Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 2)
2.
The reflex angle between the hands of a clock at 10.25 is:
Answer: Option
Explanation:
| Angle traced by hour hand in | 125 | hrs = |  |
360 | x | 125 |  |
° | = 312 | 1 | ° | . |
| 12 | 12 | 12 | 2 |
| Angle traced by minute hand in 25 min = | |
360 | x 25 | |
° | = 150°. |
| 60 |
 Reflex angle = 360° - |
|
312 | 1 | - 150 | |
° | = 360° - 162 | 1 | ° | = 197 | 1° | . |
| 2 | 2 | 2 |
Discussion:
269 comments Page 20 of 27.
Vinayak Mahadev said:
8 years ago
10.25.
10*60=600 min.
25 min
625min /60 min. = 125/12 hr.
10*60=600 min.
25 min
625min /60 min. = 125/12 hr.
Dony David said:
8 years ago
Use this formula (max of the problems will be solved).
Angle=30h-11/2(m)
so acc to given values the time is 10:25,
so h=10,m=25
on solving
angle=30(10)-11/2(25)
=300-11 x12.5
=300-137.5
=162.5(this is internal angle).
Therefore==> reflex=360(this is total angle of clock)-162.5,
=360-162.5,
=197.5,
==>197 1/2 deg.
Angle=30h-11/2(m)
so acc to given values the time is 10:25,
so h=10,m=25
on solving
angle=30(10)-11/2(25)
=300-11 x12.5
=300-137.5
=162.5(this is internal angle).
Therefore==> reflex=360(this is total angle of clock)-162.5,
=360-162.5,
=197.5,
==>197 1/2 deg.
ANAND MAURYA said:
8 years ago
Hour Hand: 10:25
1 Hour=30° 10*30=300°
1 Minute=1/2° 25*1/2=25/2°
(300+25/2)°;
Minute Hand: 25
1 Minute=6° 25*6=150°;
Angle b/w HH & MH = (300+25/2-150)°,
Reflexive Angle = [360-(300+25/2-150)]°,
Reflexive Angle = 197.5°.
1 Hour=30° 10*30=300°
1 Minute=1/2° 25*1/2=25/2°
(300+25/2)°;
Minute Hand: 25
1 Minute=6° 25*6=150°;
Angle b/w HH & MH = (300+25/2-150)°,
Reflexive Angle = [360-(300+25/2-150)]°,
Reflexive Angle = 197.5°.
Shaik salman said:
8 years ago
Formula:|11/2(M)-30(H)| here M=minutes, H=hour.
Given time 10:25 substitute in above formula.
|11/2(25)-30(10)| = 1621/2.
Reflexive Angle = [360-162.5] = 197.5deg.
Given time 10:25 substitute in above formula.
|11/2(25)-30(10)| = 1621/2.
Reflexive Angle = [360-162.5] = 197.5deg.
Mitul said:
8 years ago
I have made a formula to calculate clock angle.
(h-(m/5))*30 + m/2 (for calculating ordinary angle)
360 - (this formula for calculating reflex angle)
Hope it Helps!
(h-(m/5))*30 + m/2 (for calculating ordinary angle)
360 - (this formula for calculating reflex angle)
Hope it Helps!
Mahi said:
8 years ago
1) For 12 hrs 360 degree (for 1 hr 30 degree) for 10 hrs 300 degree & for 25 min converted in to hrs ie ( 25 min/60 min*30 degree)=(25/60*30)12.5 degree total-300+12.5=312.5 degree.
2) for 60 min 360 degree for 25 min 150 degree we get 1)312.5 degree & 150 degree
diff 162.5 deduct rom 360 162.5 ans-197.5 deg.
2) for 60 min 360 degree for 25 min 150 degree we get 1)312.5 degree & 150 degree
diff 162.5 deduct rom 360 162.5 ans-197.5 deg.
Priya said:
8 years ago
How you get 125/12?
A.Margaret said:
8 years ago
The angle b/w 10 & 5(10:25) is 150.
For 25 min,hr hand moves 12.5 degrees.the actual angle now is 150+12.5=162.5.To calculate reflex angle 360-162.5=197.5
For simple understanding,let's assume the time is now 12.we can say the angle b/w hr hand & min hand is 0 or 360(reflex angle). At 1'o clock the angle is 30 or 330(reflex).likewise at 10:25 the angle is 162.5 or 197.5.
For 25 min,hr hand moves 12.5 degrees.the actual angle now is 150+12.5=162.5.To calculate reflex angle 360-162.5=197.5
For simple understanding,let's assume the time is now 12.we can say the angle b/w hr hand & min hand is 0 or 360(reflex angle). At 1'o clock the angle is 30 or 330(reflex).likewise at 10:25 the angle is 162.5 or 197.5.
Mugdha said:
8 years ago
How did you get 162.5 or 197.5? @A.Margaret.
Dula said:
8 years ago
Thanks all for the given explanation.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers