Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Answer: Option
Explanation:
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
Discussion:
258 comments Page 11 of 26.
Revathi said:
1 decade ago
Hi pavithra, tell me if they asked for the year with below 1900. Because the value will be gone to minus so what to do?
Gajendra Singh said:
8 years ago
Can someone help to me for this question?
If 31st July, 1993 was Friday, then what will be the day on 31st July, 2001?
If 31st July, 1993 was Friday, then what will be the day on 31st July, 2001?
Saheb ali said:
1 decade ago
According to pavitra formula
15 aug 1947
=15+3+(1947-1900)+(1947-1900)/4
=18+47+47/4
=76/7
remainder 6
its friday!
15 aug 1947
=15+3+(1947-1900)+(1947-1900)/4
=18+47+47/4
=76/7
remainder 6
its friday!
Sam said:
7 years ago
If 21st November falls five days before Wednesday then what will be the day on 25th December?
Can anyone answer this?
Can anyone answer this?
Rishika said:
9 years ago
If Thursday falls on 1st January 2015, what day of the week will be on 1st January 2016?
Give me the clear solution.
Give me the clear solution.
Anciya said:
4 years ago
Odd days in 1800 = 1800/7.
Thus we get quotient 52 and remainder 1.
So, the number of odd days in 1800 = 1 odd day.
Thus we get quotient 52 and remainder 1.
So, the number of odd days in 1800 = 1 odd day.
Soumya said:
6 years ago
6th day of August 1989 falls on Thursday.
Then the number of Sunday in that month are? Can anyone explain to me?
Then the number of Sunday in that month are? Can anyone explain to me?
Suresh said:
8 years ago
In 2007 -one odd day,
In 2008 -two odd days,
In 2009 -one odd day,
So 2010-(add 4 days to sunday).
ANS: Friday.
In 2008 -two odd days,
In 2009 -one odd day,
So 2010-(add 4 days to sunday).
ANS: Friday.
Kummari Hemanth said:
8 years ago
1600+400=6odd days.
10 =2+8
=4+8=12
=4odd days
Total=4+6/7=10/7=3odd days.
Jan=2.
All odd days =3+2=5=Friday.
10 =2+8
=4+8=12
=4odd days
Total=4+6/7=10/7=3odd days.
Jan=2.
All odd days =3+2=5=Friday.
(1)
SUBASHINI said:
2 years ago
No.of days in 1 week = 7 days.
No.of days in x week = 7 * x = 7x.
No.of days in x week x days = 7x + x = 8x.
No.of days in x week = 7 * x = 7x.
No.of days in x week x days = 7x + x = 8x.
(27)
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