Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 2)
2.
The reflex angle between the hands of a clock at 10.25 is:
Answer: Option
Explanation:
| Angle traced by hour hand in | 125 | hrs = |  |
360 | x | 125 |  |
° | = 312 | 1 | ° | . |
| 12 | 12 | 12 | 2 |
| Angle traced by minute hand in 25 min = | |
360 | x 25 | |
° | = 150°. |
| 60 |
 Reflex angle = 360° - |
|
312 | 1 | - 150 | |
° | = 360° - 162 | 1 | ° | = 197 | 1° | . |
| 2 | 2 | 2 |
Discussion:
269 comments Page 24 of 27.
Atharv Pathak said:
5 years ago
Angle=(60*h-11*m)/2.
And reflex angle=360-angle.
And reflex angle=360-angle.
(1)
Vasu said:
5 years ago
Explain in clear @Atharv Pathak.
KOHLI said:
5 years ago
Thanks all for explaining.
Piyush said:
5 years ago
Thanks all for explaining.
Sanju said:
5 years ago
Thank you all for explaining the answer.
Nisanth said:
5 years ago
What is the need to find an hour hand and min hand? Please explain me.
Revanth said:
5 years ago
Why to find an hour hand and a min hand? Please explain me.
Sangay Dorji said:
5 years ago
10.25 means: 10hrs + 0.25 hrs.
Therefore, it can be written as 10hrs+(25/60)hrs.
Make the L.C.M as 60, then it will become ((10 * 60) + (25))/60 = 125/12 hrs.
Therefore, it can be written as 10hrs+(25/60)hrs.
Make the L.C.M as 60, then it will become ((10 * 60) + (25))/60 = 125/12 hrs.
Hemanth RAMAN' said:
5 years ago
Thank you @Sangay.
Rahul said:
5 years ago
Thank you all.
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