Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Answer: Option
Explanation:
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
Discussion:
258 comments Page 15 of 26.
Sumit said:
1 decade ago
Please just tell me how to find out leap year, and odd days?
Prabhas said:
1 decade ago
What is the day of 8-oct-1996?
Sohan bansal said:
1 decade ago
What is the even day?
Akshay dixit said:
1 decade ago
Yes, still I have doubt. Can any one give easy and clear method?
Manoj said:
1 decade ago
I am little confused with this particular question. Could you please explain in detail?
M Rajeswari said:
1 decade ago
Simple in question we have 2006 Jan 1 to 2010 Jan 1.
Here 2006, 2007, 2008, 2009, 2010.
In this number of odd days in each year is 1 but 2008 is is the leap year. So we can take extra one day so it is 2.
Then now total number of odd days is 6.
Now from Jan 1 2006 Sunday to 6th day of Jan 1 2010 is Friday.
I think it is helpful.
Here 2006, 2007, 2008, 2009, 2010.
In this number of odd days in each year is 1 but 2008 is is the leap year. So we can take extra one day so it is 2.
Then now total number of odd days is 6.
Now from Jan 1 2006 Sunday to 6th day of Jan 1 2010 is Friday.
I think it is helpful.
Ashwini said:
1 decade ago
Lot of confusion is there in calendar problems. Please give me clarity on finding odd days of leap and ordinary year and days also.
Sumanth geras said:
1 decade ago
Hello guys according to the formula.
Jan=1.
Feb=4.
Mar=4.
Apr=0.
May=2.
Jun=5.
Jul=0.
Aug=3.
Sep=6.
Oct=1.
Nov=4.
Dec=6.
Days:
S=1.
M=2.
T=3.
W=4.
Th=5.
F=6.
Sat=7 or 0.
Formula = Day+month no. + (x-1900) + (x-1900) /4.
X = The year we have to calculate.
Answer/7 = Day we require. We can calculate it for leap year also.
If the given date is before 1st mar' of leap year. The obtained answer is given date if it is. On and after 1st march leap year you should subtract 1 from answer.
Jan=1.
Feb=4.
Mar=4.
Apr=0.
May=2.
Jun=5.
Jul=0.
Aug=3.
Sep=6.
Oct=1.
Nov=4.
Dec=6.
Days:
S=1.
M=2.
T=3.
W=4.
Th=5.
F=6.
Sat=7 or 0.
Formula = Day+month no. + (x-1900) + (x-1900) /4.
X = The year we have to calculate.
Answer/7 = Day we require. We can calculate it for leap year also.
If the given date is before 1st mar' of leap year. The obtained answer is given date if it is. On and after 1st march leap year you should subtract 1 from answer.
Girish said:
1 decade ago
Is above formula is applicable to leap year?
Akki said:
10 years ago
In 100 year they found 76 odd & 24 leap year.
I cannot understand please any body help me?
I cannot understand please any body help me?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers