Online Aptitude Test - Aptitude Test - Random

Clearly, we have r = 3 cm and h = 4 cm.

Volume =	1	r2h =		1	x x 32 x 4	cm3	= 12 cm3.
	3			3

Sum = Rs.		50 x 100		= Rs. 500.
		2 x 5

Amount	= Rs. 500 x 1 + 5 2 100
	= Rs. 500 x 21 x 21 20 20
	= Rs. 551.25

C.I. = Rs. (551.25 - 500) = Rs. 51.25

C.P. = Rs.		100 - 4 +	1		= Rs. 96.25
			4

By investing Rs. 1552, income = Rs. 128.

By investing Rs. 97, income = Rs.		128	x 97		= Rs. 8.
		1552

Dividend = 8%

(0.04)-1.5 =		4		-1.5
		100

=		1		-(3/2)
		25

   = (25)^(3/2)

   = (5²)^(3/2)

   = (5)^{2 x (3/2)}

   = 5³

   = 125.

S.I. = Rs. (15500 - 12500) = Rs. 3000.

Rate =		100 x 3000	%	= 6%
		12500 x 4

Let man's rate upstream be x kmph.

Then, his rate downstream = 2x kmph.

(Speed in still water) : (Speed of stream) =		2x + x		:		2x - x
		2				2

=	3x	:	x
	2		2

   = 3 : 1.

  617.00
    6.017
    0.617
 +  6.0017
  --------
  629.6357
  --------- 

There are two series (8, 11, 14, 17, 20) and (7, 12, 17, 22) increasing by 3 and 5 respectively.

Capacity = r²h.

I gives, r² = 61600. This gives r.

II gives, h = 1.5 r.

Thus, I and II give the answer.

Again, III gives 2r = 880. This gives r.

So, II and III also give the answer.

Correct answer is (E).

Let AB be the lighthouse and C and D be the positions of the ships.

Then, AB = 100 m, ACB = 30° and ADB = 45°.

AB	= tan 30° =	1	AC = AB x 3 = 1003 m.
AC		3

AB	= tan 45° = 1         AD = AB = 100 m.
AD

CD = (AC + AD)	= (1003 + 100) m
	= 100(3 + 1)
	= (100 x 2.73) m
	= 273 m.

Let the required number of bottles be x.

More machines, More bottles (Direct Proportion)

More minutes, More bottles (Direct Proportion)

Machines	6	:	10		:: 270 : x
Time (in minutes)	1	:	4

6 x 1 x x = 10 x 4 x 270

x =	(10 x 4 x 270)
	(6)

x = 1800.

There is a meal for 200 children. 150 children have taken the meal.

Remaining meal is to be catered to 50 children.

Now, 200 children 120 men.

50 children		120	x 50		= 30 men.
		200

Let the sum be Rs. x.

I gives, S.I. = Rs. 7000 and T = 7 years.

II gives, Sum + S.I. for 5 years = 2 x Sum         Sum = S.I. for 5 years.

Now, S.I. for 7 years = Rs. 7000.

S.I. for 1 year = Rs.	7000	= Rs. 1000.
	7

Thus, I and II both are needed to get the answer.

Correct answer is (E).

Let the length of the train be x metres and its speed by y m/sec.

Then,	x	= 8         x = 8y
	y

Now,	x + 264	= y
	20

8y + 264 = 20y

y = 22.

Speed = 22 m/sec =		22 x	18		km/hr = 79.2 km/hr.
			5

Let, B.D = Re. 1.

Then, B.G. = Re.	3	.
	25

T.D. = (B.D. - B.G.) = Re.		1 -	3		= Re.	22	.
			25			25

Sum =		1 x (22/25)		= Rs.	22	.
		1-(22/25)			3

S.I. on Rs.	22	for 1	1	years is Re. 1.
	3		2

Rate =		100 x 1	%	= 100 = 9 1 %. 11 11
		22 x 3 3 2

Let the tens and units digit be x and y respectively. Then,

I. x + y = 8 and	x	=	1
	y		3

I gives, 4y = 24       y = 6.

So, x + 6 = 8       x = 2.

II. xy = 12 and	x	=	3
	y		1

II gives, x² = 36       x = 6.

So, 3y = 6       y = 2.

Therefore, Either I or II alone sufficient to answer.