Aptitude - Chain Rule - Discussion
Discussion Forum : Chain Rule - General Questions (Q.No. 1)
1.
3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the tank in 1 day?
Answer: Option
Explanation:
Let the required number of working hours per day be x.
More pumps, Less working hours per day (Indirect Proportion)
Less days, More working hours per day (Indirect Proportion)
| Pumps | 4 | : | 3 |  |
:: 8 : x |
| Days | 1 | : | 2 |
4 x 1 x x = 3 x 2 x 8
 x = |
(3 x 2 x 8) |
| (4) |
x = 12.
Discussion:
69 comments Page 2 of 7.
Abhishek said:
1 decade ago
@ Math Master I like your Approach :))
Bernard said:
1 decade ago
4 x 1 x x = 3 x 2 x 8
x = (3 x 2 x 8) / (4)
x = 12.
x = (3 x 2 x 8) / (4)
x = 12.
Akhilesh Sahu said:
1 decade ago
Please solve my problem
If 38 men , working 6 hours a day ,can do a piece of work in 12 days , find the number of days in which 57 men working 8 hours a day, can do twice that piece of work, supposing that two men of the first set do as much work in 1 hour as 3 men of the secand set do in 3/2 hours.
If 38 men , working 6 hours a day ,can do a piece of work in 12 days , find the number of days in which 57 men working 8 hours a day, can do twice that piece of work, supposing that two men of the first set do as much work in 1 hour as 3 men of the secand set do in 3/2 hours.
Umesh said:
1 decade ago
Total work (Time to empty the tank by one pump) = 3(pumps)* 8(hours)*2(days)
= 42hours
When 4 pumps are using it will take 42/4= 12 hours
= 42hours
When 4 pumps are using it will take 42/4= 12 hours
Anamika said:
1 decade ago
Math Master's solution is really easy to uderstand
Cauverypithan said:
1 decade ago
Math master method is wrong if 3 pumps works a day for 16 hour and one pump will 16/3 not 16*3.
Naresh said:
1 decade ago
Thanks mehar.
Hiscan said:
1 decade ago
@Cauverypithan
Math master is rite....coz 3 pumps will empty in 16hrs....
if they r using one pump,then work load ll increase,then 48hrs is rite....
still not clear...
then c...3 pump ll empty one tank in 16hr...so more the no of pump faster it gets emptied,
lesser the no of pump slower it gets emptied...
Math master is rite....coz 3 pumps will empty in 16hrs....
if they r using one pump,then work load ll increase,then 48hrs is rite....
still not clear...
then c...3 pump ll empty one tank in 16hr...so more the no of pump faster it gets emptied,
lesser the no of pump slower it gets emptied...
Deepika said:
1 decade ago
Thanks for all for there short cuts.
Imraz said:
1 decade ago
3 pumps 8 hours 2 days =work
3*8*2=work----->eqn1
now to complete the same work with 4 pumps in 1 day how many hours are required? lets take the hours required as x. then we can write the same work as
4 pump x hours 1 day =work
4*x*1=work ---->eqn2
equating both equation
3*8*2=4*x*1
x=48/4
x=12 hours
3*8*2=work----->eqn1
now to complete the same work with 4 pumps in 1 day how many hours are required? lets take the hours required as x. then we can write the same work as
4 pump x hours 1 day =work
4*x*1=work ---->eqn2
equating both equation
3*8*2=4*x*1
x=48/4
x=12 hours
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