain it.

Nagu said:   10 years ago
Why the spaces are same for 5'clock and 7'clock == 25 spaces?

In which direction we have to take the spaces clock wise or anti clock wise?

Abc said:   10 years ago
Superb formula. Thanks alot.

Adi said:   10 years ago
Dear sir,

Please prove formula.

Prashanth said:   10 years ago
If the minute hand is present before hour hand then use theta = 11/2min-30hr.

Like that hour hand is before minute hand theta = 30hr-11/2hr.

Use it you will get exact solution.

Lakhan singh meena said:   9 years ago
Direct formula:

6*x - 90 = 30(y + x/60);

Where y = 5 hr.

So 6x = 30(5 + x/60) + 90;

x = 43(7/11)min. past 5.

Tilak Dewangan said:   9 years ago
Sorry @Riddilavan your formula may wrong if you solve this question.

How many minutes after 7 o'clock and before 8'o clock will the hands of the clock be in opposite direction?

Prithvi said:   9 years ago
Thanks @Harry.

Kumar said:   9 years ago
Since for 1 hour, the minute's arm move 360 degrees. And for each hour arm move 30 degrees.

Hence for every 1 degree move the minute's arm move 12 degrees.

When the time is 5 : 30 the angle between the min arm and hour arm is 15 degree.

Our target to find a time when the angle is 90 degree.

For this, we solve the equation :12x - x + 15 = 90.

From here we get x = 75/11.

30 degree = 1 hour.

75/11 degree = 1/30 * 75/11 = 5/22hours = 300/22min.

Hence final time is 30 + 300/22 = 480/22 min from 5 o'clock. (we add 30 because we have considered the arms move from 5:30).

Mounika said:   9 years ago
I was getting confused in using the formula.

But your answer helps me, Thankyou @Prashanth.


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