Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 14)
14.
8 litres are drawn from a cask full of wine and is then filled with water. This operation is performed three more times. The ratio of the quantity of wine now left in cask to that of water is 16 : 65. How much wine did the cask hold originally?
Answer: Option
Explanation:
Let the quantity of the wine in the cask originally be x litres.
Then, quantity of wine left in cask after 4 operations = | ![]() |
x | ![]() |
1 - | 8 | ![]() |
4 | ![]() |
x |
![]() |
![]() |
x(1 - (8/x))4 | ![]() |
= | 16 |
x | 81 |
![]() |
![]() |
1 - | 8 | ![]() |
4 | = | ![]() |
2 | ![]() |
4 |
x | 3 |
![]() |
![]() |
x - 8 | ![]() |
= | 2 |
x | 3 |
3x - 24 = 2x
x = 24.
Discussion:
96 comments Page 6 of 10.
Chitwanjit said:
1 decade ago
How come it get divided by x, While it should be quantity of water ? Alternate way can be dividing by x and putting in 16/97 instead of 16/81.
Sanjay said:
1 decade ago
Could anyone explain the method above?
I couldn't make out why x is divided when it should have been divided by the quantity of water.
I couldn't make out why x is divided when it should have been divided by the quantity of water.
Priya said:
1 decade ago
@sanjay
Its a formula....
[a(1-X/a)n]
a=initial quantity, X=quantity taken out, n=raised power on small bracket(no. of action done)
Its a formula....
[a(1-X/a)n]
a=initial quantity, X=quantity taken out, n=raised power on small bracket(no. of action done)
Dileep said:
1 decade ago
@Reeya.
I didn't get you. what you are saying.
From the given information we can write it as,
x(1-8/x)^4 = 16/81.
i.e x = 24.
I didn't get you. what you are saying.
From the given information we can write it as,
x(1-8/x)^4 = 16/81.
i.e x = 24.
Sadiq said:
5 years ago
@Mahesh.
After 4 operations, wine and water ratio is 16:65.
Just assume that original wine was (16+65)=81, which we assumed by x.
After 4 operations, wine and water ratio is 16:65.
Just assume that original wine was (16+65)=81, which we assumed by x.
Venkat said:
6 years ago
@All.
16x/81 is the quantity of wine in the mixture is given so equate to x(1-8/x)^4. (x is fixed litres of mixture).
16x/81 is the quantity of wine in the mixture is given so equate to x(1-8/x)^4. (x is fixed litres of mixture).
Rupesh said:
1 decade ago
Answer for x.
As the ratio is 16/65 (Wine:Water).
So the amount wine/total mixture = 16/65+16 = 16/81.
Here x = 81.
As the ratio is 16/65 (Wine:Water).
So the amount wine/total mixture = 16/65+16 = 16/81.
Here x = 81.
Vijay said:
9 years ago
If this process done with 5 litres only one time, and the given ratio is 361:39. What will be the answer?
Salaj Mondal said:
4 years ago
x^4 = 81
=>x=3
y^4=16
=>y=2
x - y
= 3 - 2
= 1.
1 ratio means 8 litre.
so, 3 ratio means 24 litre.
=>x=3
y^4=16
=>y=2
x - y
= 3 - 2
= 1.
1 ratio means 8 litre.
so, 3 ratio means 24 litre.
(4)
Manju said:
1 decade ago
Not understood. Can anyone help? Why divide by x? Also shouldn't ratio be directly used as a fraction?
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