Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 4)
4.
A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?
Answer: Option
Explanation:
Let the cost of 1 litre milk be Re. 1
Milk in 1 litre mix. in 1st can = | 3 | litre, C.P. of 1 litre mix. in 1st can Re. | 3 |
4 | 4 |
Milk in 1 litre mix. in 2nd can = | 1 | litre, C.P. of 1 litre mix. in 2nd can Re. | 1 |
2 | 2 |
Milk in 1 litre of final mix. = | 5 | litre, Mean price = Re. | 5 |
8 | 8 |
By the rule of alligation, we have:
C.P. of 1 litre mixture in 1st can C.P. of 1 litre mixture in 2nd can | ||||||||
|
Mean Price
|
|
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|
|
![]() |
1 | : | 1 | = 1 : 1. |
8 | 8 |
So, quantity of mixture taken from each can = | ![]() |
1 | x 12 | ![]() |
= 6 litres. |
2 |
Discussion:
74 comments Page 4 of 8.
Adithi said:
9 years ago
In the first can water and milk ratio is 1 : 3 and in the second it is 1 : 1.
Mixture is 3 : 5 now sub 1/4 and 3/8 (water) it is 1/8. Next 1/2-3/8 it is 1/8 (milk). So the water and milk ratio is 1 : 1. Hence in total of 12 litres 6 litres milk and 6 litres water.
Mixture is 3 : 5 now sub 1/4 and 3/8 (water) it is 1/8. Next 1/2-3/8 it is 1/8 (milk). So the water and milk ratio is 1 : 1. Hence in total of 12 litres 6 litres milk and 6 litres water.
Dhananjay said:
9 years ago
Can somebody help me do the same sum with ratios 2:1, 1:3 and final needed ratio 1:1 the ratios being milk:water in the mixture.
Pranjal Patel said:
9 years ago
It's really easy but I can do it in an easier way by another method.
Naveen said:
9 years ago
I'm confusing, please clearly explain the solution.
Cipher Gopal said:
9 years ago
@Amisha, can you explain how we get 5/8?
Anil said:
9 years ago
See, first of all understand that the resultant mixture contain water and milk in ratio 3 : 5.
So, water concentration is 3/8 = P (resultant one).
Now we have first mixture (can) water concentration 1/4 = P1.
Similarly second mixture (can) water concentration 1/2 = P2.
Q1/Q2 = (P2 - P)/(P - P1).
Will give the answer as 1 : 1.
So, the answer is B.
So, water concentration is 3/8 = P (resultant one).
Now we have first mixture (can) water concentration 1/4 = P1.
Similarly second mixture (can) water concentration 1/2 = P2.
Q1/Q2 = (P2 - P)/(P - P1).
Will give the answer as 1 : 1.
So, the answer is B.
Sabarinath S said:
9 years ago
Easy method: Take from options
1. Eliminate all answer whose sum is not 12L (here all r 12).
2. 3x/5x new ratio , take option A gives 3 * 4/5 * 8 not equal to 3 : 5.
So, b) 3 * 6/5 * 6 is 3 : 5.
1. Eliminate all answer whose sum is not 12L (here all r 12).
2. 3x/5x new ratio , take option A gives 3 * 4/5 * 8 not equal to 3 : 5.
So, b) 3 * 6/5 * 6 is 3 : 5.
Yuhi said:
9 years ago
The ratio given is 3 : 5 water to milk means 5 parts of milk and 3 parts of water in total 8 parts (3 + 5). So mean here is 5/8 because we need to find out the milk percent.
Dinesh said:
9 years ago
I think the questions is wrong because 12 is not only milk mixture, 12 is a total mixed mixture.
Saurabh said:
9 years ago
Can anyone explain me how "Milk in 1 litre mix in 1st can =3/4 litre come?
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