Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 6)
6.
A dishonest milkman professes to sell his milk at cost price but he mixes it with water and thereby gains 25%. The percentage of water in the mixture is:
4%
6
%
%20%
25%
Answer: Option
Explanation:
Let C.P. of 1 litre milk be Re. 1
Then, S.P. of 1 litre of mixture = Re. 1, Gain = 25%.
| C.P. of 1 litre mixture = Re. |  |
100 | x 1 |  |
= | 4 |
| 125 | 5 |
By the rule of alligation, we have:
| C.P. of 1 litre of milk C.P. of 1 litre of water | |||||
| Re. 1 | Mean Price
| 0 | |||
|
|
||||
 Ratio of milk to water = |
4 | : | 1 | = 4 : 1. |
| 5 | 5 |
| Hence, percentage of water in the mixture = | |
1 | x 100 | % |
= 20%. |
| 5 |
Discussion:
65 comments Page 7 of 7.
Sharvam Dave said:
9 years ago
If ingredient worth no value (water) is added to another ingredient of some value(milk), when the mixture (solution) is sold at cost of ingredient with some value and profit earned is 'P' percent, then amount of ingredient with no value(water) added = (P/100) x Amount of Milk.
Ratio of Water to Milk is P:100
If Solution is sold at some other rate than rate of milk, say K% higher or lower rate than milk, than;
Actual rate of solution = Rate of milk x (100+k)/100, when rate is K percent higher than rate of milk; and,
Actual rate of solution = Rate of milk x (100-k)/100, when rate is K percent lower than rate of milk.
Let the actual Rate be S,
Let P = S-100.
Ratio of Milk to Water is, P:100.
Ratio of Water to Milk is P:100
If Solution is sold at some other rate than rate of milk, say K% higher or lower rate than milk, than;
Actual rate of solution = Rate of milk x (100+k)/100, when rate is K percent higher than rate of milk; and,
Actual rate of solution = Rate of milk x (100-k)/100, when rate is K percent lower than rate of milk.
Let the actual Rate be S,
Let P = S-100.
Ratio of Milk to Water is, P:100.
Mamta said:
8 years ago
I will not able to understand that please give me easy example's to understand.
Please, help me.
Please, help me.
Naux said:
8 years ago
Say the vendor buys L liters of milk and the cost of this is X.
Now, the vendor mixes some amount of water so the quantity is becoming say (L+Z) the cost of this is X(original cost)+25/100(X) that would be 5X/4.
Cost---->quantity
X---->L
5X/4--->?
So, ? = 5L/4,
So (L+Z) = 5L/4,
Z =L/4,
So, that would be 25% right but the answer is 20%.
Now, the vendor mixes some amount of water so the quantity is becoming say (L+Z) the cost of this is X(original cost)+25/100(X) that would be 5X/4.
Cost---->quantity
X---->L
5X/4--->?
So, ? = 5L/4,
So (L+Z) = 5L/4,
Z =L/4,
So, that would be 25% right but the answer is 20%.
Reisang Kasar said:
8 years ago
Please someone help me.
How to find out the weight of the water mixed in gm per kilogram of milk?
How to find out the weight of the water mixed in gm per kilogram of milk?
Anamika said:
1 decade ago
Where it is given that C.P. is rupee one?
Would you please explain.
Would you please explain.
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