Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 4)
4.
A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?
Answer: Option
Explanation:
Let the cost of 1 litre milk be Re. 1
| Milk in 1 litre mix. in 1st can = | 3 | litre, C.P. of 1 litre mix. in 1st can Re. | 3 |
| 4 | 4 |
| Milk in 1 litre mix. in 2nd can = | 1 | litre, C.P. of 1 litre mix. in 2nd can Re. | 1 |
| 2 | 2 |
| Milk in 1 litre of final mix. = | 5 | litre, Mean price = Re. | 5 |
| 8 | 8 |
By the rule of alligation, we have:
| C.P. of 1 litre mixture in 1st can C.P. of 1 litre mixture in 2nd can | ||||||||
|
Mean Price
|
|
||||||
|
|
|||||||
 Ratio of two mixtures = |
1 | : | 1 | = 1 : 1. |
| 8 | 8 |
| So, quantity of mixture taken from each can = |  |
1 | x 12 |  |
= 6 litres. |
| 2 |
Discussion:
74 comments Page 2 of 8.
Shrti said:
4 years ago
I can't understand please explain in simplest way.
(3)
Guru Prasad said:
6 years ago
Alternate method:
-
CAN:1---> 25% water and the remaining 75% milk.
CAN:2---> 50% water and 50% milk.
Given ratio is 3:5. since only the quantity of milk is to be estimated therefore there is 5/8 of milk present in the mixture. converting this into percentage it is 62.50%.
By using allegation:-
{75% = M & 50% = N and D = 62.50%}--------> General Assumption.
M - D = 75% - 62.50%
= 12.50%.
D - N = 62.50% - 50%,
= 12.50%.
(M - D) : (D - N) = 1 : 1.
Therefore the quantity of milk to be mixed from each of the containers in order to 12 litres of milk is;
(1/2) * 12
= 6 litres. since the obtained ratio is 1:1 therefore from container-1 it is 6 litres and from container-2 it is also 6 litres.
-
CAN:1---> 25% water and the remaining 75% milk.
CAN:2---> 50% water and 50% milk.
Given ratio is 3:5. since only the quantity of milk is to be estimated therefore there is 5/8 of milk present in the mixture. converting this into percentage it is 62.50%.
By using allegation:-
{75% = M & 50% = N and D = 62.50%}--------> General Assumption.
M - D = 75% - 62.50%
= 12.50%.
D - N = 62.50% - 50%,
= 12.50%.
(M - D) : (D - N) = 1 : 1.
Therefore the quantity of milk to be mixed from each of the containers in order to 12 litres of milk is;
(1/2) * 12
= 6 litres. since the obtained ratio is 1:1 therefore from container-1 it is 6 litres and from container-2 it is also 6 litres.
(2)
Kalai said:
2 years ago
@Hardik.
Thanks for explaining the answer.
Thanks for explaining the answer.
(2)
Abhishek Hajong said:
1 year ago
Assume, can 1 and can 2 have the same volume.
Now can 1 have a water & milk ratio= 1 : 4.
Can2 have a water & milk ratio = 1 : 1.
And New mix is 12L then the water-milk ratio=3 : 5
Now put all the Options in Trial and error:
You will see option C is 5,7
By validating option C;
(5x1/5 + 7X1/2) Water/ (5x4/5+7x1/2)milk.
= 9/15.
= 3:5.
So, Option C would be the right answer.
Now can 1 have a water & milk ratio= 1 : 4.
Can2 have a water & milk ratio = 1 : 1.
And New mix is 12L then the water-milk ratio=3 : 5
Now put all the Options in Trial and error:
You will see option C is 5,7
By validating option C;
(5x1/5 + 7X1/2) Water/ (5x4/5+7x1/2)milk.
= 9/15.
= 3:5.
So, Option C would be the right answer.
(2)
Vivek kumar said:
1 decade ago
If we take mixture of both the can be x.
Than (x/4+x/2)/(3x/4 + x/2) = 3x/5x = 3/5.
The ratio comes 3/5 only if we have equal amount of milk(x here). So, according to question,
x+x=12;
2x=12.
x = 6.
12-6 = 6.
So, Answer is 6, 6.
Than (x/4+x/2)/(3x/4 + x/2) = 3x/5x = 3/5.
The ratio comes 3/5 only if we have equal amount of milk(x here). So, according to question,
x+x=12;
2x=12.
x = 6.
12-6 = 6.
So, Answer is 6, 6.
(1)
Kailash chandra said:
1 decade ago
Let,
25+50=75 (water).
75+50=125(milk).
75/125=3/5.
3/5=3/5.
Obviously mix ratio 1:1.
So, 12 lit=6 and 6.
25+50=75 (water).
75+50=125(milk).
75/125=3/5.
3/5=3/5.
Obviously mix ratio 1:1.
So, 12 lit=6 and 6.
(1)
Ajay said:
1 decade ago
Cont 1 has 25% water and 75% milk.
Cont 2 has 50% water and 50% milk.
We take x lit mixture from cont 1.
25x/100 lit water and 75x/100 lit milk.
And take y lit mixture from cont 2.
50y/100 lit water and 50y/100 lit milk.
Ratio of water to milk = 25x+50y/75x+50y = 3/5.
From here x = y.
And total milk = 12 lit.
25x/100+75x/100+50y/100+50y/100 = 12 lit.
Put x = y.
Get answer as x = 6 and y = 6 lit.
And enjoy your day!
Cont 2 has 50% water and 50% milk.
We take x lit mixture from cont 1.
25x/100 lit water and 75x/100 lit milk.
And take y lit mixture from cont 2.
50y/100 lit water and 50y/100 lit milk.
Ratio of water to milk = 25x+50y/75x+50y = 3/5.
From here x = y.
And total milk = 12 lit.
25x/100+75x/100+50y/100+50y/100 = 12 lit.
Put x = y.
Get answer as x = 6 and y = 6 lit.
And enjoy your day!
(1)
Sasi said:
5 years ago
x -> quantity from A.
y -> quantity grom B.
x + y = 12;
0.25x + 0.5y = (3/8)*12.
Solving for x and y we get an answer.
y -> quantity grom B.
x + y = 12;
0.25x + 0.5y = (3/8)*12.
Solving for x and y we get an answer.
(1)
Pradeep said:
9 years ago
Thanks a lot @Kailash Chandra.
(1)
Saurabh said:
9 years ago
Can anyone explain me how "Milk in 1 litre mix in 1st can =3/4 litre come?
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