Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 4)
4.
A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?
Answer: Option
Explanation:
Let the cost of 1 litre milk be Re. 1
| Milk in 1 litre mix. in 1st can = | 3 | litre, C.P. of 1 litre mix. in 1st can Re. | 3 |
| 4 | 4 |
| Milk in 1 litre mix. in 2nd can = | 1 | litre, C.P. of 1 litre mix. in 2nd can Re. | 1 |
| 2 | 2 |
| Milk in 1 litre of final mix. = | 5 | litre, Mean price = Re. | 5 |
| 8 | 8 |
By the rule of alligation, we have:
| C.P. of 1 litre mixture in 1st can C.P. of 1 litre mixture in 2nd can | ||||||||
|
Mean Price
|
|
||||||
|
|
|||||||
 Ratio of two mixtures = |
1 | : | 1 | = 1 : 1. |
| 8 | 8 |
| So, quantity of mixture taken from each can = |  |
1 | x 12 |  |
= 6 litres. |
| 2 |
Discussion:
76 comments Page 4 of 8.
Prakhar said:
6 years ago
Best explanation, thanks @Ajay.
Dinesh said:
6 years ago
How will you find the quantity of mixture?
Andy said:
6 years ago
Three parts milk and 1 part water in one container and 1 part milk and 1 part water in the second container.
Representing the milk 3x/4+1x/2 = 7.5(5/8*12) Solving x you get 6.
Representing the water 1x/4+1x/2 = 4.5(3/8*12) Solving x you get 6.
Representing the milk 3x/4+1x/2 = 7.5(5/8*12) Solving x you get 6.
Representing the water 1x/4+1x/2 = 4.5(3/8*12) Solving x you get 6.
Surya said:
5 years ago
Can anyone tell how we are multiplying 1/2 with 12?
Harshada said:
5 years ago
Well explained @Kunal.
Muslih said:
5 years ago
As per allegation, we obtained that same quantity are taken from each Can.
So (.75)*x+(.5)*x=12 milk in the new mix, where x-> quantity mixer taken from can1 and can2(1:1).
X=12*4/5.
MILK FROM CAN 1 is = (.75) * 12 * 4/5 = 36/5 = 7.2..
Milk from can 2 is =.(.5) * 12 * 4/5 = 24/5 = 4.8.
Hence answer for the quantity of milk collected from each CAN to get the 12lit of milk is 7.2 and 4.8 respectively.
Am I right?
So (.75)*x+(.5)*x=12 milk in the new mix, where x-> quantity mixer taken from can1 and can2(1:1).
X=12*4/5.
MILK FROM CAN 1 is = (.75) * 12 * 4/5 = 36/5 = 7.2..
Milk from can 2 is =.(.5) * 12 * 4/5 = 24/5 = 4.8.
Hence answer for the quantity of milk collected from each CAN to get the 12lit of milk is 7.2 and 4.8 respectively.
Am I right?
Shivam said:
4 years ago
@Hardik.
Nice explanation!
Nice explanation!
XiYo said:
4 years ago
Nice Explaination @Hardick!
Sylvester OgboluOtutu said:
1 month ago
Representations:
Let W = Water & M = Milk
From Container 1
25% water = 0.25W
75% milk = 0.75M
From Container 2
50% water = 0.5W.
50% milk = 0.5M.
Water to Milk in the ratio of 3:5 is 4.5 litres of water (3/8 × 12 litres = 4.5W) to 7.5 litres of milk (5/8 × 12 litres = 7.5M).
The linear equation to solve is:
0.25W + 0.75M + 0.5W + 0.5M = 4.5 litres + 7.5 litres.
0.75W + 1.25M = 4.5 litres water + 7.5 litres milk.
0.75W = 4.5 litres.
W = 4.5 ÷ 0.75,
W = 450 ÷ 75,
W = 6 litres.
10.25M = 7.5 litres.
M = 7.5 ÷ 1.25.
M = 750 ÷ 125.
M = 6 litres.
Accordingly, 6 litres from each container must be added to obtain a mixture that is 50 percent water and 50 percent milk.
Let W = Water & M = Milk
From Container 1
25% water = 0.25W
75% milk = 0.75M
From Container 2
50% water = 0.5W.
50% milk = 0.5M.
Water to Milk in the ratio of 3:5 is 4.5 litres of water (3/8 × 12 litres = 4.5W) to 7.5 litres of milk (5/8 × 12 litres = 7.5M).
The linear equation to solve is:
0.25W + 0.75M + 0.5W + 0.5M = 4.5 litres + 7.5 litres.
0.75W + 1.25M = 4.5 litres water + 7.5 litres milk.
0.75W = 4.5 litres.
W = 4.5 ÷ 0.75,
W = 450 ÷ 75,
W = 6 litres.
10.25M = 7.5 litres.
M = 7.5 ÷ 1.25.
M = 750 ÷ 125.
M = 6 litres.
Accordingly, 6 litres from each container must be added to obtain a mixture that is 50 percent water and 50 percent milk.
Jeeva said:
1 week ago
1st one milk 75%. Second one milk 50%. At last, the final one milk is (if the total 8 parts means 100% milk should be ( (100/8) *5).
So (125/2) %.
So (75%- (125/2%) : (125/2) %-50%= 1:1.
Two cans of milk are 12 litres. So each can add 6 ltrs.
So (125/2) %.
So (75%- (125/2%) : (125/2) %-50%= 1:1.
Two cans of milk are 12 litres. So each can add 6 ltrs.
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