Aptitude - Boats and Streams - Discussion
Discussion Forum : Boats and Streams - General Questions (Q.No. 3)
3.
A boat running upstream takes 8 hours 48 minutes to cover a certain distance, while it takes 4 hours to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively?
Answer: Option
Explanation:
Let the man's rate upstream be x kmph and that downstream be y kmph.
Then, distance covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs.
![]() |
![]() |
x x 8 | 4 | ![]() |
= (y x 4) |
5 |
![]() |
44 | x =4y |
5 |
![]() |
11 | x. |
5 |
![]() |
![]() |
y + x | ![]() |
: | ![]() |
y - x | ![]() |
2 | 2 |
= | ![]() |
16x | x | 1 | ![]() |
: | ![]() |
6x | x | 1 | ![]() |
5 | 2 | 5 | 2 |
= | 8 | : | 3 |
5 | 5 |
= 8 : 3.
Discussion:
109 comments Page 2 of 11.
Ajit said:
5 years ago
Just look simple method:
Upward= 8 hr + 48 Min. = 8+48/60 = 44/5.
Downward = 4 hr.
Speed of stream = (44/5 -4)/2 = 2.4 hr.
Speed of boat = 4+2.4 = 6.4 hr.
So, Ratio is 6.4:2.4.
i.e 8:3.
Upward= 8 hr + 48 Min. = 8+48/60 = 44/5.
Downward = 4 hr.
Speed of stream = (44/5 -4)/2 = 2.4 hr.
Speed of boat = 4+2.4 = 6.4 hr.
So, Ratio is 6.4:2.4.
i.e 8:3.
(6)
Virendra kumar said:
5 years ago
Let,
Upstream speed = X kmph.
Downstream spead = Y kmph.
So,
We know that distance is the same.
And we know, D=SXT (speedxtime)
D= X(8+48/60) upstream case--->eq1
D=Y(4)---> eq 2
Now, equate both.
4Y = X(8+4/5).
4Y= X(44/5).
Y=X(11/5).
Y/X = 11/5.
So now relate as Y=11, X=5.
Now speed of water(S.W) = downstrean-upstream/2.
= Y-X/2.
=11-5/2 = 6/2 = 3.
Now, speed of boat = downstream - speed of the water.
= Y- (S.W).
= 11-3 = 8.
Now ratio of both as given in question,
Ratio of boat speed to water speed = 8/3.
Ratio = 8:3.
Hope you'll get it well.
Upstream speed = X kmph.
Downstream spead = Y kmph.
So,
We know that distance is the same.
And we know, D=SXT (speedxtime)
D= X(8+48/60) upstream case--->eq1
D=Y(4)---> eq 2
Now, equate both.
4Y = X(8+4/5).
4Y= X(44/5).
Y=X(11/5).
Y/X = 11/5.
So now relate as Y=11, X=5.
Now speed of water(S.W) = downstrean-upstream/2.
= Y-X/2.
=11-5/2 = 6/2 = 3.
Now, speed of boat = downstream - speed of the water.
= Y- (S.W).
= 11-3 = 8.
Now ratio of both as given in question,
Ratio of boat speed to water speed = 8/3.
Ratio = 8:3.
Hope you'll get it well.
(6)
Lakaka said:
2 years ago
Thank you. @Tushar Pawar.
(5)
Aman sankhyan said:
4 years ago
@All.
You did not mention which speed of the boat to be calculated if it was in the still water or downstream or against the stream!
You did not mention which speed of the boat to be calculated if it was in the still water or downstream or against the stream!
(3)
Mallika B said:
2 years ago
Can somebody please explain why have we done (y-x/2) in the required ratio step? If that is associated with downstream, why are we subtracting?
Please explain me.
Please explain me.
(3)
Sorsta said:
1 year ago
Well said, Thank you @Mahesh.
(3)
Kanchan said:
5 years ago
By using the formula we have;
Speed upstream = u-v.
Speed downstream= u+v.
Where u&v is speed of the boat in still water and speed of stream respectively.
Given that distance covered is equal so;
By the time distance formula;
Speed *time= distance.
Both the values put according to formula.
(u-v) *8*48/60=(u+v) 4.
(u-v) 8*4/5=(u+v) 4.
44/5u-44/5v= 4u+4v.
44/5u- 4u = 44/5v+4v.
u[44/5-4] = v[44/5+4].
24u = 64v.
u/v = 64/24.
u/v = 8/3.
So, the ratio between the speed of the boat and speed of the water current is;
8:3.
Speed upstream = u-v.
Speed downstream= u+v.
Where u&v is speed of the boat in still water and speed of stream respectively.
Given that distance covered is equal so;
By the time distance formula;
Speed *time= distance.
Both the values put according to formula.
(u-v) *8*48/60=(u+v) 4.
(u-v) 8*4/5=(u+v) 4.
44/5u-44/5v= 4u+4v.
44/5u- 4u = 44/5v+4v.
u[44/5-4] = v[44/5+4].
24u = 64v.
u/v = 64/24.
u/v = 8/3.
So, the ratio between the speed of the boat and speed of the water current is;
8:3.
(2)
Anish said:
1 decade ago
How this required ratio? pls explain?
(1)
Vikas verma said:
1 decade ago
Let the speed of the Boat be X kmph and Speed of the stream be Y kmph.
Then 44/5 * (X-Y) = 4 * (X+Y).
By solving the equation you will get X/Y = 8:3.
I hope you'll understand.
Then 44/5 * (X-Y) = 4 * (X+Y).
By solving the equation you will get X/Y = 8:3.
I hope you'll understand.
(1)
Hely said:
8 years ago
Boat speed=x,
Water speed=y then.
The upstream speed of boat=(x-y),
And downstream speed of boat=(x+y).
The distance of upstream =speed of downstream
so, distance=speed * time.
(x-y)*528 = (x+y)*240,
(x-y)*(11/5) = (x+y),
11x-11y = 5x+5y,
6x-16y = 0,
6x = 16y,
x/y = 16/6,
x/y = 8/3 (speed of boat/speed of water).
Water speed=y then.
The upstream speed of boat=(x-y),
And downstream speed of boat=(x+y).
The distance of upstream =speed of downstream
so, distance=speed * time.
(x-y)*528 = (x+y)*240,
(x-y)*(11/5) = (x+y),
11x-11y = 5x+5y,
6x-16y = 0,
6x = 16y,
x/y = 16/6,
x/y = 8/3 (speed of boat/speed of water).
(1)
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