Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Sunday
Saturday
Friday
Wednesday
Answer: Option
Explanation:

On 31st December, 2005 it was Saturday.

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday.

Discussion:
261 comments Page 24 of 27.

Some x said:   2 decades ago
Vijaya please don't confuse students with your typical explanation. Sunder's explanation is pretty simple when compared to yours. Don't make students to give up their effort in learning something by giving these type of difficult explanations.

Deena said:   2 decades ago
Pavithra your formula is perfect and easy method. Thank you.

Rajellam said:   2 decades ago
Thank you sunder. Actually I don't know how to calculate. But now I can do with help of you. Thak you.

Siddharth said:   2 decades ago
Well done sundar.

Let me know that simple method to find leap year.

Priyanka said:   2 decades ago
Guys give a simple and easy method to find the leap year like pavithra has given to find the week day of a certain date.

Priya said:   2 decades ago
Multiples of 4 and multiples of 400 are leap years but multiples of 100 not a leap year

Akhtar said:   2 decades ago
I think sundar gave perfect ans.

DG1234 said:   2 decades ago
This formula does not work on leap year. Pavithra..I am so sorry

Sonu navgotri said:   2 decades ago
For non-leap year odd number = 1 .

For leap year odd number = 2.

Kamal said:   2 decades ago
Pavithra can you apply you are concept for this date?.

1st Jan 2008.

If please explain it with steps.


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