Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 2)
2.
The reflex angle between the hands of a clock at 10.25 is:
180°
192 1 °
2
195°
197 1 °
2
Answer: Option
Explanation:

Angle traced by hour hand in 125 hrs = 360 x 125 ° = 312 1 ° .
12 12 12 2

Angle traced by minute hand in 25 min = 360 x 25 ° = 150°.
60

Reflex angle = 360° - 312 1 - 150 ° = 360° - 162 1 ° = 197 .
2 2 2

Discussion:
270 comments Page 8 of 27.

Sandy said:   1 decade ago
From the above example, we have already got the answr for 10.25 in hour hand, then why we agin find the deg for minute hand that too only for 25 min not 10 hours? please clear my doubt.

Sathish said:   1 decade ago
Thank you sundar.

Aparna said:   1 decade ago
Thanks a lot Venu. Lekkala and Sumit.

Avinash said:   1 decade ago
@Umesh

Your answer is quite good man! Thank you.

Deepa said:   1 decade ago
@umesh

Why did you multiply 30 to 5/12?

Gobi said:   1 decade ago
@Deepa

Because 30 degree is to mention for one hour so the angle traced out in (1 hr= 30 degrees) * (25 min ie., 25/60 hrs) = 25/2.

Gopal said:   1 decade ago
Thank you Venu. Lekkala.

B.Vamsi Srinivas said:   1 decade ago
Have a look at my solution once...

Time 10:25

Reflex Time...
11:60
-10:25
~~~~~~~
1:35

formulae to find angle

Angle = 11*(m)
---- - 30(h)
2
m = minutes
h = hours

so
now

11*35
= ----- - 30* 1
2


385 - 60
= --------
2

325
=---
2

1
=167 ---
2

Correct me if I'm wrong.

Nandhini said:   1 decade ago
This is the formula to calculate the angle.

Angle = min*(11/2)-30*hour.

Mayur said:   1 decade ago
Simple solution.

At 10 o'clock angle between them = 300

for 25min displacement between them = 25*5.5 = 137.5

so, angle between them = 300-137.5 = 162.5

for reflex angle = 300-162.5 = 197.5


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