Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Answer: Option
Explanation:
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
Discussion:
258 comments Page 6 of 26.
Chandu said:
1 decade ago
Thanks sundar
Intaj said:
1 decade ago
Hi, you can do it easily follow my shortcut rule :-
jan = (1) = 3 jan = 31/7 = remain = 3
feb = (2)= 0 feb= 28/7 = remain = 0
march = (3)= 3
april = (4)= 2 april = 30/7 = reminder = 2
may = (5) = 3
june = (6) = 2
july = (7) =3 ====================================
aug = (8)= 3 (1 , 3, 5, 7, 8, 10, 12) = 3
sept = (9)= 2 ( 4, 6, 9, 11) = 2
oct = (10)= 3 2= 0 (Feb)
nov = (11) = 2
dec = (12) = 3 JUST REMEMBER ABOVE
jan = (1) = 3 jan = 31/7 = remain = 3
feb = (2)= 0 feb= 28/7 = remain = 0
march = (3)= 3
april = (4)= 2 april = 30/7 = reminder = 2
may = (5) = 3
june = (6) = 2
july = (7) =3 ====================================
aug = (8)= 3 (1 , 3, 5, 7, 8, 10, 12) = 3
sept = (9)= 2 ( 4, 6, 9, 11) = 2
oct = (10)= 3 2= 0 (Feb)
nov = (11) = 2
dec = (12) = 3 JUST REMEMBER ABOVE
Arkright said:
1 decade ago
Why do you divide with is it 4 or 7 to get a leap /ordinary year am confused some of you using 7 while others 4. Please explain?
Manish tiwari said:
1 decade ago
Thanks pavitra. Really good dear.
Sreehitha said:
1 decade ago
Pavitra, can you please explain for 1st jan 2008 as it is a leap year how to approach it. The example 16 may 2011 which you have given is for non leap year right.
Nallathambim said:
1 decade ago
Please explain it with more details.
Shashi said:
1 decade ago
Nice one Sundar & Pavitra.
Mamatha said:
1 decade ago
Thanks Pavithra.
Kayal said:
1 decade ago
First we take the previous century why because every 4th century is leap year.
Then take the finding year with substract 1.
So 2009-2000=9.
Now find the how many leap year and how many ordinary year in this 9. So we divide.
9/4=2. So 2 leap year and 7 ordinary year.
= (2*2+7*1) =4.
Now take the months table what they ask to find out here jan 1.
So no months is there as to take 1.
=4+1.
=5 (friday).
Weeks table.
0-sunday.
1-monday.
2-tuesday.
3-wednesday.
4-thursday.
5-friday.
6-saturday.
Thats all.
Then take the finding year with substract 1.
So 2009-2000=9.
Now find the how many leap year and how many ordinary year in this 9. So we divide.
9/4=2. So 2 leap year and 7 ordinary year.
= (2*2+7*1) =4.
Now take the months table what they ask to find out here jan 1.
So no months is there as to take 1.
=4+1.
=5 (friday).
Weeks table.
0-sunday.
1-monday.
2-tuesday.
3-wednesday.
4-thursday.
5-friday.
6-saturday.
Thats all.
K.velmurugan said:
1 decade ago
odd days
1-jan
4-feb
4-mar
0-apr
2-may
5-jun
0-july
3-agu
6-sep
1-oct
4-nov
6-dec
0-sunday.
1-monday.
2-tuesday.
3-wednesday.
4-thursday.
5-friday.
6-saturday.
20--=6 odddays
19--=0 oddays
ex : 27/03/2012
day=27 total=day+month+20--+ year
month=4
20--=6 =27+4+6+17=54/7
(year=--12/7= 5remainter) remainder=5
year=12+5=17
ans: friday
1-jan
4-feb
4-mar
0-apr
2-may
5-jun
0-july
3-agu
6-sep
1-oct
4-nov
6-dec
0-sunday.
1-monday.
2-tuesday.
3-wednesday.
4-thursday.
5-friday.
6-saturday.
20--=6 odddays
19--=0 oddays
ex : 27/03/2012
day=27 total=day+month+20--+ year
month=4
20--=6 =27+4+6+17=54/7
(year=--12/7= 5remainter) remainder=5
year=12+5=17
ans: friday
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