Online Aptitude Test - Aptitude Test - Random



Loading...  Loading Test...

Instruction:

  • This is a FREE online test. DO NOT pay money to anyone to attend this test.
  • Total number of questions : 20.
  • Time alloted : 30 minutes.
  • Each question carry 1 mark, no negative marks.
  • DO NOT refresh the page.
  • All the best :-).


1.

(0.1667)(0.8333)(0.3333) is approximately equal to:
(0.2222)(0.6667)(0.1250)

A.
2
B.
2.40
C.
2.43
D.
2.50

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Given expression
= (0.3333) x (0.1667)(0.8333)
(0.2222) (0.6667)(0.1250)
= 3333 x
1 x 5
6 6
2222
2 x 125
3 1000
= 3 x 1 x 5 x 3 x 8
2 6 6 2
= 5
2
= 2.50

Learn more problems on : Decimal Fraction

Discuss about this problem : Discuss in Forum


2.

If a = 0.1039, then the value of 4a2 - 4a + 1 + 3a is:

A.
0.1039
B.
0.2078
C.
1.1039
D.
2.1039

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

4a2 - 4a + 1 + 3a = (1)2 + (2a)2 - 2 x 1 x 2a + 3a

   = (1 - 2a)2 + 3a

   = (1 - 2a) + 3a

   = (1 + a)

   = (1 + 0.1039)

   = 1.1039

Learn more problems on : Square Root and Cube Root

Discuss about this problem : Discuss in Forum


3.

The true discount on a bill of Rs. 540 is Rs. 90. The banker's discount is:

A.
Rs. 60
B.
Rs. 108
C.
Rs. 110
D.
Rs. 112

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

P.W. = Rs. (540 - 90) = Rs. 450.

S.I. on Rs. 450 = Rs. 90.

S.I. on Rs. 540 = Rs. 90 x 540 = Rs. 108.
450

B.D. = Rs. 108.

Learn more problems on : Banker's Discount

Discuss about this problem : Discuss in Forum


4.

A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:

A.
100 kmph
B.
110 kmph
C.
120 kmph
D.
130 kmph

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Let speed of the car be x kmph.

Then, speed of the train = 150 x = 3 x kmph.
100 2

75 - 75 = 125
x (3/2)x 10 x 60

75 - 50 = 5
x x 24

x = 25 x24 = 120 kmph.
5

Learn more problems on : Time and Distance

Discuss about this problem : Discuss in Forum


5.

A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.

A.
220 km
B.
224 km
C.
230 km
D.
234 km

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

(1/2)x + (1/2)x = 10
21 24

x + x = 20
21 24

15x = 168 x 20

x = 168 x 20 = 224 km.
15

Learn more problems on : Time and Distance

Discuss about this problem : Discuss in Forum


6.

A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?

A.
320 m
B.
350 m
C.
650 m
D.
Data inadequate

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Speed = ( 300 ( m/sec = 50 m/sec.
18 3

Let the length of the platform be x metres.

Then, ( x + 300 ( = 50
39 3

=> 3(x + 300) = 1950

=> x = 350 m.

Learn more problems on : Problems on Trains

Discuss about this problem : Discuss in Forum


7.

In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C:

A.
18 m
B.
20 m
C.
27 m
D.
9 m

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

A : B = 100 : 90.

A : C = 100 : 72.

B : C = B x A = 90 x 100 = 90 .
A C 100 72 72

When B runs 90 m, C runs 72 m.

When B runs 100 m, C runs 72 x 100 m = 80 m.
90

B can give C 20 m.

Learn more problems on : Races and Games

Discuss about this problem : Discuss in Forum


8.

How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?

A.
5
B.
10
C.
15
D.
20

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Since each desired number is divisible by 5, so we must have 5 at the unit place. So, there is 1 way of doing it.

The tens place can now be filled by any of the remaining 5 digits (2, 3, 6, 7, 9). So, there are 5 ways of filling the tens place.

The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.

Required number of numbers = (1 x 5 x 4) = 20.

Learn more problems on : Permutation and Combination

Discuss about this problem : Discuss in Forum


9.

Find the highest common factor of 36 and 84.

A.
4
B.
6
C.
12
D.
18

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

36 = 22 x 32

84 = 22 x 3 x 7

H.C.F. = 22 x 3 = 12.

Learn more problems on : Problems on H.C.F and L.C.M

Discuss about this problem : Discuss in Forum


10.

The G.C.D. of 1.08, 0.36 and 0.9 is:

A.
0.03
B.
0.9
C.
0.18
D.
0.108

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Given numbers are 1.08, 0.36 and 0.90.   H.C.F. of 108, 36 and 90 is 18,

H.C.F. of given numbers = 0.18.

Learn more problems on : Problems on H.C.F and L.C.M

Discuss about this problem : Discuss in Forum


11.

A man invested Rs. 4455 in Rs. 10 shares quoted at Rs. 8.25. If the rate of dividend be 12%, his annual income is:

A.
Rs. 207.40
B.
Rs. 534.60
C.
Rs. 648
D.
Rs. 655.60

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Number of shares = 4455 = 540.
8.25

Face value = Rs. (540 x 10) = Rs. 5400.

Annual income = Rs. 12 x 5400 = Rs. 648.
100

Learn more problems on : Stocks and Shares

Discuss about this problem : Discuss in Forum


12.

If log a + log b = log (a + b), then:
b a

A.
a + b = 1
B.
a - b = 1
C.
a = b
D.
a2 - b2 = 1

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

log a + log b = log (a + b)
b a

log (a + b) = log a x b = log 1.
b a

So, a + b = 1.

Learn more problems on : Logarithm

Discuss about this problem : Discuss in Forum


13.

The value of 1 + 1 + 1 is:
log3 60 log4 60 log5 60

A.
0
B.
1
C.
5
D.
60

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Given expression = log60 3 + log60 4 + log60 5
= log60 (3 x 4 x 5)
= log60 60
= 1.

Learn more problems on : Logarithm

Discuss about this problem : Discuss in Forum


14.

If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 512 is:

A.
2.870
B.
2.967
C.
3.876
D.
3.912

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

log5 512
= log 512
log 5
= log 29
log (10/2)
= 9 log 2
log 10 - log 2
= (9 x 0.3010)
1 - 0.3010
= 2.709
0.699
= 2709
699
= 3.876

Learn more problems on : Logarithm

Discuss about this problem : Discuss in Forum


15.

Free notebooks were distributed equally among children of a class. The number of notebooks each child got was one-eighth of the number of children. Had the number of children been half, each child would have got 16 notebooks. Total how many notebooks were distributed ?

A.
256
B.
432
C.
512
D.
640
E.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Let total number of children be x.

Then, x x 1 x = x x 16     x = 64.
8 2

Number of notebooks = 1 x2 = 1 x 64 x 64 = 512.
8 8

Learn more problems on : Simplification

Discuss about this problem : Discuss in Forum


16.

If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:

A.
4 days
B.
5 days
C.
6 days
D.
7 days

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.

Then, 6x + 8y = 1 and 26x + 48y = 1 .
10 2

Solving these two equations, we get : x = 1 and y = 1 .
100 200

(15 men + 20 boy)'s 1 day's work = 15 + 20 = 1 .
100 200 4

15 men and 20 boys can do the work in 4 days.

Learn more problems on : Time and Work

Discuss about this problem : Discuss in Forum


17.

A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in:

A.
5 days
B.
6 days
C.
10 days
D.
10 1 days
2

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

(B + C)'s 1 day's work = 1 + 1 = 7 .
9 12 36

Work done by B and C in 3 days = 7 x 3 = 7 .
36 12

Remaining work = 1 - 7 = 5 .
12 12

Now, 1 work is done by A in 1 day.
24

So, 5 work is done by A in 24 x 5 = 10 days.
12 12

Learn more problems on : Time and Work

Discuss about this problem : Discuss in Forum


18.

From a pack of 52 cards, two cards are drawn together at random. What is the probability of both the cards being kings?

A.
1
15
B.
25
57
C.
35
256
D.
1
221

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Let S be the sample space.

Then, n(S) = 52C2 = (52 x 51) = 1326.
(2 x 1)

Let E = event of getting 2 kings out of 4.

n(E) = 4C2 = (4 x 3) = 6.
(2 x 1)

P(E) = n(E) = 6 = 1 .
n(S) 1326 221

Learn more problems on : Probability

Discuss about this problem : Discuss in Forum


19.

If x = 3 + 22, then the value of x - 1 is:
x

A.
1
B.
2
C.
22
D.
33

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

x - 1 2 = x + 1 - 2
x x

   = (3 + 22) + 1 - 2
(3 + 22)

   = (3 + 22) + 1 x (3 - 22) - 2
(3 + 22) (3 - 22)

   = (3 + 22) + (3 - 22) - 2

   = 4.

x - 1 = 2.
x

Learn more problems on : Surds and Indices

Discuss about this problem : Discuss in Forum


20.

Some articles were bought at 6 articles for Rs. 5 and sold at 5 articles for Rs. 6. Gain percent is:

A.
30%
B.
33 1 %
3
C.
35%
D.
44%

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Suppose, number of articles bought = L.C.M. of 6 and 5 = 30.

C.P. of 30 articles = Rs. 5 x 30 = Rs. 25.
6

S.P. of 30 articles = Rs. 6 x 30 = Rs. 36.
5

Gain % = 11 x 100 % = 44%.
25

Learn more problems on : Profit and Loss

Discuss about this problem : Discuss in Forum


Submit your test now to view the Results and Statistics with answer explanation.