Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 2)
2.
The reflex angle between the hands of a clock at 10.25 is:
180°
192 1 °
2
195°
197 1 °
2
Answer: Option
Explanation:

Angle traced by hour hand in 125 hrs = 360 x 125 ° = 312 1 ° .
12 12 12 2

Angle traced by minute hand in 25 min = 360 x 25 ° = 150°.
60

Reflex angle = 360° - 312 1 - 150 ° = 360° - 162 1 ° = 197 .
2 2 2

Discussion:
269 comments Page 8 of 27.

Sathish said:   1 decade ago
Thank you sundar.

Aparna said:   1 decade ago
Thanks a lot Venu. Lekkala and Sumit.

Avinash said:   1 decade ago
@Umesh

Your answer is quite good man! Thank you.

Deepa said:   1 decade ago
@umesh

Why did you multiply 30 to 5/12?

Gobi said:   1 decade ago
@Deepa

Because 30 degree is to mention for one hour so the angle traced out in (1 hr= 30 degrees) * (25 min ie., 25/60 hrs) = 25/2.

Gopal said:   1 decade ago
Thank you Venu. Lekkala.

B.Vamsi Srinivas said:   1 decade ago
Have a look at my solution once...

Time 10:25

Reflex Time...
11:60
-10:25
~~~~~~~
1:35

formulae to find angle

Angle = 11*(m)
---- - 30(h)
2
m = minutes
h = hours

so
now

11*35
= ----- - 30* 1
2


385 - 60
= --------
2

325
=---
2

1
=167 ---
2

Correct me if I'm wrong.

Nandhini said:   1 decade ago
This is the formula to calculate the angle.

Angle = min*(11/2)-30*hour.

Mayur said:   1 decade ago
Simple solution.

At 10 o'clock angle between them = 300

for 25min displacement between them = 25*5.5 = 137.5

so, angle between them = 300-137.5 = 162.5

for reflex angle = 300-162.5 = 197.5

Ravi said:   1 decade ago
Angle traced in 1 hour=360/12=30 angle
Angle traced in 10 hours=30*10=300 angle
Angle traced in 25min=25/60hour=30*25/60 angle=25/2=12.5 angle=12(1/2)

total Angle traced in 10hour25min=300+12.5 angle =312(1/2)


Angle traced by minute hand in 25 min =(360/60)*25=150 angle
hence 312(1/2)-150=197.5=197(1/2)


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