Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 3)
3.
A clock is started at noon. By 10 minutes past 5, the hour hand has turned through:
Answer: Option
Explanation:
Angle traced by hour hand in 12 hrs = 360°.
| Angle traced by hour hand in 5 hrs 10 min. i.e., | 31 | hrs = |  |
360 | x | 31 |  |
° | = 155°. |
| 6 | 12 | 6 |
Discussion:
87 comments Page 5 of 9.
Sabungar said:
6 years ago
The clock is started noon matlab 12 o clock.
15 min =90 degree,
1 hr =360 degree,
Clock is start 12 o clock to 5 o clock .
Min hand is 10.
10*0.5=5
=> 5 and 6 gap between the 30 degrees.
So,30 -5 =25
And180-25=155°.
15 min =90 degree,
1 hr =360 degree,
Clock is start 12 o clock to 5 o clock .
Min hand is 10.
10*0.5=5
=> 5 and 6 gap between the 30 degrees.
So,30 -5 =25
And180-25=155°.
Vaibhav said:
5 years ago
Hr hand move 10 min in 5 hrs so afternoon means start from 12 then after 5 hrs show 5 o'clock but 10 min means 10/2=5° so 12 to 5 150°+5°=155°.
Siddhant Bharti said:
5 years ago
12hr=360° so,
1hr=30°
Coming to Question
10 past 5 = 5:10.
Here, from 12 noon to 5 indicate= 5*30=150° This is the angle when Time is exactly 5 o'Clock but,
In this question, Time is 5:10. Now we need to calculate how much extra distance travelled by the hour hand in that 10 min.
Converting 10 min in Hours= 10/60 = 1/6.
The Angle travelled by the minute hand in 10 = 1/6*30= 5°.
So the total Angle= 150°+ 5° = 155°.
1hr=30°
Coming to Question
10 past 5 = 5:10.
Here, from 12 noon to 5 indicate= 5*30=150° This is the angle when Time is exactly 5 o'Clock but,
In this question, Time is 5:10. Now we need to calculate how much extra distance travelled by the hour hand in that 10 min.
Converting 10 min in Hours= 10/60 = 1/6.
The Angle travelled by the minute hand in 10 = 1/6*30= 5°.
So the total Angle= 150°+ 5° = 155°.
Charm said:
5 years ago
360/12*31/6=155.
How? Anyone please explain.
How? Anyone please explain.
Morpankh said:
5 years ago
For hour hand (HH), we have a notation. Right?
Narendran, S S said:
1 decade ago
Angle between hr and min is given by
A =30*hr~(11/2)*min
= 30*5 - (11/2)*10
= 95 degrees
Now the angle swiped by the min hand alone is
6 degrees per min
hence 60 degrees per 10 min
Angle swiped by hr hand alone is
A+60 = 95+60 = 155 degrees.
A =30*hr~(11/2)*min
= 30*5 - (11/2)*10
= 95 degrees
Now the angle swiped by the min hand alone is
6 degrees per min
hence 60 degrees per 10 min
Angle swiped by hr hand alone is
A+60 = 95+60 = 155 degrees.
Guru govind said:
1 decade ago
The question asked is not for angle b/w hours hand and minutes hand.the question is:how much distance only hours hand rotated from noon...
from 12 to 5:00 the hours hand rotated is 150degree.use the formula 30h-(11/2)*m=theta; now how much is the hours hand rotated in in 10min. i.e..for 1hour..it will make 30degree...for 10min..it will make 5degree. therefore 150+5=155
from 12 to 5:00 the hours hand rotated is 150degree.use the formula 30h-(11/2)*m=theta; now how much is the hours hand rotated in in 10min. i.e..for 1hour..it will make 30degree...for 10min..it will make 5degree. therefore 150+5=155
Rupa said:
1 decade ago
If 1hr=30degrees.
Then 5hrs= (5*30) =150degrees.
And then 10min= (10/60) =1/6.
1/6*30=5degrees.
The total is 155degrees.
Then 5hrs= (5*30) =150degrees.
And then 10min= (10/60) =1/6.
1/6*30=5degrees.
The total is 155degrees.
Sowmya said:
1 decade ago
How can it be 360-95=155? it is 265. I don't understand the logic.
Mary said:
1 decade ago
Its easy
1hr=30 degree
ie 5hr=5*30=150 degree
also
10 min=10/60hr=1/6hr
we know 1hr=30 degree
ie
(1/6)*30=5 degree
so 150 deg+5 deg=155 deg.
its solved :)
1hr=30 degree
ie 5hr=5*30=150 degree
also
10 min=10/60hr=1/6hr
we know 1hr=30 degree
ie
(1/6)*30=5 degree
so 150 deg+5 deg=155 deg.
its solved :)
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