Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 4)
4.
A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?
Answer: Option
Explanation:
Let the cost of 1 litre milk be Re. 1
Milk in 1 litre mix. in 1st can = | 3 | litre, C.P. of 1 litre mix. in 1st can Re. | 3 |
4 | 4 |
Milk in 1 litre mix. in 2nd can = | 1 | litre, C.P. of 1 litre mix. in 2nd can Re. | 1 |
2 | 2 |
Milk in 1 litre of final mix. = | 5 | litre, Mean price = Re. | 5 |
8 | 8 |
By the rule of alligation, we have:
C.P. of 1 litre mixture in 1st can C.P. of 1 litre mixture in 2nd can | ||||||||
|
Mean Price
|
|
||||||
|
|
![]() |
1 | : | 1 | = 1 : 1. |
8 | 8 |
So, quantity of mixture taken from each can = | ![]() |
1 | x 12 | ![]() |
= 6 litres. |
2 |
Discussion:
74 comments Page 5 of 8.
ANIL KUMAR JAT said:
1 decade ago
With the help of option
M W
6 3 : 1
6 1 : 1
M=3+4.5=7.5
W=3+1.5=4.5
THERFORE W:M=4.5:7.5=3:5 IS GIVEN SO ANSWER 6,6 IS CORRECT.
M W
6 3 : 1
6 1 : 1
M=3+4.5=7.5
W=3+1.5=4.5
THERFORE W:M=4.5:7.5=3:5 IS GIVEN SO ANSWER 6,6 IS CORRECT.
Jamshaid said:
3 years ago
Yes, right @Muslih.
Water by mixing 2 solutions:
1/3 * X + 1/1 * (12-X) = 3/5 * 12,
X = 7.2 L,
12-X = 4.8 L, so D is the right option.
Water by mixing 2 solutions:
1/3 * X + 1/1 * (12-X) = 3/5 * 12,
X = 7.2 L,
12-X = 4.8 L, so D is the right option.
(4)
Parvy Govil said:
10 years ago
Let x litres of A and y litres of B is extracted x+y = 12.
Milk quantity = 1/5x+1/2y = 3/5(4/5x+1/2 y).
x = 5 litres.
y = 7 litres.
Milk quantity = 1/5x+1/2y = 3/5(4/5x+1/2 y).
x = 5 litres.
y = 7 litres.
Sridharsan said:
8 years ago
Actually, we need 12 ltrs of milk, here where is 12 ltr of milk, 6+6=12 (it is a mix, not purely milk).
Please explain in detail.
Please explain in detail.
Dhananjay said:
9 years ago
Can somebody help me do the same sum with ratios 2:1, 1:3 and final needed ratio 1:1 the ratios being milk:water in the mixture.
Sasi said:
5 years ago
x -> quantity from A.
y -> quantity grom B.
x + y = 12;
0.25x + 0.5y = (3/8)*12.
Solving for x and y we get an answer.
y -> quantity grom B.
x + y = 12;
0.25x + 0.5y = (3/8)*12.
Solving for x and y we get an answer.
(1)
Kailash chandra said:
1 decade ago
Let,
25+50=75 (water).
75+50=125(milk).
75/125=3/5.
3/5=3/5.
Obviously mix ratio 1:1.
So, 12 lit=6 and 6.
25+50=75 (water).
75+50=125(milk).
75/125=3/5.
3/5=3/5.
Obviously mix ratio 1:1.
So, 12 lit=6 and 6.
(1)
Kabir said:
8 years ago
12 liter milk or mix. I am confused. Is this question in right mood. Please anyone explain the question.
Dinesh said:
9 years ago
I think the questions is wrong because 12 is not only milk mixture, 12 is a total mixed mixture.
Sri Divya said:
1 decade ago
Hi friends, Please explain how 5/8 became the mean price?
How to calculate mean price?
How to calculate mean price?
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