Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 12)
12.
In what ratio must a grocer mix two varieties of tea worth Rs. 60 a kg and Rs. 65 a kg so that by selling the mixture at Rs. 68.20 a kg he may gain 10%?
Answer: Option
Explanation:
S.P. of 1 kg of the mixture = Rs. 68.20, Gain = 10%.
| C.P. of 1 kg of the mixture = Rs. |  |
100 | x 68.20 |  |
= Rs. 62. |
| 110 |
By the rule of alligation, we have:
| Cost of 1 kg tea of 1st kind. Cost of 1 kg tea of 2nd kind. | ||
| Rs. 60 | Mean Price Rs. 62 | Rs. 65 |
| 3 | 2 | |
Required ratio = 3 : 2.
Discussion:
23 comments Page 3 of 3.
It's me said:
4 years ago
Didn't understand !
(2)
DEVINDER SINGH said:
2 years ago
CP 1 = 60
CP2 = 65
CP of mixture = 62.
Explanation:
Because 68.20 is sp of mixture which comes after a 10 % gain.
So cp * 111% = 68.20.
CP of mix = 62alligation imposed when all quantity will in same unit cp1 ,cp2, cp mixture.
CP2 = 65
CP of mixture = 62.
Explanation:
Because 68.20 is sp of mixture which comes after a 10 % gain.
So cp * 111% = 68.20.
CP of mix = 62alligation imposed when all quantity will in same unit cp1 ,cp2, cp mixture.
Sylvester OgboluOtutu said:
21 hours ago
Let the two varieties of tea be represented by x & y.
It is given that:
60x + 65y = 1.10(x + y), abd;
1.10(x + y) = 68.20.
(x + y) = 68.20 รท 1.10.
(x + y) = 62.00.
Therefore;
60x + 65y = 62(x + y).
60x + 65y = 62x + 62y.
65y - 62y = 62x - 60x.
3y = 2x.
3y/2y = 2x/2y.
3/2 = x/y.
Therefore, the answer is x : y = 3 : 2.
It is given that:
60x + 65y = 1.10(x + y), abd;
1.10(x + y) = 68.20.
(x + y) = 68.20 รท 1.10.
(x + y) = 62.00.
Therefore;
60x + 65y = 62(x + y).
60x + 65y = 62x + 62y.
65y - 62y = 62x - 60x.
3y = 2x.
3y/2y = 2x/2y.
3/2 = x/y.
Therefore, the answer is x : y = 3 : 2.
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