Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 6)
6.
A dishonest milkman professes to sell his milk at cost price but he mixes it with water and thereby gains 25%. The percentage of water in the mixture is:
4%
6
%
%20%
25%
Answer: Option
Explanation:
Let C.P. of 1 litre milk be Re. 1
Then, S.P. of 1 litre of mixture = Re. 1, Gain = 25%.
| C.P. of 1 litre mixture = Re. |  |
100 | x 1 |  |
= | 4 |
| 125 | 5 |
By the rule of alligation, we have:
| C.P. of 1 litre of milk C.P. of 1 litre of water | |||||
| Re. 1 | Mean Price
| 0 | |||
|
|
||||
 Ratio of milk to water = |
4 | : | 1 | = 4 : 1. |
| 5 | 5 |
| Hence, percentage of water in the mixture = | |
1 | x 100 | % |
= 20%. |
| 5 |
Discussion:
65 comments Page 6 of 7.
Prabhat Ranjan said:
1 decade ago
I have very simple solution for the above problem, which is as follow:
Suppose we have 100 kg of milk @ Rs.1 per kg Cost price.
Total cost price = Rs.100.
Profit is given 25%, therefore SP of 100kg milk = Rs. 125.
But according to question, he sells at CP. therefore he has to mix 25 litres of water.
Therefore % of water in mixture = 25*100/125 = 20%.
Suppose we have 100 kg of milk @ Rs.1 per kg Cost price.
Total cost price = Rs.100.
Profit is given 25%, therefore SP of 100kg milk = Rs. 125.
But according to question, he sells at CP. therefore he has to mix 25 litres of water.
Therefore % of water in mixture = 25*100/125 = 20%.
Ted said:
1 decade ago
You are assuming CP. AS rupee one for easy calculation. Thats all!
Anamika said:
1 decade ago
Where it is given that C.P. is rupee one?
Would you please explain.
Would you please explain.
Vishal said:
1 decade ago
Let the price of the milk is 100% and he is getting the profit of 25% so the selling price must be 125%.
Now according the formula:
[(x/x+100)*100]%
{if price is 25% more than original then the milk is [25/100+25*100]% less than}
So,
[25/125*100]% = 20%.
He is selling the milk mixed with 20% of water.
Now according the formula:
[(x/x+100)*100]%
{if price is 25% more than original then the milk is [25/100+25*100]% less than}
So,
[25/125*100]% = 20%.
He is selling the milk mixed with 20% of water.
Vikatakavee said:
1 decade ago
Let us consider C.P of the milk = Rs. 100 (milk is 100%).
--> S.P also = 100.
If you are getting 25% profit S.P = 1.25 C.P.
--> 100 = 1.25 C.P.
--> C.P = 80.
C.P 80 means 80% of milk. So remaining 20% water.
--> S.P also = 100.
If you are getting 25% profit S.P = 1.25 C.P.
--> 100 = 1.25 C.P.
--> C.P = 80.
C.P 80 means 80% of milk. So remaining 20% water.
Shikha said:
1 decade ago
CP of 1 liter of milk = Re1.
SP of 1 liter of milk = Re1(given).
Gain = 25%(for the mixture [M+W]).
CP of milk(mixture) = (SP*(100/100+gain)) = 1*100/125 = 4/5.
Hence by allegation rule,
Milk(old) water
CP = Re1(dearer) CP = 0(for milk)(cheaper)
Mixture
CP = 4/5(mean).
Cheaper:Dearer = (1-4/5)/(4/5-0) = 1:4.
Water : milk = 1:4.
Water% = 1/5*100 = 20%.
SP of 1 liter of milk = Re1(given).
Gain = 25%(for the mixture [M+W]).
CP of milk(mixture) = (SP*(100/100+gain)) = 1*100/125 = 4/5.
Hence by allegation rule,
Milk(old) water
CP = Re1(dearer) CP = 0(for milk)(cheaper)
Mixture
CP = 4/5(mean).
Cheaper:Dearer = (1-4/5)/(4/5-0) = 1:4.
Water : milk = 1:4.
Water% = 1/5*100 = 20%.
Roose said:
1 decade ago
I saw the important formula section but I'm still unable to understand the use of rule of allegation.
In every problem I come across I find it used in a diff manner.
Can someone explain it?
In every problem I come across I find it used in a diff manner.
Can someone explain it?
Vikas Rawat said:
1 decade ago
let assume milk to be 100..
After mixing water he gets profit of 25 i.e. he sell mixture (water+milk) at 125..
now percentage of water in full mixture is 25/125*100= 20%
After mixing water he gets profit of 25 i.e. he sell mixture (water+milk) at 125..
now percentage of water in full mixture is 25/125*100= 20%
Teena said:
1 decade ago
What is rule of alligation?
Swati said:
1 decade ago
Explain whole Question once again.
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