Aptitude - Boats and Streams - Discussion
Discussion Forum : Boats and Streams - General Questions (Q.No. 3)
3.
A boat running upstream takes 8 hours 48 minutes to cover a certain distance, while it takes 4 hours to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively?
Answer: Option
Explanation:
Let the man's rate upstream be x kmph and that downstream be y kmph.
Then, distance covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs.
![]() |
![]() |
x x 8 | 4 | ![]() |
= (y x 4) |
5 |
![]() |
44 | x =4y |
5 |
![]() |
11 | x. |
5 |
![]() |
![]() |
y + x | ![]() |
: | ![]() |
y - x | ![]() |
2 | 2 |
= | ![]() |
16x | x | 1 | ![]() |
: | ![]() |
6x | x | 1 | ![]() |
5 | 2 | 5 | 2 |
= | 8 | : | 3 |
5 | 5 |
= 8 : 3.
Discussion:
109 comments Page 2 of 11.
Tushar Pawar said:
3 years ago
Distance Upstream = Distance Downstream.
Speed Upstream * Time Upstream = Speed Downstream * Time Downstream.
(x - y) * 44/5 = (x + y) * 4,
24x = 64y,
x:y = 8:3.
Speed Upstream * Time Upstream = Speed Downstream * Time Downstream.
(x - y) * 44/5 = (x + y) * 4,
24x = 64y,
x:y = 8:3.
(125)
Sourav ghosh said:
3 years ago
Thanks for this short trick @Mahesh.
(7)
Aman sankhyan said:
3 years ago
@All.
You did not mention which speed of the boat to be calculated if it was in the still water or downstream or against the stream!
You did not mention which speed of the boat to be calculated if it was in the still water or downstream or against the stream!
(3)
Mahesh said:
4 years ago
When the same distance is mentioned in this type of question best shortcut is the sum:difference. Nothing but 12hr 48 min: 4hr 48min.
Other than change completely minutes. so 768min:288 min = 8:3
Other than change completely minutes. so 768min:288 min = 8:3
(55)
Anshul said:
4 years ago
Speed = Distance/Time.
Downstream = (u-v) km/hr.
Upstream = (u+v) km/hr.
Converting time to mins gives;
8hrs. 48 mins = 528 mins.
4 hrs. = 240 mins.
Let, Distance travelled = x km.
Therefore,
u-v = x/528 ----> 1.
u+v = x/240 ----> 2.
On dividing 1/2.
Therefore, (u-v)/(u+v) = 240/528 = 10/22.
On solving u/v = 32/12 = 8/3.
Downstream = (u-v) km/hr.
Upstream = (u+v) km/hr.
Converting time to mins gives;
8hrs. 48 mins = 528 mins.
4 hrs. = 240 mins.
Let, Distance travelled = x km.
Therefore,
u-v = x/528 ----> 1.
u+v = x/240 ----> 2.
On dividing 1/2.
Therefore, (u-v)/(u+v) = 240/528 = 10/22.
On solving u/v = 32/12 = 8/3.
(11)
Ahamed Kabeer said:
4 years ago
Thank you everyone for explaining.
Marak said:
4 years ago
8*4/5 will give 44/5 only which is not equal to 8hr 48min.
Please someone explain it to me, how 8hr 48min, how it becomes 8*4/5?
Please someone explain it to me, how 8hr 48min, how it becomes 8*4/5?
Virendra kumar said:
5 years ago
Let,
Upstream speed = X kmph.
Downstream spead = Y kmph.
So,
We know that distance is the same.
And we know, D=SXT (speedxtime)
D= X(8+48/60) upstream case--->eq1
D=Y(4)---> eq 2
Now, equate both.
4Y = X(8+4/5).
4Y= X(44/5).
Y=X(11/5).
Y/X = 11/5.
So now relate as Y=11, X=5.
Now speed of water(S.W) = downstrean-upstream/2.
= Y-X/2.
=11-5/2 = 6/2 = 3.
Now, speed of boat = downstream - speed of the water.
= Y- (S.W).
= 11-3 = 8.
Now ratio of both as given in question,
Ratio of boat speed to water speed = 8/3.
Ratio = 8:3.
Hope you'll get it well.
Upstream speed = X kmph.
Downstream spead = Y kmph.
So,
We know that distance is the same.
And we know, D=SXT (speedxtime)
D= X(8+48/60) upstream case--->eq1
D=Y(4)---> eq 2
Now, equate both.
4Y = X(8+4/5).
4Y= X(44/5).
Y=X(11/5).
Y/X = 11/5.
So now relate as Y=11, X=5.
Now speed of water(S.W) = downstrean-upstream/2.
= Y-X/2.
=11-5/2 = 6/2 = 3.
Now, speed of boat = downstream - speed of the water.
= Y- (S.W).
= 11-3 = 8.
Now ratio of both as given in question,
Ratio of boat speed to water speed = 8/3.
Ratio = 8:3.
Hope you'll get it well.
(6)
Kanchan said:
5 years ago
By using the formula we have;
Speed upstream = u-v.
Speed downstream= u+v.
Where u&v is speed of the boat in still water and speed of stream respectively.
Given that distance covered is equal so;
By the time distance formula;
Speed *time= distance.
Both the values put according to formula.
(u-v) *8*48/60=(u+v) 4.
(u-v) 8*4/5=(u+v) 4.
44/5u-44/5v= 4u+4v.
44/5u- 4u = 44/5v+4v.
u[44/5-4] = v[44/5+4].
24u = 64v.
u/v = 64/24.
u/v = 8/3.
So, the ratio between the speed of the boat and speed of the water current is;
8:3.
Speed upstream = u-v.
Speed downstream= u+v.
Where u&v is speed of the boat in still water and speed of stream respectively.
Given that distance covered is equal so;
By the time distance formula;
Speed *time= distance.
Both the values put according to formula.
(u-v) *8*48/60=(u+v) 4.
(u-v) 8*4/5=(u+v) 4.
44/5u-44/5v= 4u+4v.
44/5u- 4u = 44/5v+4v.
u[44/5-4] = v[44/5+4].
24u = 64v.
u/v = 64/24.
u/v = 8/3.
So, the ratio between the speed of the boat and speed of the water current is;
8:3.
(2)
Vaishnavi said:
5 years ago
Upstream, x = b(speed of boat) - w(speed of water).
Downstream, y = b + w.
Equalling both using distance.
(b+w) *44/5 = (b-w) * 4.
(b+w)*11/5 = (b-w),
11b+11w = 5b-5w.
6b = -16w(ignore negative sign).
b/w = 8/3.
So, b : w = 8 : 3.
Downstream, y = b + w.
Equalling both using distance.
(b+w) *44/5 = (b-w) * 4.
(b+w)*11/5 = (b-w),
11b+11w = 5b-5w.
6b = -16w(ignore negative sign).
b/w = 8/3.
So, b : w = 8 : 3.
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