Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 9)
9.
A jar full of whisky contains 40% alcohol. A part of this whisky is replaced by another containing 19% alcohol and now the percentage of alcohol was found to be 26%. The quantity of whisky replaced is:
Answer: Option
Explanation:
By the rule of alligation, we have:
| Strength of first jar Strength of 2nd jar | ||
| 40% | Mean Strength 26% | 19% |
| 7 | 14 | |
So, ratio of 1st and 2nd quantities = 7 : 14 = 1 : 2
 Required quantity replaced = |
2 |
| 3 |
Discussion:
63 comments Page 4 of 7.
Mounika said:
9 years ago
Can anyone make it easy to understand?
Manish said:
9 years ago
It should be 1/3 right? because in the question it was asked that quantity of whisky replaced not alcohol.
Tanut said:
9 years ago
I think the solution is wrong because 2/3 is the amount of alcohol the 2nd mixture contains which has been combined with the 1st mixture. So 2/3 can't be the whole mixture.
Vejay said:
9 years ago
@Anhat.
Please see the comment of Moncy, it'll clear your doubt.
Please see the comment of Moncy, it'll clear your doubt.
Anhat said:
9 years ago
How 2/3 come?
Please explain. I am still confused.
Please explain. I am still confused.
Sonam said:
9 years ago
Since their in question only one jar is mention where replacing is being done, but in solution why they have mentioned 1st jar strength and second jar strength? Where does this second jar come from? please help me to explain.
Deepak Kumar said:
10 years ago
Its too simple,
According to allegation rule,
Chip/Deep = (Deep-Common)/(Common-Chip).
Chip/Deep = (0.40-0.26)/(0.26-0.19).
Chip/Deep = 0.14/0.07.
Chip/Deep = 2/1.
So, Chip (whisky with 19% alcohol) = 2/3rd of total final mixture.
Deep (whisky with 40% alcohol) = 1/3rd of total final mixture.
Now here is the logic. According to question, whisky containing 40% alcohol (deep) was replaced with whisky containing 19% alcohol (chip) to make this final mixture. So 2/3rd of whisky (40%) was replaced with 2/3rd of whisky (19%).
So answer = 2/3.
According to allegation rule,
Chip/Deep = (Deep-Common)/(Common-Chip).
Chip/Deep = (0.40-0.26)/(0.26-0.19).
Chip/Deep = 0.14/0.07.
Chip/Deep = 2/1.
So, Chip (whisky with 19% alcohol) = 2/3rd of total final mixture.
Deep (whisky with 40% alcohol) = 1/3rd of total final mixture.
Now here is the logic. According to question, whisky containing 40% alcohol (deep) was replaced with whisky containing 19% alcohol (chip) to make this final mixture. So 2/3rd of whisky (40%) was replaced with 2/3rd of whisky (19%).
So answer = 2/3.
(1)
Ramakrishna said:
10 years ago
I think this is the easy method.
If the 40% will alcohol is a1 = 40% and another 19% is a2 = 19%.
And in the resultant is A = 26%.
Any solution Alligation is given as:
Average A = (n1a1*n2a2)/(n1+n2).
n1:n2 = (a1-A)/(A-a2).
n1:n2 = (40-26):(26-19) then the result is 14:7 that will give 2:1.
If the 40% will alcohol is a1 = 40% and another 19% is a2 = 19%.
And in the resultant is A = 26%.
Any solution Alligation is given as:
Average A = (n1a1*n2a2)/(n1+n2).
n1:n2 = (a1-A)/(A-a2).
n1:n2 = (40-26):(26-19) then the result is 14:7 that will give 2:1.
Harshel jain said:
10 years ago
I am confused from this stick method.
Sanzzz said:
1 decade ago
Whisky taken out from the jar 1 is 1/3, but the whisky replaced or added is 2/3. I think now you can understand?
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