Aptitude - Chain Rule - Discussion

Discussion Forum : Chain Rule - General Questions (Q.No. 1)
1.
3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the tank in 1 day?
9
10
11
12
Answer: Option
Explanation:

Let the required number of working hours per day be x.

More pumps, Less working hours per day (Indirect Proportion)

Less days, More working hours per day (Indirect Proportion)

Pumps 4 : 3 :: 8 : x
Days 1 : 2

4 x 1 x x = 3 x 2 x 8

x = (3 x 2 x 8)
(4)

x = 12.

Discussion:
69 comments Page 3 of 7.

Nikhilkuruli said:   1 decade ago
@Akhilesh sahu: 27 hours.

Neha said:   1 decade ago
Why are you 16*3 for 1 pump?

Ankita agrawal said:   1 decade ago
Its so simple. Just we need to apply correct logic.

Rajeev Guda said:   1 decade ago
3*8 = 24 hours in 2 day i.e., 12 hours a day with 3 pumps.

How can it be 12 hours with 4 pumps?

Emilia said:   1 decade ago
I like @Mehar's Method. So simple to understand. Thanks.

Arjita said:   1 decade ago
@Math master: I didn't get your first statement.

Celita Lewis said:   1 decade ago
If 3 pumps work for 8 hours than total hours in 1 day is 3 * 8 = 24 hours.

So in 2 days total hours of work is 48 hours.

So for 4 pumps the work distributed is (48 / 4) = 12 hours.

Karm Bodh Yadav said:   1 decade ago
There is simple and understandable style to solve:

3 pumps take 24 hrs total (8 Hrs a day).

If 1 pump will be working then, it will need 8*3 = 24 hrs.

1 pump need 24 Hrs in two day.

1 pump need 24*2 Hrs in one day.

If I contribute 4 pumps then.

48/4 = 12 hrs.

Deepika said:   1 decade ago
Hey I have one simple way that is ma formula is n*D*H/w = N1*D1*H1/W1.

Where n = no.of men.
d = days.
h = hours.
w = work.

So my opinion is 3*8*2 = 4*1*x.

x = 12.

Sobuz said:   1 decade ago
At First we find the Total_hour to finish the work, that is:

3*8*2 = 48.

So, 4*X*1 = 48.

X = 48/4 = 12.


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