Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 7)
7.
At what time between 5.30 and 6 will the hands of a clock be at right angles?
Answer: Option
Explanation:
At 5 o'clock, the hands are 25 min. spaces apart.
To be at right angles and that too between 5.30 and 6, the minute hand has to gain (25 + 15) = 40 min. spaces.
55 min. spaces are gained in 60 min.
| 40 min. spaces are gained in | ![]() |
60 | x 40 | min |
= | 43 | 7 | min. |
| 55 | 11 |
Required time = 43 |
7 | min. past 5. |
| 11 |
Discussion:
76 comments Page 4 of 8.
Diksha Mishra said:
6 years ago
Please, someone, share the solution of how come40*60÷55 = 7÷11 came ? Pls someone explain it..
Yuvrajsinh said:
10 years ago
Friends please help me, I don't know this chapter.
Ajay said:
6 years ago
Thank @Ajay.
Ashu said:
9 years ago
How can you get 11/2 in the formula?
Can anyone help me? Please.
Can anyone help me? Please.
Arpita Saxena said:
9 years ago
I didn"t understand this solution. Can anyone please explain?
Jeet said:
9 years ago
At 5.30, Angle between hands is 15 degree and 75' more required to make a right angle. Relative angle made by hands is 11/2 ' in a minute.
We can assume in x min they cover remaining 75.
So 11/2 * x = 75.
x = 150/11 min.
So at 30 + 150/11 min, they make a right angle.
We can assume in x min they cover remaining 75.
So 11/2 * x = 75.
x = 150/11 min.
So at 30 + 150/11 min, they make a right angle.
Jonas palmiano said:
1 decade ago
What time after 4 o'clock will the hands of the clock be at right angle? Please help.
Vijaya said:
8 years ago
I don't understand how, 15 m gain? please anyone explain it.
Saravana said:
8 years ago
How the calculation (60\55)*40 = 43*7/11?
Siddharth Pandey said:
8 years ago
Tell me both the times at which der will be 90-degree b/w min hand and second hand between 1 AM/PM to 2 AM/PM using the formula mentioned above. Does this formula work for given timings?
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min
Required time = 43