Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 7)
7.
At what time between 5.30 and 6 will the hands of a clock be at right angles?
Answer: Option
Explanation:
At 5 o'clock, the hands are 25 min. spaces apart.
To be at right angles and that too between 5.30 and 6, the minute hand has to gain (25 + 15) = 40 min. spaces.
55 min. spaces are gained in 60 min.
40 min. spaces are gained in | ![]() |
60 | x 40 | ![]() |
= | 43 | 7 | min. |
55 | 11 |
![]() |
7 | min. past 5. |
11 |
Discussion:
76 comments Page 3 of 8.
Appu said:
8 years ago
At 5:30, the hands are 55 mins apart.To get an angle 90 btw them space must 15 mins apart,
so, the space is 55-15=40.
therefore,60/55-40=43 7/11.
so, the space is 55-15=40.
therefore,60/55-40=43 7/11.
(2)
Jeet said:
8 years ago
At 5.30, Angle between hands is 15 degree and 75' more required to make a right angle. Relative angle made by hands is 11/2 ' in a minute.
We can assume in x min they cover remaining 75.
So 11/2 * x = 75.
x = 150/11 min.
So at 30 + 150/11 min, they make a right angle.
We can assume in x min they cover remaining 75.
So 11/2 * x = 75.
x = 150/11 min.
So at 30 + 150/11 min, they make a right angle.
Arpita Saxena said:
8 years ago
I didn"t understand this solution. Can anyone please explain?
Ashu said:
8 years ago
How can you get 11/2 in the formula?
Can anyone help me? Please.
Can anyone help me? Please.
MATH EXPERT said:
9 years ago
FORMULA :
Guess P = ANS .
(11/2) x (minutes) - 30 x (Hours) = 90 degree.
11/2 x P - 30 x 5 = 90,
P = 480/11= ANS.
Guess P = ANS .
(11/2) x (minutes) - 30 x (Hours) = 90 degree.
11/2 x P - 30 x 5 = 90,
P = 480/11= ANS.
(1)
Yuvrajsinh said:
9 years ago
Friends please help me, I don't know this chapter.
Mounika said:
9 years ago
I was getting confused in using the formula.
But your answer helps me, Thankyou @Prashanth.
But your answer helps me, Thankyou @Prashanth.
Kumar said:
9 years ago
Since for 1 hour, the minute's arm move 360 degrees. And for each hour arm move 30 degrees.
Hence for every 1 degree move the minute's arm move 12 degrees.
When the time is 5 : 30 the angle between the min arm and hour arm is 15 degree.
Our target to find a time when the angle is 90 degree.
For this, we solve the equation :12x - x + 15 = 90.
From here we get x = 75/11.
30 degree = 1 hour.
75/11 degree = 1/30 * 75/11 = 5/22hours = 300/22min.
Hence final time is 30 + 300/22 = 480/22 min from 5 o'clock. (we add 30 because we have considered the arms move from 5:30).
Hence for every 1 degree move the minute's arm move 12 degrees.
When the time is 5 : 30 the angle between the min arm and hour arm is 15 degree.
Our target to find a time when the angle is 90 degree.
For this, we solve the equation :12x - x + 15 = 90.
From here we get x = 75/11.
30 degree = 1 hour.
75/11 degree = 1/30 * 75/11 = 5/22hours = 300/22min.
Hence final time is 30 + 300/22 = 480/22 min from 5 o'clock. (we add 30 because we have considered the arms move from 5:30).
Prithvi said:
9 years ago
Thanks @Harry.
Tilak Dewangan said:
9 years ago
Sorry @Riddilavan your formula may wrong if you solve this question.
How many minutes after 7 o'clock and before 8'o clock will the hands of the clock be in opposite direction?
How many minutes after 7 o'clock and before 8'o clock will the hands of the clock be in opposite direction?
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