Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 10)
10.
At 3:40, the hour hand and the minute hand of a clock form an angle of:
Answer: Option
Explanation:
Angle traced by hour hand in 12 hrs. = 360°.
Angle traced by it in | 11 | hrs = | ![]() |
360 | x | 11 | ![]() |
° | = 110°. |
3 | 12 | 3 |
Angle traced by minute hand in 60 min. = 360°.
Angle traced by it in 40 min. = | ![]() |
360 | x 40 | ![]() |
° | = 240°. |
60 |
Required angle (240 - 110)° = 130°.
Discussion:
44 comments Page 3 of 5.
Shahid kureshi said:
8 years ago
3 hour is 30*3=90 and minute 40*5.5,
=220 and different is 220-90=130.
=220 and different is 220-90=130.
Jitendra rathore said:
8 years ago
130° is right answer. I agree.
MOTIUR RAHMAN said:
7 years ago
°=11/2 min.-30H.
So,11*40/2-30*3,
°= 220-90,
= 130(answer).
So,11*40/2-30*3,
°= 220-90,
= 130(answer).
Sopan said:
1 decade ago
Whenever the angle b/w hands of clock is asked just apply the formula:
Angle= |30h -11/2(m)|.
Where h is hour and m is min.
Angle= |30h -11/2(m)|.
Where h is hour and m is min.
Abi said:
1 decade ago
Actually why they put 11/3hrs here ..can anyone clear my doubt
Palanivel said:
1 decade ago
For hour hand.
Convert min into hr keep 3 without change 3+(40/60)=11/3.
Convert min into hr keep 3 without change 3+(40/60)=11/3.
Shree said:
1 decade ago
Here we can use the formula:
theta(degree)=11(m)/2-30h
min(m)=40; hour(h)=3
theta=11(40)/2-30(3)
=130 degree
theta(degree)=11(m)/2-30h
min(m)=40; hour(h)=3
theta=11(40)/2-30(3)
=130 degree
Sri said:
1 decade ago
Even I have the sme doubt as Abi. I dint get how they took 11/3. Pls, pls, please any solve my problem.
Lalitha said:
1 decade ago
I also didn't understand how they have taken 11/3 hrs, and I could not understand how the hours hand angle has been traced.
Sushil said:
1 decade ago
Convert the whole time in hour.
3 hour+40 min=3h+(40/60) h=22/6=11/3 hour.
3 hour+40 min=3h+(40/60) h=22/6=11/3 hour.
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