Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 2)
2.
The reflex angle between the hands of a clock at 10.25 is:
Answer: Option
Explanation:
| Angle traced by hour hand in | 125 | hrs = |  |
360 | x | 125 |  |
° | = 312 | 1 | ° | . |
| 12 | 12 | 12 | 2 |
| Angle traced by minute hand in 25 min = | |
360 | x 25 | |
° | = 150°. |
| 60 |
 Reflex angle = 360° - |
|
312 | 1 | - 150 | |
° | = 360° - 162 | 1 | ° | = 197 | 1° | . |
| 2 | 2 | 2 |
Discussion:
269 comments Page 10 of 27.
Vikrant shukla said:
1 decade ago
10:25 converted min. and div. 60 that is ((10*60)25)/60 = 125/12.
IRSHAD said:
1 decade ago
@Vani here 10.25 means 10 + (25/60).
i.e. 10 + (5/12).
i.e. 125/12.
i.e. 10 + (5/12).
i.e. 125/12.
Raambharath said:
1 decade ago
Finding the angle= (11/2) M - (30) H.
M is the minutes.
H is the hours.
10:25.
(11/2) 25 - 30*10.
M is the minutes.
H is the hours.
10:25.
(11/2) 25 - 30*10.
Thejas said:
1 decade ago
|30h-(11/2)m| ----> Formula to find angle between 2 hands.
|30*10-(11/2)25|
|300-275/2|
|(600-275)/2|
|325/2|
162.5 degrees.
Reflex angle is 360 - 162.5 = 197.5.
|30*10-(11/2)25|
|300-275/2|
|(600-275)/2|
|325/2|
162.5 degrees.
Reflex angle is 360 - 162.5 = 197.5.
Karthik said:
1 decade ago
Follow this:
Min hand 1 min movement swipes 6 deg.
Min hand 1 min movement = hour hand 0.5 deg.
Min hand 1 min movement swipes 6 deg.
Min hand 1 min movement = hour hand 0.5 deg.
P.C. RAJASEKAR said:
1 decade ago
Hey thanks for everyone who gav the answer and who raised the questions. From you all I understood how to calculate angle between 2 hands and to calculate reflex angle.
Angle between 2 hands = 30(h) - (11/2)*m.
Reflex angle = 360 - angle between 2 hands.
(if angle between 2 hands is < 180).
Thanks to everyone.
Angle between 2 hands = 30(h) - (11/2)*m.
Reflex angle = 360 - angle between 2 hands.
(if angle between 2 hands is < 180).
Thanks to everyone.
Vyshnavi said:
1 decade ago
How to calculate reflex angle?
Jithin said:
1 decade ago
The equation for calculating the angle b/w the hands was given as (11/2)m-30h.
For eg: We clearly know that in case of 9.00 am/pm, that the angle is 90 degree, using this formula I got as 60 degree is it correct? please explain me with example.
For eg: We clearly know that in case of 9.00 am/pm, that the angle is 90 degree, using this formula I got as 60 degree is it correct? please explain me with example.
Jasna said:
1 decade ago
The equation to find the angle between the hands is (11/2)*m-30h.
Where m:minutes.
h:hour reading.
Please explain the thing that in case of 3'oclock, that is 3.00.
The angle b/w hands are 90 degree, with the given equation it is got as 120 degree. How is it possible?. please explain how to use the equation properly, and where to use.
Where m:minutes.
h:hour reading.
Please explain the thing that in case of 3'oclock, that is 3.00.
The angle b/w hands are 90 degree, with the given equation it is got as 120 degree. How is it possible?. please explain how to use the equation properly, and where to use.
Mani said:
1 decade ago
@Jasna.
3'o clock means 3.00.
So, Hours - 3.
Minutes - 0.
Correct formula is 30h - 11/2m.
So, 30*3-11/2*0 = 90°.
3'o clock means 3.00.
So, Hours - 3.
Minutes - 0.
Correct formula is 30h - 11/2m.
So, 30*3-11/2*0 = 90°.
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