Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Sunday
Saturday
Friday
Wednesday
Answer: Option
Explanation:

On 31st December, 2005 it was Saturday.

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday.

Discussion:
258 comments Page 17 of 26.

Karan said:   10 years ago
How many odd days are there till 1947?

Shivaram said:   10 years ago
Its simple:

2007-1 odd day (leap year).
2008-2 odd days (non leap).
2009-1 odd day (leap year).

= 1 + 1 + 2 + 1 (Jan 1= 1 day) = 5 = Friday.

Vinay said:   9 years ago
How to solve the problem method or what was the day on the 15th August 1947?

Bharathi said:   9 years ago
I need the correct answer. Which is very simple to understand?

Rajesh said:   9 years ago
In 100 year they found 76 odd & 24 leap year.

I cannot understand please any body help me?

Soubhagya said:   9 years ago
In 100 year we find leap year & non leap year first.
We take 99 years because 100th years is continues.

In 100/4 we get 24 leap year & 99-24=76 is normal yard.

In leap year we get 2 odd days,
In non-leap yard we get 1 odd day, Like this we can find leap the non leap years.

PRAVEEN KUMAR said:   9 years ago
How to solve the problem method or what was the day on the 16 JULY 1988.

Vijendra said:   9 years ago
It is helpful. Good question with good explanation. Thank you all.

Revathi said:   9 years ago
How can we know 2008 is leap year?

Dipesh said:   9 years ago
@Revathi. Divide by 4 is Leap Year.

This is Simple. Example 1st January 2014 is Sunday, then next year same date 1st january 2015 will be Monday.

Similarly, 1st January 2016 will be Tuesday.
Now, 2016 is leap year. So if the question asks what was the day on 1st January 2017 then it will increase by two days i.e Thursday.


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