Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 14)
14.
8 litres are drawn from a cask full of wine and is then filled with water. This operation is performed three more times. The ratio of the quantity of wine now left in cask to that of water is 16 : 65. How much wine did the cask hold originally?
Answer: Option
Explanation:
Let the quantity of the wine in the cask originally be x litres.
Then, quantity of wine left in cask after 4 operations = | ![]() |
x | ![]() |
1 - | 8 | ![]() |
4 | ![]() |
x |
![]() |
![]() |
x(1 - (8/x))4 | ![]() |
= | 16 |
x | 81 |
![]() |
![]() |
1 - | 8 | ![]() |
4 | = | ![]() |
2 | ![]() |
4 |
x | 3 |
![]() |
![]() |
x - 8 | ![]() |
= | 2 |
x | 3 |
3x - 24 = 2x
x = 24.
Discussion:
96 comments Page 4 of 10.
Venky said:
8 years ago
It should be 16:81.
Sajan said:
8 years ago
Explanation for (x(1 - 8/x)pow 4)/x =16/81.
In question it's given water/wine = 16/65,
We assumed x= total wine in cask,
That means total capacity of cask is x,
So looking at ratio 16/65 we can see that total
Capacity is (16+65) = 81.
(x(1 - 8/x)pow 4) is nothing but the wine replaced by water, In other word, it is the quantity of water in a final mixture of water and wine.
So, (x(1 - 8/x)pow 4)/x must be 16/81.
In question it's given water/wine = 16/65,
We assumed x= total wine in cask,
That means total capacity of cask is x,
So looking at ratio 16/65 we can see that total
Capacity is (16+65) = 81.
(x(1 - 8/x)pow 4) is nothing but the wine replaced by water, In other word, it is the quantity of water in a final mixture of water and wine.
So, (x(1 - 8/x)pow 4)/x must be 16/81.
Sobat singh said:
8 years ago
Let cask is full of wine = x lt.
After 4 operations wine left= x(1-8/x)^4.
Ratio of water to wine after operation = 16/65.
From this ratio part of wine present after op= 16/81.
Total amount of mixture is = x(as cask is full of x quantity).
Now,
x(1-8/x)^4.
---------------- = 16/81
X
From this x = 24.
After 4 operations wine left= x(1-8/x)^4.
Ratio of water to wine after operation = 16/65.
From this ratio part of wine present after op= 16/81.
Total amount of mixture is = x(as cask is full of x quantity).
Now,
x(1-8/x)^4.
---------------- = 16/81
X
From this x = 24.
Dee said:
8 years ago
Lets wine x.
After 1st time wine remain x-8
Now, ratio of wine:water x-8:8
So 2nd time wine removed=(x-8) * (8/x)
After 2nd time wine remain=(x-8) - (x-8) * (8/x).
= (x-8){1-8/x}
= x(1-8/x)(1-8/x)
= x(1-8/x)^2.
After 3rd time wine remain=[x(1-8/x)^2]-[x(1-8/x)^2]x/8.
= [x(1-8/x)^2]{1-8/x}
= [x(1-8/x)^2](1-8/x)
= x(1-8/x)^3 and so on;
For n operation remain=x(1-8/x)^n.
After 1st time wine remain x-8
Now, ratio of wine:water x-8:8
So 2nd time wine removed=(x-8) * (8/x)
After 2nd time wine remain=(x-8) - (x-8) * (8/x).
= (x-8){1-8/x}
= x(1-8/x)(1-8/x)
= x(1-8/x)^2.
After 3rd time wine remain=[x(1-8/x)^2]-[x(1-8/x)^2]x/8.
= [x(1-8/x)^2]{1-8/x}
= [x(1-8/x)^2](1-8/x)
= x(1-8/x)^3 and so on;
For n operation remain=x(1-8/x)^n.
Amit said:
8 years ago
As 65:15 is wine as to water ratio is given means total solution was (65+16)=81 which was totally quantity of wine before removal of 8 liter wine that's why it is x = total =81.
Where x=initial quantity of wine.
W:T = x(1-(8/x))^4:x = 16/81.
Where x=initial quantity of wine.
W:T = x(1-(8/x))^4:x = 16/81.
Vijay said:
9 years ago
If this process done with 5 litres only one time, and the given ratio is 361:39. What will be the answer?
Lekhraj said:
9 years ago
Suppose, the initial amount of mixture is X.
Remaining quantity of wine after four operations ( P suppose)= X*(1-8/X)^4 = P(Suppose)
The total quantity of mixture will always remain X because how much mixture we are removing same we are adding as water and quantity which is not of wine that is water so after 4 operations quantity of water in the mixture = X-P.
Given: remaining wine/water=16/65= P/(X-P)...................(1).
By solving equation (1) we will get P/X=16/81, that is the ratio of remaining wine and present water in the mixture.
So this is the explanation why he divided by X.
Further is simple as we supposed P = X * (1-8/X) ^4.
So, P/X = (1-8/X)^4 = 16/81.............(2).
Solving equation (2) we get X = 24.
Remaining quantity of wine after four operations ( P suppose)= X*(1-8/X)^4 = P(Suppose)
The total quantity of mixture will always remain X because how much mixture we are removing same we are adding as water and quantity which is not of wine that is water so after 4 operations quantity of water in the mixture = X-P.
Given: remaining wine/water=16/65= P/(X-P)...................(1).
By solving equation (1) we will get P/X=16/81, that is the ratio of remaining wine and present water in the mixture.
So this is the explanation why he divided by X.
Further is simple as we supposed P = X * (1-8/X) ^4.
So, P/X = (1-8/X)^4 = 16/81.............(2).
Solving equation (2) we get X = 24.
Vijay said:
9 years ago
Thanks @Ayush.
Srihu said:
9 years ago
Thanks, @Pravu.
You explained the derivation of the formula is very well.
You explained the derivation of the formula is very well.
Hardeep Singh said:
9 years ago
Let initial quantity of wine = x.
After, 4 operations, quantity of wine left = x(1 - 8/x)^4.
Also the quantity of wine in the jar = (16/81)x.
Therefore, x(1-8/x)^4 = (16/81)x.
On solving, x = 24.
After, 4 operations, quantity of wine left = x(1 - 8/x)^4.
Also the quantity of wine in the jar = (16/81)x.
Therefore, x(1-8/x)^4 = (16/81)x.
On solving, x = 24.
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