Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Answer: Option
Explanation:
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
Discussion:
258 comments Page 25 of 26.
Lakshmi said:
4 years ago
How do we know the leap year of that specific year? How to know? Please explain.
(7)
Kets said:
4 years ago
@All.
Leap year means February has 29 days.
The last leap year was 2020.
Leap year comes every 4 years.
Eg;
2004, 2008, 2012,2016,2020,2024.
Leap year means February has 29 days.
The last leap year was 2020.
Leap year comes every 4 years.
Eg;
2004, 2008, 2012,2016,2020,2024.
(11)
HEpER said:
4 years ago
FROM 2007 Normal year- 1 0dd day.
2008 leap year- 2 odd days.
2009 & 2010 normal year - 1 & 1 odd day.
add all the odd numbers= 5 odd days.
Sunday+ 5 odd day= Friday.
2008 leap year- 2 odd days.
2009 & 2010 normal year - 1 & 1 odd day.
add all the odd numbers= 5 odd days.
Sunday+ 5 odd day= Friday.
(32)
Monty sharma said:
4 years ago
There was only one leap year and the difference of years is 4 now add 1 leap year (eg. 4+1).
Answer is 5 so add five to Sunday it became Friday.
Answer is 5 so add five to Sunday it became Friday.
(33)
Calnd said:
4 years ago
@All.
Here is the clarification.
Most of us have no prob in calculating no. Off odd days.
But confusion is there when considering the day code.
Simple;
1jan 2000 -sundays.
To
1jan 2006.
Odd days = 6.
2006 = 1.
2007 = 1.
2008 = 2.
2009 = 1.
1 jan 2006 so one day =one odd day.
Total=6
Odd day=7-6=1.
Starting day is sunday so again start from sunday then keep increasing by one
For odd 2=
1 = Monday,
2 = Tuesdays .
So on.
Here is the clarification.
Most of us have no prob in calculating no. Off odd days.
But confusion is there when considering the day code.
Simple;
1jan 2000 -sundays.
To
1jan 2006.
Odd days = 6.
2006 = 1.
2007 = 1.
2008 = 2.
2009 = 1.
1 jan 2006 so one day =one odd day.
Total=6
Odd day=7-6=1.
Starting day is sunday so again start from sunday then keep increasing by one
For odd 2=
1 = Monday,
2 = Tuesdays .
So on.
(15)
Monir said:
4 years ago
Thanks everyone for explaining.
(10)
Pradyumna Sinha said:
3 years ago
@ Sundar.
Thank you for giving a good explanation.
Thank you for giving a good explanation.
(23)
Sharukh said:
2 years ago
How to find the day of the week for 31st Oct 1998? Anyone, explain to me.
(49)
SUBASHINI said:
2 years ago
No.of days in 1 week = 7 days.
No.of days in x week = 7 * x = 7x.
No.of days in x week x days = 7x + x = 8x.
No.of days in x week = 7 * x = 7x.
No.of days in x week x days = 7x + x = 8x.
(27)
Arpit Kumar said:
2 years ago
Thanks, everyone for solving this clearly.
(36)
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