Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Sunday
Saturday
Friday
Wednesday
Answer: Option
Explanation:

On 31st December, 2005 it was Saturday.

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday.

Discussion:
258 comments Page 17 of 26.

Visu said:   10 years ago
Miss @Pavithra.

Your calculation is wrong. Please correct your mistake.

Karan said:   10 years ago
How many odd days are there till 1947?

Shivaram said:   10 years ago
Its simple:

2007-1 odd day (leap year).
2008-2 odd days (non leap).
2009-1 odd day (leap year).

= 1 + 1 + 2 + 1 (Jan 1= 1 day) = 5 = Friday.

Vinay said:   10 years ago
How to solve the problem method or what was the day on the 15th August 1947?

Bharathi said:   10 years ago
I need the correct answer. Which is very simple to understand?

Rajesh said:   10 years ago
In 100 year they found 76 odd & 24 leap year.

I cannot understand please any body help me?

Soubhagya said:   10 years ago
In 100 year we find leap year & non leap year first.
We take 99 years because 100th years is continues.

In 100/4 we get 24 leap year & 99-24=76 is normal yard.

In leap year we get 2 odd days,
In non-leap yard we get 1 odd day, Like this we can find leap the non leap years.

PRAVEEN KUMAR said:   10 years ago
How to solve the problem method or what was the day on the 16 JULY 1988.

Vijendra said:   10 years ago
It is helpful. Good question with good explanation. Thank you all.

Revathi said:   9 years ago
How can we know 2008 is leap year?


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