Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 14)
14.
8 litres are drawn from a cask full of wine and is then filled with water. This operation is performed three more times. The ratio of the quantity of wine now left in cask to that of water is 16 : 65. How much wine did the cask hold originally?
Answer: Option
Explanation:
Let the quantity of the wine in the cask originally be x litres.
Then, quantity of wine left in cask after 4 operations = | ![]() |
x | ![]() |
1 - | 8 | ![]() |
4 | ![]() |
x |
![]() |
![]() |
x(1 - (8/x))4 | ![]() |
= | 16 |
x | 81 |
![]() |
![]() |
1 - | 8 | ![]() |
4 | = | ![]() |
2 | ![]() |
4 |
x | 3 |
![]() |
![]() |
x - 8 | ![]() |
= | 2 |
x | 3 |
3x - 24 = 2x
x = 24.
Discussion:
96 comments Page 2 of 10.
Rajesh said:
5 years ago
Final wine = x{1 - 8/x}^4 ----> 1.
where x is the original wine quantity.
(As from formula)
Now given final wine to water ratio i.e.
Wine: water = 16:65.
Therefore final wine (in litres) = (16÷81)*(x) where ----> 2
81 = 16 +65 represnting total volume.
X = also representing initial total volume.
Equating 1 and 2 we will get the answer.
where x is the original wine quantity.
(As from formula)
Now given final wine to water ratio i.e.
Wine: water = 16:65.
Therefore final wine (in litres) = (16÷81)*(x) where ----> 2
81 = 16 +65 represnting total volume.
X = also representing initial total volume.
Equating 1 and 2 we will get the answer.
(1)
Athira said:
3 years ago
Here, x is just used for simplification.
Suppose we write the equation as:
[x({1-(8/x)}^4)]/32 = 16/65 it is correct.
But, it will be very difficult to simplify because of the fifth power in the resulting equation that we have to solve.
So instead, we take the ratio of wine to total liquid in the end. We can find the total liquid by simply adding 16+65, ie, wine=water, so this is not an issue. This way, we can eliminate the x outside bracket in the numerator and find the answer very quickly.
Hope it's clear.
Suppose we write the equation as:
[x({1-(8/x)}^4)]/32 = 16/65 it is correct.
But, it will be very difficult to simplify because of the fifth power in the resulting equation that we have to solve.
So instead, we take the ratio of wine to total liquid in the end. We can find the total liquid by simply adding 16+65, ie, wine=water, so this is not an issue. This way, we can eliminate the x outside bracket in the numerator and find the answer very quickly.
Hope it's clear.
(1)
Niket Polle said:
5 years ago
Thanks all.
(1)
Santosh said:
5 years ago
Let x be initial volume(in lit) of wine.
By formula final amount of wine after n(=4) iteration = x{1 - 8/x}^4 ---->1.
Given the final ratio of wine to water is 16:65.
So the volume of wine in the final iteration is {16/(16+65)}x -------> 2.
Equate 1 and 2,
And we get x=24.
By formula final amount of wine after n(=4) iteration = x{1 - 8/x}^4 ---->1.
Given the final ratio of wine to water is 16:65.
So the volume of wine in the final iteration is {16/(16+65)}x -------> 2.
Equate 1 and 2,
And we get x=24.
(1)
Govind Prajapati said:
5 years ago
How 16:65 is converted to 16:81? Please explain me.
(1)
Vijay said:
9 years ago
Thanks @Ayush.
Ananta chatterjee said:
10 years ago
See the formula is well understood a(1-b/a)^n. Now even after adding and removing water we have the total amount o be the same that is x.
So we have 16/81 of x = This is the part of wine left that should be equal to the formula.
So we have 16/81 of x = This is the part of wine left that should be equal to the formula.
Venky said:
8 years ago
It should be 16:81.
Sajan said:
9 years ago
Explanation for (x(1 - 8/x)pow 4)/x =16/81.
In question it's given water/wine = 16/65,
We assumed x= total wine in cask,
That means total capacity of cask is x,
So looking at ratio 16/65 we can see that total
Capacity is (16+65) = 81.
(x(1 - 8/x)pow 4) is nothing but the wine replaced by water, In other word, it is the quantity of water in a final mixture of water and wine.
So, (x(1 - 8/x)pow 4)/x must be 16/81.
In question it's given water/wine = 16/65,
We assumed x= total wine in cask,
That means total capacity of cask is x,
So looking at ratio 16/65 we can see that total
Capacity is (16+65) = 81.
(x(1 - 8/x)pow 4) is nothing but the wine replaced by water, In other word, it is the quantity of water in a final mixture of water and wine.
So, (x(1 - 8/x)pow 4)/x must be 16/81.
Sobat singh said:
9 years ago
Let cask is full of wine = x lt.
After 4 operations wine left= x(1-8/x)^4.
Ratio of water to wine after operation = 16/65.
From this ratio part of wine present after op= 16/81.
Total amount of mixture is = x(as cask is full of x quantity).
Now,
x(1-8/x)^4.
---------------- = 16/81
X
From this x = 24.
After 4 operations wine left= x(1-8/x)^4.
Ratio of water to wine after operation = 16/65.
From this ratio part of wine present after op= 16/81.
Total amount of mixture is = x(as cask is full of x quantity).
Now,
x(1-8/x)^4.
---------------- = 16/81
X
From this x = 24.
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