Aptitude - Alligation or Mixture - Discussion

Discussion Forum : Alligation or Mixture - General Questions (Q.No. 14)
14.
8 litres are drawn from a cask full of wine and is then filled with water. This operation is performed three more times. The ratio of the quantity of wine now left in cask to that of water is 16 : 65. How much wine did the cask hold originally?
18 litres
24 litres
32 litres
42 litres
Answer: Option
Explanation:

Let the quantity of the wine in the cask originally be x litres.

Then, quantity of wine left in cask after 4 operations = x 1 - 8 4  litres.
x

x(1 - (8/x))4 = 16
x 81

1 - 8 4 = 2 4
x 3

x - 8 = 2
x 3

3x - 24 = 2x

x = 24.

Discussion:
96 comments Page 9 of 10.

Amrita said:   6 years ago
This will be more understandable by using the fomula (Q/T)=(1-R/T)^n.

Here Q=16(present quantity,from the ratio).
T=81(total quantity of solution,16+65),
R=8(replacing quantity).
n=4.

So,
(16/81)=1-8/T)^4,
We have to find the value of T In RHS,
So by taking the fourth root of 16/8 we get 2/3,
Now by solving the eq 2/3=(1-8/T).
T=24.

Prashanth reddy said:   6 years ago
Here cask initially contains x lit of wine.

Each time the operation is repeated the same amount of water is replaced by wine.

So, after any number of operations, the final quantity in cask is always x.
Now wine:water = 16:65.
Wine:total mixture = 16:81.
Wine left after final operation:total mixture=16:8.

Mahesh said:   5 years ago
The resulting ratio is 16:65.

How we get 16/81?

Please explain.

Vivek Rajput said:   5 years ago
@Sanjay(first comment) x is the total quantity.

x(1 - (8/x))4
--------------- = 16/81.
x

the numerator is the quantity of wine left and the denominator is the total quantity.

Sadiq said:   5 years ago
@Mahesh.

After 4 operations, wine and water ratio is 16:65.
Just assume that original wine was (16+65)=81, which we assumed by x.

Rajesh said:   5 years ago
Final wine = x{1 - 8/x}^4 ----> 1.

where x is the original wine quantity.
(As from formula)
Now given final wine to water ratio i.e.
Wine: water = 16:65.

Therefore final wine (in litres) = (16÷81)*(x) where ----> 2
81 = 16 +65 represnting total volume.
X = also representing initial total volume.
Equating 1 and 2 we will get the answer.
(1)

Govind Prajapati said:   5 years ago
How 16:65 is converted to 16:81? Please explain me.
(1)

Niket Polle said:   5 years ago
Thanks all.
(1)

Santosh said:   5 years ago
Let x be initial volume(in lit) of wine.
By formula final amount of wine after n(=4) iteration = x{1 - 8/x}^4 ---->1.

Given the final ratio of wine to water is 16:65.
So the volume of wine in the final iteration is {16/(16+65)}x -------> 2.

Equate 1 and 2,
And we get x=24.

Barath s said:   4 years ago
For those who don't understand why it is divided by x?

Here in 16/81, 81 can be taken as total mixture are 81y is the total capacity of the cask. So x is the total wine that was kept at first which is nothing but the total capacity of the cask.
(2)


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