Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 2)
2.
The reflex angle between the hands of a clock at 10.25 is:
Answer: Option
Explanation:
| Angle traced by hour hand in | 125 | hrs = |  |
360 | x | 125 |  |
° | = 312 | 1 | ° | . |
| 12 | 12 | 12 | 2 |
| Angle traced by minute hand in 25 min = | |
360 | x 25 | |
° | = 150°. |
| 60 |
 Reflex angle = 360° - |
|
312 | 1 | - 150 | |
° | = 360° - 162 | 1 | ° | = 197 | 1° | . |
| 2 | 2 | 2 |
Discussion:
269 comments Page 11 of 27.
Psm said:
1 decade ago
Correct formula is 30h - 11/2m. So this mean at 0 hours and 1 minute you get an angle of: 30*0 - 11 / 2*1 = -5.5 ?
How come the minute arrow moves almost 6 degrees then?
How come the minute arrow moves almost 6 degrees then?
Ravi said:
1 decade ago
Here they had given time is 10:25.
Angle = (11/2(minutes)-30(hours)).
Angle = (11/2(25)-30(10)).
Angle = (137.5-300).
Angle = 162.5.
Ref angle = 360-162.5 = 197.5.
Angle = (11/2(minutes)-30(hours)).
Angle = (11/2(25)-30(10)).
Angle = (137.5-300).
Angle = 162.5.
Ref angle = 360-162.5 = 197.5.
Sireesha said:
1 decade ago
Hai guys u can solve any problem regarding clocks easily by using formula
angle=(11/2)m-30h
Simply substitute minutes in place of 'm' and hours in place of 'h'.
angle=(11/2)m-30h
Simply substitute minutes in place of 'm' and hours in place of 'h'.
Shaik salman said:
8 years ago
Formula:|11/2(M)-30(H)| here M=minutes, H=hour.
Given time 10:25 substitute in above formula.
|11/2(25)-30(10)| = 1621/2.
Reflexive Angle = [360-162.5] = 197.5deg.
Given time 10:25 substitute in above formula.
|11/2(25)-30(10)| = 1621/2.
Reflexive Angle = [360-162.5] = 197.5deg.
Mitul said:
8 years ago
I have made a formula to calculate clock angle.
(h-(m/5))*30 + m/2 (for calculating ordinary angle)
360 - (this formula for calculating reflex angle)
Hope it Helps!
(h-(m/5))*30 + m/2 (for calculating ordinary angle)
360 - (this formula for calculating reflex angle)
Hope it Helps!
Kailash chandra patria said:
7 years ago
The angle between hand at 10 hr & 25 /Min is 210,
But hr hand passed 12.5° more (30* in 60 Min multiplied by 25 Min),
Hence net angle 210 - 12.5 = 197.5°.
But hr hand passed 12.5° more (30* in 60 Min multiplied by 25 Min),
Hence net angle 210 - 12.5 = 197.5°.
Varun said:
4 years ago
@Meghna
Because in 25 minutes the hour hand would have moved ahead of 10. (At the rate of 0.5' per minute) '.
It was exactly at 10 when the minute hand was at 12.
Because in 25 minutes the hour hand would have moved ahead of 10. (At the rate of 0.5' per minute) '.
It was exactly at 10 when the minute hand was at 12.
Abhinit Aand said:
1 decade ago
This one is for those who have chosen formula to solve these sort of problems. Use formula to find angle between clock hands at 1:50? particularly to @Kasinath@Hyd.
Aanand said:
6 years ago
Simply;
Angle: (30*hours given)-(11/2 * minutes given).
And here it is told to find the reflex angle so subtract 360° from the angle, we will get the answer.
Angle: (30*hours given)-(11/2 * minutes given).
And here it is told to find the reflex angle so subtract 360° from the angle, we will get the answer.
Sailakshmi said:
7 years ago
By Using this formula 30H- 11/2 *M.
H denotes hour.
M denotes minute.
Here... 30*10- 11/2*25.
=300-137.5,
=162.5~ angle.
To get reflex angle: 360-162.5 =197.5.
H denotes hour.
M denotes minute.
Here... 30*10- 11/2*25.
=300-137.5,
=162.5~ angle.
To get reflex angle: 360-162.5 =197.5.
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