Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 3)
3.
A can contains a mixture of two liquids A and B is the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially?
Answer: Option
Explanation:
Suppose the can initially contains 7x and 5x of mixtures A and B respectively.
Quantity of A in mixture left = | ![]() |
7x - | 7 | x 9 | ![]() |
litres = | ![]() |
7x - | 21 | ![]() |
12 | 4 |
Quantity of B in mixture left = | ![]() |
5x - | 5 | x 9 | ![]() |
litres = | ![]() |
5x - | 15 | ![]() |
12 | 4 |
![]() |
|
= | 7 | |||||
|
9 |
![]() |
28x - 21 | = | 7 |
20x + 21 | 9 |
252x - 189 = 140x + 147
112x = 336
x = 3.
So, the can contained 21 litres of A.
Discussion:
100 comments Page 4 of 10.
SAM said:
8 years ago
A : B.
7 : 5
7 : 9
Here A is not changed ,but B added 9 liters more,
B = 9 - 5 = 4 difference by adding 9 on [ 9+7=16].
9/4 * 16 = 36.
Total is 36.
A =36 * 7/12 = 21.
7 : 5
7 : 9
Here A is not changed ,but B added 9 liters more,
B = 9 - 5 = 4 difference by adding 9 on [ 9+7=16].
9/4 * 16 = 36.
Total is 36.
A =36 * 7/12 = 21.
Suri said:
8 years ago
The Whole Question is clear but Why we are Multiplying with 9 in ration (7/12) *9.
What does multiplying with 9 litres means?
Please answer thank you.
What does multiplying with 9 litres means?
Please answer thank you.
Dhivya said:
8 years ago
Initial A:B 7:5 ->12Parts.
New ratio A:B 7:9.
In the new ratio only 4 parts is changed so, 4parts=9litre.
for 12 parts =27litre + 9Litre.
Initial Litre is 36.
for Initial liquid A :7/12 *36 = 21Litre.
New ratio A:B 7:9.
In the new ratio only 4 parts is changed so, 4parts=9litre.
for 12 parts =27litre + 9Litre.
Initial Litre is 36.
for Initial liquid A :7/12 *36 = 21Litre.
Dhivya said:
8 years ago
Initial A:B 7:5 ->12Parts.
New ratio A:B 7:9.
In the new ratio only 4 parts is changed so, 4parts=9litre.
for 12 parts =27litre + 9Litre.
Initial Litre is 36.
for Initial liquid A :7/12 *36 = 21Litre.
New ratio A:B 7:9.
In the new ratio only 4 parts is changed so, 4parts=9litre.
for 12 parts =27litre + 9Litre.
Initial Litre is 36.
for Initial liquid A :7/12 *36 = 21Litre.
BDSHAHJAHAN said:
8 years ago
Good job @Silu, @Anilkumar.
Kia said:
8 years ago
Let A initially be 7x & B be 5x.
The amount of A in a mixture is 7x /12& the amount of B in a mixture is 5x/12.
Let the total amount of mixture be x.
Now, it is given that 9litre of the mixture is taken out from the mixture & it can fill up with an amount of B.
Now, amount of new mixture be-
The Amount of A is 7(x-9)/12.
The amount of Bis 5(x-9)/12+9.
Now, it is given that the resultant ratio is 7/9.
7(X-9)/12:5(x-9)/12+9 = 7/9.
Now, it can easily solve to get the value of x=36 which is put in 7x/12 then get the amount of A is 21.
The amount of A in a mixture is 7x /12& the amount of B in a mixture is 5x/12.
Let the total amount of mixture be x.
Now, it is given that 9litre of the mixture is taken out from the mixture & it can fill up with an amount of B.
Now, amount of new mixture be-
The Amount of A is 7(x-9)/12.
The amount of Bis 5(x-9)/12+9.
Now, it is given that the resultant ratio is 7/9.
7(X-9)/12:5(x-9)/12+9 = 7/9.
Now, it can easily solve to get the value of x=36 which is put in 7x/12 then get the amount of A is 21.
Karen said:
8 years ago
Do we use the ratio? Please tell.
Saurabh mishra said:
8 years ago
Let A initially be 7x & B be 5x.
The amount of A in a mixture is 7x /12& the amount of B in a mixture is 5x/12.
Let total amount of mixture be x.
Now, it is given that 9litre of the mixture is taken out from the mixture & it can fill up with an amount of B.
Now, amount of new mixture be-
Amount of A is 7(x-9)/12.
The amount of Bis 5(x-9)/12+9.
Now, it is given that the resultant ratio is 7/9.
7(X-9)/12:5(x-9)/12+9 = 7/9.
Now, it can easily solve to get the value of x=36 which is put in 7x/12 then get the amount of A is 21.
The amount of A in a mixture is 7x /12& the amount of B in a mixture is 5x/12.
Let total amount of mixture be x.
Now, it is given that 9litre of the mixture is taken out from the mixture & it can fill up with an amount of B.
Now, amount of new mixture be-
Amount of A is 7(x-9)/12.
The amount of Bis 5(x-9)/12+9.
Now, it is given that the resultant ratio is 7/9.
7(X-9)/12:5(x-9)/12+9 = 7/9.
Now, it can easily solve to get the value of x=36 which is put in 7x/12 then get the amount of A is 21.
(1)
ESWARARAO S said:
8 years ago
When mixture removed, same 7:9 remains.
7 : 5 when Mixture B,
Gained 3 points of B mixture for 9 litres.
So 1 Point of mixture is 3 litres,
And, 7 Points of A mixture is 7 * 3= 21 litres.
7 : 5 when Mixture B,
Gained 3 points of B mixture for 9 litres.
So 1 Point of mixture is 3 litres,
And, 7 Points of A mixture is 7 * 3= 21 litres.
Teju said:
9 years ago
7x+5x-9 = 9x(mixture removed equals B added)
X = 3
7x = 21= A.
X = 3
7x = 21= A.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers