Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 2)
2.
The reflex angle between the hands of a clock at 10.25 is:
Answer: Option
Explanation:
| Angle traced by hour hand in | 125 | hrs = |  |
360 | x | 125 |  |
° | = 312 | 1 | ° | . |
| 12 | 12 | 12 | 2 |
| Angle traced by minute hand in 25 min = | |
360 | x 25 | |
° | = 150°. |
| 60 |
 Reflex angle = 360° - |
|
312 | 1 | - 150 | |
° | = 360° - 162 | 1 | ° | = 197 | 1° | . |
| 2 | 2 | 2 |
Discussion:
269 comments Page 13 of 27.
Divya said:
1 decade ago
What's the formula to calculate reflex angle if it is greater than 180 degrees? Anyone who know please tell me.
Soundarya said:
1 decade ago
Reflex angle is nothing but an angle greater than 180 degrees.
Ajay said:
1 decade ago
Equation for the angle of the hour hand,
(Hour Angle) = (60H+M)/2.
Where, H= Hour.
M is the minutes past the hour.
And, Equation for the angle of the minute hand, (minute Angle) = 6M.
For Example:
10.25.
(Hour Angle) = (60*10+25)/2 = 312.5.
(Minute Angle) = 6*25 = 150.
Reflex angle = 360-(312.5-150) = 197.5.
(Hour Angle) = (60H+M)/2.
Where, H= Hour.
M is the minutes past the hour.
And, Equation for the angle of the minute hand, (minute Angle) = 6M.
For Example:
10.25.
(Hour Angle) = (60*10+25)/2 = 312.5.
(Minute Angle) = 6*25 = 150.
Reflex angle = 360-(312.5-150) = 197.5.
Sweta said:
1 decade ago
Hi everyone, Please help me to solve clock problems because I am unable to understand the concept.
Murugesh said:
1 decade ago
What is flexible angle?
Kasinath@Hyd said:
1 decade ago
So simple, to find degrees for a value > 180 or > 6'o clock.
Formula is 1/2 (60*hrs-11*min).
= 1/2(60*10-11*25) ==> 1/2(600-275).
==>162.5.
Since reflex angle i.e., 360 deg.
Therefore 360-162.5 ==> 197.5.
Formula is 1/2 (60*hrs-11*min).
= 1/2(60*10-11*25) ==> 1/2(600-275).
==>162.5.
Since reflex angle i.e., 360 deg.
Therefore 360-162.5 ==> 197.5.
Alok said:
1 decade ago
I think 125/12 is wrong.
10.25 hrs = 10h+0.25 hrs = (10*60+0.25*60) mins = 615 mins = 615/60 mins = 123/12 hrs.
10.25 hrs = 10h+0.25 hrs = (10*60+0.25*60) mins = 615 mins = 615/60 mins = 123/12 hrs.
Harindra said:
1 decade ago
10.25 = 10+25/60 = 10+5/12 = (120+5)/12 = 125/12.
So 125/12*360/12 = 312 (1/2).
And now long hand in 25 minute = 6*25 = 150.
Reflex angle = 360-(321(1/2)-150) = 197(1/2).
So 125/12*360/12 = 312 (1/2).
And now long hand in 25 minute = 6*25 = 150.
Reflex angle = 360-(321(1/2)-150) = 197(1/2).
Abhinit Aand said:
1 decade ago
This one is for those who have chosen formula to solve these sort of problems. Use formula to find angle between clock hands at 1:50? particularly to @Kasinath@Hyd.
M Rajeswari said:
1 decade ago
Hi everyone,
It is simple question The reflex angle b/w the hands of a clock at 10.25.
Then formula is 11/2M-30H.
So, we can substitute in this, 11/2(25)-30(10).
=>162.5.
Then, the angle 360-162.5.
=>197.5.
That's it.
It is simple question The reflex angle b/w the hands of a clock at 10.25.
Then formula is 11/2M-30H.
So, we can substitute in this, 11/2(25)-30(10).
=>162.5.
Then, the angle 360-162.5.
=>197.5.
That's it.
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