Aptitude - Boats and Streams - Discussion

Discussion Forum : Boats and Streams - General Questions (Q.No. 4)
4.
A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is:
4
5
6
10
Answer: Option
Explanation:

Let the speed of the stream be x km/hr. Then,

Speed downstream = (15 + x) km/hr,

Speed upstream = (15 - x) km/hr.

30 + 30 = 4 1
(15 + x) (15 - x) 2

900 = 9
225 - x2 2

9x2 = 225

x2 = 25

x = 5 km/hr.

Video Explanation: https://youtu.be/lMFnNB3YQOo

Discussion:
63 comments Page 4 of 7.

Lakki said:   10 years ago
Any shortcut method for this sum?

Aary said:   10 years ago
How did we get 30*30 = 900?

Are we taking 30 common or what?

Roneet Jena said:   10 years ago
[(450-30x)+(450+30x)]/(225-x^2) = [900/(225-x^2)].

AdityaLath said:   10 years ago
Short trick:

D = z(x^2-y^2)/2x.

Where.

D = Distance.

Z = Time taken.

x = Speed of boat in still water.

y = Speed of stream.

30 = 9*(15^2-y^2)/2*2*15.
200 = 225-y^2.

y^2 = 25.
y = 5 answer.

Sneha said:   9 years ago
How you people got 9/2? Please explain that.

Anjali said:   9 years ago
Please explain it in an easy way, which will be helpful for me.

Ranjith said:   9 years ago
4 hours and 30 minutes as 9/2. Total in terms of km/ hr.

Muthu said:   9 years ago
@Ajax.

You answer is very simple. But I don't understand it please explain Clearly.

Eve said:   9 years ago
Why is it downstream + something and upstream - something?

Shubh said:   9 years ago
Agree @Arun D.


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