Aptitude - Chain Rule - Discussion

Discussion Forum : Chain Rule - General Questions (Q.No. 1)
1.
3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the tank in 1 day?
9
10
11
12
Answer: Option
Explanation:

Let the required number of working hours per day be x.

More pumps, Less working hours per day (Indirect Proportion)

Less days, More working hours per day (Indirect Proportion)

Pumps 4 : 3 :: 8 : x
Days 1 : 2

4 x 1 x x = 3 x 2 x 8

x = (3 x 2 x 8)
(4)

x = 12.

Discussion:
69 comments Page 6 of 7.

Math Master said:   1 decade ago
Better you do like this:
3 pumps take 16 hrs total (8 Hrs a day)
If 1 pump will be working then, it will need 16*3=48 hrs
1 pump need 48 Hrs
If I contribute 4 pumps then
48/4=12 hrs.

Sivakumar said:   1 decade ago
a:b::c:d=>bc=ad

Shaunak said:   1 decade ago
It's simple direct and inverse ratio theory. You can apply unitary method,but that'll take a hell lot of time.

Naveen moorthy said:   1 decade ago
As tank are Same.

So 3x8=24 hours required for 1 day for that tank.

So hrs will be same.

For 4 tanks, 4x6=24 for 2 days.

If it 1 day, 6x2=12 hours.

Imraz said:   1 decade ago
3 pumps 8 hours 2 days =work
3*8*2=work----->eqn1

now to complete the same work with 4 pumps in 1 day how many hours are required? lets take the hours required as x. then we can write the same work as

4 pump x hours 1 day =work

4*x*1=work ---->eqn2

equating both equation
3*8*2=4*x*1
x=48/4
x=12 hours

Raja said:   1 decade ago
@maher. I am just asking where is the concept of chain rule (indirect propprtion) approach.

Sudheer said:   1 decade ago
Imraz said well.

Yogendra said:   1 decade ago
Thanks imraz your method is very easy to understand.

Maths lover said:   1 decade ago
@math master and all.

Your approach is right because fortunately question is asking of 1 day. If not. Then we have to divide the answer by number of days. So people take care of that also.

Kuntal Paul said:   1 decade ago
Mathmaster method is so simple and effective.


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