Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 2)
2.
The reflex angle between the hands of a clock at 10.25 is:
Answer: Option
Explanation:
Angle traced by hour hand in | 125 | hrs = | ![]() |
360 | x | 125 | ![]() |
° | = 312 | 1 | ° | . |
12 | 12 | 12 | 2 |
Angle traced by minute hand in 25 min = | ![]() |
360 | x 25 | ![]() |
° | = 150°. |
60 |
![]() |
![]() |
312 | 1 | - 150 | ![]() |
° | = 360° - 162 | 1 | ° | = 197 | 1° | . |
2 | 2 | 2 |
Discussion:
269 comments Page 25 of 27.
Pragna said:
1 decade ago
Will you explain me in a simple way?
Chandra said:
1 decade ago
Why we have to find out 150 degree?
Tanu said:
1 decade ago
@Guru Hi Arjit formula is correct.
Raj said:
2 years ago
I think 192.5 is the right answer.
(28)
Anonymous said:
9 years ago
@Hell Rider cleared it very well.
Shalini said:
1 decade ago
Why multiplied by 12 and not 60?
Vasu said:
5 years ago
Explain in clear @Atharv Pathak.
Harshini said:
5 years ago
Thanks all for explaining this.
Ankit said:
2 decades ago
How to calculate reflex angle?
Gaurav said:
1 decade ago
10:25= 10+25/60=10+5/12=125/12
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