Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 4)
4.
A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?
Answer: Option
Explanation:
Let the cost of 1 litre milk be Re. 1
| Milk in 1 litre mix. in 1st can = | 3 | litre, C.P. of 1 litre mix. in 1st can Re. | 3 |
| 4 | 4 |
| Milk in 1 litre mix. in 2nd can = | 1 | litre, C.P. of 1 litre mix. in 2nd can Re. | 1 |
| 2 | 2 |
| Milk in 1 litre of final mix. = | 5 | litre, Mean price = Re. | 5 |
| 8 | 8 |
By the rule of alligation, we have:
| C.P. of 1 litre mixture in 1st can C.P. of 1 litre mixture in 2nd can | ||||||||
|
Mean Price
|
|
||||||
|
|
|||||||
 Ratio of two mixtures = |
1 | : | 1 | = 1 : 1. |
| 8 | 8 |
| So, quantity of mixture taken from each can = |  |
1 | x 12 |  |
= 6 litres. |
| 2 |
Discussion:
74 comments Page 2 of 8.
Kailash chandra said:
1 decade ago
Let,
25+50=75 (water).
75+50=125(milk).
75/125=3/5.
3/5=3/5.
Obviously mix ratio 1:1.
So, 12 lit=6 and 6.
25+50=75 (water).
75+50=125(milk).
75/125=3/5.
3/5=3/5.
Obviously mix ratio 1:1.
So, 12 lit=6 and 6.
(1)
Vikram Ojha said:
1 decade ago
1st can Water:milk = 1:3.
In 2nd can water:milk = 1:1.
In 12 liters = water:milk = 3:5.
So in 12 liters we have 3(12)/8 = 4.5 liter of water.
Lets us consider we have x liters of water in new mix.
So our equation will be,
1(x)/4 + 1(x)/2 = 4.5.
x = 6 liters.
So amount of water in new mixture = 6 liters.
And that of milk will be = 12-x = 6 liters.
In 2nd can water:milk = 1:1.
In 12 liters = water:milk = 3:5.
So in 12 liters we have 3(12)/8 = 4.5 liter of water.
Lets us consider we have x liters of water in new mix.
So our equation will be,
1(x)/4 + 1(x)/2 = 4.5.
x = 6 liters.
So amount of water in new mixture = 6 liters.
And that of milk will be = 12-x = 6 liters.
Vivek kumar said:
1 decade ago
If we take mixture of both the can be x.
Than (x/4+x/2)/(3x/4 + x/2) = 3x/5x = 3/5.
The ratio comes 3/5 only if we have equal amount of milk(x here). So, according to question,
x+x=12;
2x=12.
x = 6.
12-6 = 6.
So, Answer is 6, 6.
Than (x/4+x/2)/(3x/4 + x/2) = 3x/5x = 3/5.
The ratio comes 3/5 only if we have equal amount of milk(x here). So, according to question,
x+x=12;
2x=12.
x = 6.
12-6 = 6.
So, Answer is 6, 6.
(1)
Meeran said:
1 decade ago
Water : Milk
Can 1 1 : 3
Can 2 1 : 1
Required ratio = 3 : 4.
Therefore ratio of can1+ can2+ added quantity = required quantity.
1+1+1 : 3+1+1 is the only possible way, ratio added must b,
1 : 1.
Hence, option B, 6 : 6 is only possible which can give 1 : 1 ratio.
Can 1 1 : 3
Can 2 1 : 1
Required ratio = 3 : 4.
Therefore ratio of can1+ can2+ added quantity = required quantity.
1+1+1 : 3+1+1 is the only possible way, ratio added must b,
1 : 1.
Hence, option B, 6 : 6 is only possible which can give 1 : 1 ratio.
ANAND PATEL said:
1 decade ago
From the first can mixture is X liter.
From the first can mixture is Y liter.
NOW X + Y = 12.
IN 12 LITER portion of water is 4.5 and milk IS 7.5 LITER.
X( (1/4)+ (1/2))+ Y ((3/4)+(1/2))= 4.5 + 7.5.
SO X( (1/4)+ (1/2))= 4.5 => X= 6 LITER.
Y ((3/4)+(1/2)) = 7.5 +> Y = 6 LITER.
From the first can mixture is Y liter.
NOW X + Y = 12.
IN 12 LITER portion of water is 4.5 and milk IS 7.5 LITER.
X( (1/4)+ (1/2))+ Y ((3/4)+(1/2))= 4.5 + 7.5.
SO X( (1/4)+ (1/2))= 4.5 => X= 6 LITER.
Y ((3/4)+(1/2)) = 7.5 +> Y = 6 LITER.
Vaishnavi said:
1 decade ago
Please explain me in a simple way guys?
I can't get the logic?
I can't get the logic?
Ajay said:
1 decade ago
Cont 1 has 25% water and 75% milk.
Cont 2 has 50% water and 50% milk.
We take x lit mixture from cont 1.
25x/100 lit water and 75x/100 lit milk.
And take y lit mixture from cont 2.
50y/100 lit water and 50y/100 lit milk.
Ratio of water to milk = 25x+50y/75x+50y = 3/5.
From here x = y.
And total milk = 12 lit.
25x/100+75x/100+50y/100+50y/100 = 12 lit.
Put x = y.
Get answer as x = 6 and y = 6 lit.
And enjoy your day!
Cont 2 has 50% water and 50% milk.
We take x lit mixture from cont 1.
25x/100 lit water and 75x/100 lit milk.
And take y lit mixture from cont 2.
50y/100 lit water and 50y/100 lit milk.
Ratio of water to milk = 25x+50y/75x+50y = 3/5.
From here x = y.
And total milk = 12 lit.
25x/100+75x/100+50y/100+50y/100 = 12 lit.
Put x = y.
Get answer as x = 6 and y = 6 lit.
And enjoy your day!
(1)
Gokulpriya said:
1 decade ago
How did 5/8 become mean prize what is this value?
Sri Divya said:
1 decade ago
Hi friends, Please explain how 5/8 became the mean price?
How to calculate mean price?
How to calculate mean price?
Sri said:
1 decade ago
Can anybody tell me how 5/8 arrived here?
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