Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 4)
4.
A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?
Answer: Option
Explanation:
Let the cost of 1 litre milk be Re. 1
| Milk in 1 litre mix. in 1st can = | 3 | litre, C.P. of 1 litre mix. in 1st can Re. | 3 |
| 4 | 4 |
| Milk in 1 litre mix. in 2nd can = | 1 | litre, C.P. of 1 litre mix. in 2nd can Re. | 1 |
| 2 | 2 |
| Milk in 1 litre of final mix. = | 5 | litre, Mean price = Re. | 5 |
| 8 | 8 |
By the rule of alligation, we have:
| C.P. of 1 litre mixture in 1st can C.P. of 1 litre mixture in 2nd can | ||||||||
|
Mean Price
|
|
||||||
|
|
|||||||
 Ratio of two mixtures = |
1 | : | 1 | = 1 : 1. |
| 8 | 8 |
| So, quantity of mixture taken from each can = |  |
1 | x 12 |  |
= 6 litres. |
| 2 |
Discussion:
74 comments Page 2 of 8.
Abhishek Hajong said:
1 year ago
Assume, can 1 and can 2 have the same volume.
Now can 1 have a water & milk ratio= 1 : 4.
Can2 have a water & milk ratio = 1 : 1.
And New mix is 12L then the water-milk ratio=3 : 5
Now put all the Options in Trial and error:
You will see option C is 5,7
By validating option C;
(5x1/5 + 7X1/2) Water/ (5x4/5+7x1/2)milk.
= 9/15.
= 3:5.
So, Option C would be the right answer.
Now can 1 have a water & milk ratio= 1 : 4.
Can2 have a water & milk ratio = 1 : 1.
And New mix is 12L then the water-milk ratio=3 : 5
Now put all the Options in Trial and error:
You will see option C is 5,7
By validating option C;
(5x1/5 + 7X1/2) Water/ (5x4/5+7x1/2)milk.
= 9/15.
= 3:5.
So, Option C would be the right answer.
(2)
Hardik said:
4 years ago
The initial ratio of water to milk in can 1 is 1:3.
Initial ratio of water to milk in can 2 is 1:1.
If we add both then we get the ratio of water to milk 2:4.
It is said that this ratio becomes 3:5.
So from 2:4, it becomes 3:5.
As we can see there is an equal amount of change 3-2 = 1 and 5-4 = 1.
Therefore the quantity also should be in the ratio of 1:1.
Hence the answer is 6:6.
Initial ratio of water to milk in can 2 is 1:1.
If we add both then we get the ratio of water to milk 2:4.
It is said that this ratio becomes 3:5.
So from 2:4, it becomes 3:5.
As we can see there is an equal amount of change 3-2 = 1 and 5-4 = 1.
Therefore the quantity also should be in the ratio of 1:1.
Hence the answer is 6:6.
(71)
B.M. Nasim Reza Anik said:
4 years ago
If 1 litre is drawn from the 1st container, we get 0. 25L water and 0. 75L milk and if 1 litre is drawn from the 2nd container, we get 0.5L water and 0.5L milk.
By combining 1L from each of the two containers, we get 0. 75L water and 1.25L milk. In which water to milk is in the ratio of 3:5.
Thus we need 2+2+2+2+2+2 to get 12L in total and 6L from each of the containers.
By combining 1L from each of the two containers, we get 0. 75L water and 1.25L milk. In which water to milk is in the ratio of 3:5.
Thus we need 2+2+2+2+2+2 to get 12L in total and 6L from each of the containers.
(3)
Dhruv Sahni said:
1 decade ago
Container A has 25% water, Container B has 50% of water and after mixing these two final mixture has 3/8 -> 37.5% of water.
So by allegation method the ratio of A and B in final mixture will be 25% 50% 37.5%.
50%-37.5% : 37.5%-25%.
= 12.5% = 12.5% = 1:1.
So Ratio of A:B in final mixture is 1:1, hence in 12 liter of mixture there will be 6L of A and 6L of B.
So by allegation method the ratio of A and B in final mixture will be 25% 50% 37.5%.
50%-37.5% : 37.5%-25%.
= 12.5% = 12.5% = 1:1.
So Ratio of A:B in final mixture is 1:1, hence in 12 liter of mixture there will be 6L of A and 6L of B.
Vikram Ojha said:
1 decade ago
1st can Water:milk = 1:3.
In 2nd can water:milk = 1:1.
In 12 liters = water:milk = 3:5.
So in 12 liters we have 3(12)/8 = 4.5 liter of water.
Lets us consider we have x liters of water in new mix.
So our equation will be,
1(x)/4 + 1(x)/2 = 4.5.
x = 6 liters.
So amount of water in new mixture = 6 liters.
And that of milk will be = 12-x = 6 liters.
In 2nd can water:milk = 1:1.
In 12 liters = water:milk = 3:5.
So in 12 liters we have 3(12)/8 = 4.5 liter of water.
Lets us consider we have x liters of water in new mix.
So our equation will be,
1(x)/4 + 1(x)/2 = 4.5.
x = 6 liters.
So amount of water in new mixture = 6 liters.
And that of milk will be = 12-x = 6 liters.
Nagendramurthy said:
1 decade ago
Friends see can also solve the problem..
initially water and milk in first can are in 1/4 and 3/4
in the second can 1/2 and 1/2
therefore total (1/4)+(1/2) of water and (3/4)+(1/2)
i.e (3/4) of water and (5/4) of milk
If we compare it already in the ratio of 3:5
So we have add equal amount of water and milk in order to maintain the ratio same..
initially water and milk in first can are in 1/4 and 3/4
in the second can 1/2 and 1/2
therefore total (1/4)+(1/2) of water and (3/4)+(1/2)
i.e (3/4) of water and (5/4) of milk
If we compare it already in the ratio of 3:5
So we have add equal amount of water and milk in order to maintain the ratio same..
Anil said:
9 years ago
See, first of all understand that the resultant mixture contain water and milk in ratio 3 : 5.
So, water concentration is 3/8 = P (resultant one).
Now we have first mixture (can) water concentration 1/4 = P1.
Similarly second mixture (can) water concentration 1/2 = P2.
Q1/Q2 = (P2 - P)/(P - P1).
Will give the answer as 1 : 1.
So, the answer is B.
So, water concentration is 3/8 = P (resultant one).
Now we have first mixture (can) water concentration 1/4 = P1.
Similarly second mixture (can) water concentration 1/2 = P2.
Q1/Q2 = (P2 - P)/(P - P1).
Will give the answer as 1 : 1.
So, the answer is B.
Amit Ambadkar said:
6 years ago
Let's see 2 methods to solve the problem.
Let 1st can contain x lit of mixture(means 0.25x lit water and 0.75x lit milk).
2nd can contain y lit of mixture(means 0.5y lit milk and 0.5y lit water).
After mixing both the ratio of water to milk is 3:5.
So,
(0.25x+0.5y):(0.75x+0.5y) = 3:5.
After solving x:y=1:1,
And we have x+y=12,
So x=y=6.
Let 1st can contain x lit of mixture(means 0.25x lit water and 0.75x lit milk).
2nd can contain y lit of mixture(means 0.5y lit milk and 0.5y lit water).
After mixing both the ratio of water to milk is 3:5.
So,
(0.25x+0.5y):(0.75x+0.5y) = 3:5.
After solving x:y=1:1,
And we have x+y=12,
So x=y=6.
Shashi bhushan said:
10 years ago
Let x and y liters from the can to be mixed to make 12 liters of milk.
Can 1 has x/4 (water) and 3x/4 (milk).
Can 2 has y/2 (water) and y/2 (milk).
So new ratio of water to milk is.
(x/3+y/2)/(3x/4+y/2) = 3/5.....(1).
By the question.
x+y = 12.....(2).
To solve these equation.
x = 6, y = 6.
Can 1 has x/4 (water) and 3x/4 (milk).
Can 2 has y/2 (water) and y/2 (milk).
So new ratio of water to milk is.
(x/3+y/2)/(3x/4+y/2) = 3/5.....(1).
By the question.
x+y = 12.....(2).
To solve these equation.
x = 6, y = 6.
ANAND PATEL said:
1 decade ago
From the first can mixture is X liter.
From the first can mixture is Y liter.
NOW X + Y = 12.
IN 12 LITER portion of water is 4.5 and milk IS 7.5 LITER.
X( (1/4)+ (1/2))+ Y ((3/4)+(1/2))= 4.5 + 7.5.
SO X( (1/4)+ (1/2))= 4.5 => X= 6 LITER.
Y ((3/4)+(1/2)) = 7.5 +> Y = 6 LITER.
From the first can mixture is Y liter.
NOW X + Y = 12.
IN 12 LITER portion of water is 4.5 and milk IS 7.5 LITER.
X( (1/4)+ (1/2))+ Y ((3/4)+(1/2))= 4.5 + 7.5.
SO X( (1/4)+ (1/2))= 4.5 => X= 6 LITER.
Y ((3/4)+(1/2)) = 7.5 +> Y = 6 LITER.
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