Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 4)
4.
A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?
Answer: Option
Explanation:
Let the cost of 1 litre milk be Re. 1
| Milk in 1 litre mix. in 1st can = | 3 | litre, C.P. of 1 litre mix. in 1st can Re. | 3 |
| 4 | 4 |
| Milk in 1 litre mix. in 2nd can = | 1 | litre, C.P. of 1 litre mix. in 2nd can Re. | 1 |
| 2 | 2 |
| Milk in 1 litre of final mix. = | 5 | litre, Mean price = Re. | 5 |
| 8 | 8 |
By the rule of alligation, we have:
| C.P. of 1 litre mixture in 1st can C.P. of 1 litre mixture in 2nd can | ||||||||
|
Mean Price
|
|
||||||
|
|
|||||||
 Ratio of two mixtures = |
1 | : | 1 | = 1 : 1. |
| 8 | 8 |
| So, quantity of mixture taken from each can = |  |
1 | x 12 |  |
= 6 litres. |
| 2 |
Discussion:
74 comments Page 6 of 8.
Amit Ambadkar said:
6 years ago
Let's see 2 methods to solve the problem.
Let 1st can contain x lit of mixture(means 0.25x lit water and 0.75x lit milk).
2nd can contain y lit of mixture(means 0.5y lit milk and 0.5y lit water).
After mixing both the ratio of water to milk is 3:5.
So,
(0.25x+0.5y):(0.75x+0.5y) = 3:5.
After solving x:y=1:1,
And we have x+y=12,
So x=y=6.
Let 1st can contain x lit of mixture(means 0.25x lit water and 0.75x lit milk).
2nd can contain y lit of mixture(means 0.5y lit milk and 0.5y lit water).
After mixing both the ratio of water to milk is 3:5.
So,
(0.25x+0.5y):(0.75x+0.5y) = 3:5.
After solving x:y=1:1,
And we have x+y=12,
So x=y=6.
Amin said:
6 years ago
Why we take 12 litres of milk as x+y=12?
Prakhar said:
6 years ago
Best explanation, thanks @Ajay.
Dinesh said:
6 years ago
How will you find the quantity of mixture?
Sabbir said:
5 years ago
You can solve the math in this way as well,
In can1 there is 25% (1/4) water and 75% (3/4) milk.
Again, in can2 there is 50% (1/2) water and 50% (1/2) milk.
So, total volume of water = 1/4+1/2 = 3/4.
Total volume of milk = 3/4+1/2 = 5/4.
Now, as per the question, the ratio of water and milk must be 3x and 5x.
So, we can write, 3/4:5/4 = 3x:5x.
Or, 3/4* 5x = 5/4 * 3x.
Or, 15x/4 = 15x/4.
That's to say the volume of water and milk must be the same. Hence the answer will be 6 liters.
In can1 there is 25% (1/4) water and 75% (3/4) milk.
Again, in can2 there is 50% (1/2) water and 50% (1/2) milk.
So, total volume of water = 1/4+1/2 = 3/4.
Total volume of milk = 3/4+1/2 = 5/4.
Now, as per the question, the ratio of water and milk must be 3x and 5x.
So, we can write, 3/4:5/4 = 3x:5x.
Or, 3/4* 5x = 5/4 * 3x.
Or, 15x/4 = 15x/4.
That's to say the volume of water and milk must be the same. Hence the answer will be 6 liters.
(3)
Andy said:
5 years ago
Three parts milk and 1 part water in one container and 1 part milk and 1 part water in the second container.
Representing the milk 3x/4+1x/2 = 7.5(5/8*12) Solving x you get 6.
Representing the water 1x/4+1x/2 = 4.5(3/8*12) Solving x you get 6.
Representing the milk 3x/4+1x/2 = 7.5(5/8*12) Solving x you get 6.
Representing the water 1x/4+1x/2 = 4.5(3/8*12) Solving x you get 6.
Surya said:
5 years ago
Can anyone tell how we are multiplying 1/2 with 12?
Harshada said:
5 years ago
Well explained @Kunal.
Muslih said:
5 years ago
As per allegation, we obtained that same quantity are taken from each Can.
So (.75)*x+(.5)*x=12 milk in the new mix, where x-> quantity mixer taken from can1 and can2(1:1).
X=12*4/5.
MILK FROM CAN 1 is = (.75) * 12 * 4/5 = 36/5 = 7.2..
Milk from can 2 is =.(.5) * 12 * 4/5 = 24/5 = 4.8.
Hence answer for the quantity of milk collected from each CAN to get the 12lit of milk is 7.2 and 4.8 respectively.
Am I right?
So (.75)*x+(.5)*x=12 milk in the new mix, where x-> quantity mixer taken from can1 and can2(1:1).
X=12*4/5.
MILK FROM CAN 1 is = (.75) * 12 * 4/5 = 36/5 = 7.2..
Milk from can 2 is =.(.5) * 12 * 4/5 = 24/5 = 4.8.
Hence answer for the quantity of milk collected from each CAN to get the 12lit of milk is 7.2 and 4.8 respectively.
Am I right?
Sasi said:
5 years ago
x -> quantity from A.
y -> quantity grom B.
x + y = 12;
0.25x + 0.5y = (3/8)*12.
Solving for x and y we get an answer.
y -> quantity grom B.
x + y = 12;
0.25x + 0.5y = (3/8)*12.
Solving for x and y we get an answer.
(1)
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