Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 2)
2.
The reflex angle between the hands of a clock at 10.25 is:
180°
192 1 °
2
195°
197 1 °
2
Answer: Option
Explanation:

Angle traced by hour hand in 125 hrs = 360 x 125 ° = 312 1 ° .
12 12 12 2

Angle traced by minute hand in 25 min = 360 x 25 ° = 150°.
60

Reflex angle = 360° - 312 1 - 150 ° = 360° - 162 1 ° = 197 .
2 2 2

Discussion:
269 comments Page 21 of 27.

Deena said:   1 decade ago
Hi. Arijit please one example find out your formula please.

Vinayak Mahadev said:   8 years ago
10.25.
10*60=600 min.

25 min
625min /60 min. = 125/12 hr.

Revanth said:   5 years ago
Why to find an hour hand and a min hand? Please explain me.

Neethu Cheriyan said:   2 years ago
30H -11/2 * M
30*100-11/2 * 25 = 162.5
360-162.5 = 197.5.
(70)

Manoj said:   2 decades ago
10 hrs 25 min= 10.25/60. = 10.5/12 =(12*10+5)/12 =125/12

Sharmu said:   7 years ago
Where; Replex angle= clock angle (ie 360)- actual angle.

Simit said:   4 years ago
@All.

10.25 is actually ten hours and 15 mins (.25*60).

Anonomous said:   9 years ago
The best way to do is using this formulae 11/2m - 30h.

Charu said:   8 years ago
Can anyone explain what is a reflex angle (definition)?

Prajwal said:   4 years ago
Using formula:

Reflex angle = 360 - 11 * M/2 - 30 * H.


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