Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Sunday
Saturday
Friday
Wednesday
Answer: Option
Explanation:

On 31st December, 2005 it was Saturday.

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday.

Discussion:
260 comments Page 15 of 26.

Kasinath @Hyd said:   1 decade ago
From 2010..... 2000 is a factor of 400.(A/C to leap year Formula).
Therefore Year 2000 is Leap year hence we get 0 odd days.

From remaining 10 Years we have,
8 Ordinary years and 2 leap years i.e.,(4th & 8th year).

=> 8*1 + 2*2 = 12 days.
12/7 = 1 week + 5 odd days.

A/C to formula 5th day represent Friday.

Mounika said:   1 decade ago
How we can find same day of another year?

Sunidhi said:   1 decade ago
Hey friends please help me please give me another formula to solve problems because by above condition all problems are not solved. Please help me.

Sumit said:   1 decade ago
Please just tell me how to find out leap year, and odd days?

Prabhas said:   1 decade ago
What is the day of 8-oct-1996?

Sohan bansal said:   1 decade ago
What is the even day?

Akshay dixit said:   1 decade ago
Yes, still I have doubt. Can any one give easy and clear method?

Manoj said:   1 decade ago
I am little confused with this particular question. Could you please explain in detail?

M Rajeswari said:   1 decade ago
Simple in question we have 2006 Jan 1 to 2010 Jan 1.

Here 2006, 2007, 2008, 2009, 2010.

In this number of odd days in each year is 1 but 2008 is is the leap year. So we can take extra one day so it is 2.

Then now total number of odd days is 6.

Now from Jan 1 2006 Sunday to 6th day of Jan 1 2010 is Friday.

I think it is helpful.

Ashwini said:   1 decade ago
Lot of confusion is there in calendar problems. Please give me clarity on finding odd days of leap and ordinary year and days also.


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