Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 9)
9.
A jar full of whisky contains 40% alcohol. A part of this whisky is replaced by another containing 19% alcohol and now the percentage of alcohol was found to be 26%. The quantity of whisky replaced is:
Answer: Option
Explanation:
By the rule of alligation, we have:
| Strength of first jar Strength of 2nd jar | ||
| 40% | Mean Strength 26% | 19% |
| 7 | 14 | |
So, ratio of 1st and 2nd quantities = 7 : 14 = 1 : 2
 Required quantity replaced = |
2 |
| 3 |
Discussion:
63 comments Page 2 of 7.
Jasleen said:
1 decade ago
@mohan:
the vessel contains 40% alcohol initially and then some of it is replaced by 19% alcohol and final is 26%. so if uve to find the strength ratio, it is (26-19):(40-26). so it becomes 7:14 i.e. 1:2. and if we are reqd to find quantity of second one, so its 2/(1+2) i.e. 2/3.
the vessel contains 40% alcohol initially and then some of it is replaced by 19% alcohol and final is 26%. so if uve to find the strength ratio, it is (26-19):(40-26). so it becomes 7:14 i.e. 1:2. and if we are reqd to find quantity of second one, so its 2/(1+2) i.e. 2/3.
(1)
Udayana pratap said:
7 years ago
Container 1 has 40% alchol.
They mixed 19% of alcohol and they get 26% alcohol mix.
By using of allegation rule we are getting 1:2. This means we add 1 part from container 1 and remaining from container two. That 2 parts.
The total is 3 parts.
So, the Answer is 2/3.
They mixed 19% of alcohol and they get 26% alcohol mix.
By using of allegation rule we are getting 1:2. This means we add 1 part from container 1 and remaining from container two. That 2 parts.
The total is 3 parts.
So, the Answer is 2/3.
(1)
Harshita said:
2 years ago
Suppose 1 liter of whisky and x of it removed,
(1-x).
Now x part id added with 19 % of alcohol content and the total we know is 26%.
Hence 40 per cent of (1-x)summed with 19% of x gives 26 per cent.
40(1-x)/100+19x/100 = 26/100.
= > x = 2/3.
(1-x).
Now x part id added with 19 % of alcohol content and the total we know is 26%.
Hence 40 per cent of (1-x)summed with 19% of x gives 26 per cent.
40(1-x)/100+19x/100 = 26/100.
= > x = 2/3.
(24)
Nikhil said:
6 years ago
1:2 is ratio now quantity of alcohol in it is 1/3 ok, now the question is asking about the quantity of whiskey that is 1-1/3 so we got 2/3 answer because 1/3which we got earlier is the part of alcohol now 2/3 is the part of whiskey replaced.
(1)
Sonam said:
9 years ago
Since their in question only one jar is mention where replacing is being done, but in solution why they have mentioned 1st jar strength and second jar strength? Where does this second jar come from? please help me to explain.
Explorer said:
9 years ago
Here one confusion is about 2/3.
Final mixture should be in 1:2 proportion in which A is 1/3 part and B is 2/3 part. Here B is introduced in mixture by replacing A so Replaced quantity is 2/3.
Hope this can help. Thanks
Final mixture should be in 1:2 proportion in which A is 1/3 part and B is 2/3 part. Here B is introduced in mixture by replacing A so Replaced quantity is 2/3.
Hope this can help. Thanks
Sai said:
9 years ago
Quantity replaced in 1st jar is nothing but quantity added from 2nd jar. So, from the answer, the ratio is 1 : 2 which means the total number of parts (1 + 2) is 3.
Therefore the quantity of whiskey replaced is 2/3.
Therefore the quantity of whiskey replaced is 2/3.
Achyut said:
1 decade ago
Let x part of whisky removed.
Whisky removed = 40x/100.
Whisky added = 19x/100.
Total change in whisky 40/100 - 40x/100 + 19x/100.
After Equating,
40/100 - 40x/100 + 19x/100 = 26/100.
Or, x = 2/3.
Whisky removed = 40x/100.
Whisky added = 19x/100.
Total change in whisky 40/100 - 40x/100 + 19x/100.
After Equating,
40/100 - 40x/100 + 19x/100 = 26/100.
Or, x = 2/3.
Kush said:
1 decade ago
What is wrong in this approach?
Let us assume that there is x L of whiskey and we are replacing y L of whiskey.
Therefore the quantity of alcohol is:
(40/100)x-(40/100)y+(19/100)y = (26/100)(x-y).
Let us assume that there is x L of whiskey and we are replacing y L of whiskey.
Therefore the quantity of alcohol is:
(40/100)x-(40/100)y+(19/100)y = (26/100)(x-y).
(1)
Jamshaid said:
3 years ago
Wrong, the correct answer is;
19% whisky replaced be X portion of 1 jar, then 40% whisky is 1-X portion, and then mixture is 26%;
19/100 * X + 40/100 * (1-X) = 26/100 *1.
X = 7/13 of Jar.
19% whisky replaced be X portion of 1 jar, then 40% whisky is 1-X portion, and then mixture is 26%;
19/100 * X + 40/100 * (1-X) = 26/100 *1.
X = 7/13 of Jar.
(1)
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