Aptitude - Alligation or Mixture - Discussion

Discussion Forum : Alligation or Mixture - General Questions (Q.No. 6)
6.
A dishonest milkman professes to sell his milk at cost price but he mixes it with water and thereby gains 25%. The percentage of water in the mixture is:
4%
6%
20%
25%
Answer: Option
Explanation:

Let C.P. of 1 litre milk be Re. 1

Then, S.P. of 1 litre of mixture = Re. 1, Gain = 25%.

C.P. of 1 litre mixture = Re. 100 x 1 = 4
125 5

By the rule of alligation, we have:

C.P. of 1 litre of milk C.P. of 1 litre of water
Re. 1 Mean Price
Re. 4
5
0
4
5
1
5

Ratio of milk to water = 4 : 1 = 4 : 1.
5 5

Hence, percentage of water in the mixture = 1 x 100 % = 20%.
5

Discussion:
65 comments Page 4 of 7.

Mohammad Mukthar said:   9 years ago
Let 100 liter of milk be 100Rs.

When 25% of water is added the total amt of mixture = 125 L (100L of milk and 25 L of water)
Therefore % of water in mixture is 25/125 * 100 = 20%.

Vijay said:   9 years ago
CP = 100
Added cp = 25
total = 125
Non genu = 100/125 = 4/5.

Equate value must less than = .1
profit =1 - 4/5,
1/5 = 20%.

PRAVIJA REDDY said:   9 years ago
I'm not able to understand the solution. So please someone help me to get it.

Sharvam Dave said:   9 years ago
If ingredient worth no value (water) is added to another ingredient of some value(milk), when the mixture (solution) is sold at cost of ingredient with some value and profit earned is 'P' percent, then amount of ingredient with no value(water) added = (P/100) x Amount of Milk.
Ratio of Water to Milk is P:100

If Solution is sold at some other rate than rate of milk, say K% higher or lower rate than milk, than;
Actual rate of solution = Rate of milk x (100+k)/100, when rate is K percent higher than rate of milk; and,
Actual rate of solution = Rate of milk x (100-k)/100, when rate is K percent lower than rate of milk.
Let the actual Rate be S,
Let P = S-100.
Ratio of Milk to Water is, P:100.

Mamta said:   8 years ago
I will not able to understand that please give me easy example's to understand.

Please, help me.

Naux said:   8 years ago
Say the vendor buys L liters of milk and the cost of this is X.
Now, the vendor mixes some amount of water so the quantity is becoming say (L+Z) the cost of this is X(original cost)+25/100(X) that would be 5X/4.

Cost---->quantity
X---->L
5X/4--->?
So, ? = 5L/4,
So (L+Z) = 5L/4,
Z =L/4,

So, that would be 25% right but the answer is 20%.

Reisang Kasar said:   8 years ago
Please someone help me.

How to find out the weight of the water mixed in gm per kilogram of milk?

Bhagyasri said:   8 years ago
Suppose Milk man have 100 litre he want sell same 100 litre by adding some water.

Milk...................100 litre(initially)
Milk+ water.......100 litre(after addition of milk)
So, milk = 100-water.

Now, cost price Rs/-100.
Because of 25% profit selling price Rs/-125
100 * 100 = (100-water) * 125.
Water = 20.
Out of 100 litre water quantity is 20 litre.
So, answer is 20%.
(2)

Siva said:   8 years ago
Simple.

Gain=25.
Total milk =125.
Then 25/125=20%.

Shree said:   7 years ago
Thank you all for explaining it.


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