Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Answer: Option
Explanation:
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
Discussion:
258 comments Page 19 of 26.
Ayu said:
1 decade ago
I don't understand how to calculate leap year and odd day?
Bipin said:
1 decade ago
Pavithra You told us a very good way to solve the calendar question but only few things you left i.e related to leap year, this formula doesn't work for leap year, it works only for non-leap year.
@Dg1234.
You can solve leap year by this formula as told by Pavithra but only few things I have changed. Check out.
Formula For Leap Year:
0 - Apr, jul 0 - Sat
1 - Jan 1 - Sun
2 - May 2 - Mon
3 - Aug 3 - Tue
4 - Feb, mar, nov 4 - Wed
5 - Jun 5 - Thu
6 - Sep, dec 6 - Fri
7 - Sat
Note:- To find the odd days for leap year we have to add 6 only with this formula.
Formula: 6 + Day + Month + (Year-1900) + (year-1900)/4.
Eg. 4-feb-2004.
= 6+4+4+(2004-1900)+(2004-1900)/4.
= 6+8+104+(104/4).
= 118+26.
= 144.
= 144/7.
= Remainder = 4.
= Wednesday.
@Dg1234.
You can solve leap year by this formula as told by Pavithra but only few things I have changed. Check out.
Formula For Leap Year:
0 - Apr, jul 0 - Sat
1 - Jan 1 - Sun
2 - May 2 - Mon
3 - Aug 3 - Tue
4 - Feb, mar, nov 4 - Wed
5 - Jun 5 - Thu
6 - Sep, dec 6 - Fri
7 - Sat
Note:- To find the odd days for leap year we have to add 6 only with this formula.
Formula: 6 + Day + Month + (Year-1900) + (year-1900)/4.
Eg. 4-feb-2004.
= 6+4+4+(2004-1900)+(2004-1900)/4.
= 6+8+104+(104/4).
= 118+26.
= 144.
= 144/7.
= Remainder = 4.
= Wednesday.
(1)
Gayathri said:
1 decade ago
Given info is :
1.01.2006 --- Sunday.
Since 2006 is non leap year. 1 odd day
i.e 1 day extra for the next year.
1.01.2007 --- Monday.
similarly for 2007 .
1.01.2008 -- Tuesday.
2008 is a leap year. So 2 days extra.
1.01.2009 -- Thursday(2 days gap).
1.01.2010 -- Friday.
So Friday is answer.
1.01.2006 --- Sunday.
Since 2006 is non leap year. 1 odd day
i.e 1 day extra for the next year.
1.01.2007 --- Monday.
similarly for 2007 .
1.01.2008 -- Tuesday.
2008 is a leap year. So 2 days extra.
1.01.2009 -- Thursday(2 days gap).
1.01.2010 -- Friday.
So Friday is answer.
Krishna said:
1 decade ago
How 100 years having 24 leap years ?, If we divide by 4 it will be 25 leap years ! can anyone clarify my doubt?
Meethi said:
1 decade ago
//
How many times does the 29th days of the month occur in 400 consecutive years
1) 97 times 2) 4400 times 3) 4497 times 4) none
Sol: In 400 consecutive years there are 97 leap years. Hence in 400 consecutive years, February has the 29th day 97 times, and the remaining 11 months have the 29th day 400 x 11 or 4400 times.
Therefore, 29th day of the month occurs (4400 + 97) or 4497 times.
//
How to calculate leap years in 400 consecutive years ?
How many times does the 29th days of the month occur in 400 consecutive years
1) 97 times 2) 4400 times 3) 4497 times 4) none
Sol: In 400 consecutive years there are 97 leap years. Hence in 400 consecutive years, February has the 29th day 97 times, and the remaining 11 months have the 29th day 400 x 11 or 4400 times.
Therefore, 29th day of the month occurs (4400 + 97) or 4497 times.
//
How to calculate leap years in 400 consecutive years ?
Sangeeta said:
1 decade ago
But pavitra if I have to solve for 16th july 1776 which is less than 1900. Please tell me the solution.
Keepsmiling said:
1 decade ago
Nice mahesh. Its helpful.
Satishkumar said:
1 decade ago
Nice mahesh. , keep it up!
Saheb ali said:
1 decade ago
According to pavitra formula
15 aug 1947
=15+3+(1947-1900)+(1947-1900)/4
=18+47+47/4
=76/7
remainder 6
its friday!
15 aug 1947
=15+3+(1947-1900)+(1947-1900)/4
=18+47+47/4
=76/7
remainder 6
its friday!
Raaj said:
1 decade ago
@kamatchi the answer for ur question is( to find number of odd days )
be clear for every 7 days a cyle(week) wii be compleated so just divide the number of days with 7 the remainder will be the number of odd days for example number of odd days in leap year 366 divided by 7 so the remainder will be 2 days which is the number of odd days in a leap year
be clear for every 7 days a cyle(week) wii be compleated so just divide the number of days with 7 the remainder will be the number of odd days for example number of odd days in leap year 366 divided by 7 so the remainder will be 2 days which is the number of odd days in a leap year
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