# Online Aptitude Test - Aptitude Test - Random

Instruction:

• This is a FREE online test. DO NOT pay money to anyone to attend this test.
• Total number of questions : 20.
• Time alloted : 30 minutes.
• Each question carry 1 mark, no negative marks.
• DO NOT refresh the page.
• All the best :-).

1.

 (0.1667)(0.8333)(0.3333) is approximately equal to: (0.2222)(0.6667)(0.1250)

A.
 2
B.
 2.4
C.
 2.43
D.
 2.5

Explanation:

Given expression
 = (0.3333) x (0.1667)(0.8333) (0.2222) (0.6667)(0.1250)
= 3333 x
 1 x 5 6 6
2222
 2 x 125 3 1000
 = 3 x 1 x 5 x 3 x 8 2 6 6 2
 = 5 2
= 2.50

2.

If a = 0.1039, then the value of 4a2 - 4a + 1 + 3a is:

A.
 0.1039
B.
 0.2078
C.
 1.1039
D.
 2.1039

Explanation:

4a2 - 4a + 1 + 3a = (1)2 + (2a)2 - 2 x 1 x 2a + 3a

= (1 - 2a)2 + 3a

= (1 - 2a) + 3a

= (1 + a)

= (1 + 0.1039)

= 1.1039

3.

The true discount on a bill of Rs. 540 is Rs. 90. The banker's discount is:

A.
 Rs. 60
B.
 Rs. 108
C.
 Rs. 110
D.
 Rs. 112

Explanation:

P.W. = Rs. (540 - 90) = Rs. 450.

S.I. on Rs. 450 = Rs. 90.

 S.I. on Rs. 540 = Rs. 90 x 540 = Rs. 108. 450

B.D. = Rs. 108.

4.

A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:

A.
 100 kmph
B.
 110 kmph
C.
 120 kmph
D.
 130 kmph

Explanation:

Let speed of the car be x kmph.

 Then, speed of the train = 150 x = 3 x kmph. 100 2

 75 - 75 = 125 x (3/2)x 10 x 60

 75 - 50 = 5 x x 24

 x = 25 x24 = 120 kmph. 5

5.

A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.

A.
 220 km
B.
 224 km
C.
 230 km
D.
 234 km

Explanation:

 (1/2)x + (1/2)x = 10 21 24

 x + x = 20 21 24

15x = 168 x 20

 x = 168 x 20 = 224 km. 15

6.

A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?

A.
 320 m
B.
 350 m
C.
 650 m
D.

Explanation:

 Speed = 300 m/sec = 50 m/sec. 18 3

Let the length of the platform be x metres.

 Then, x + 300 = 50 39 3

3(x + 300) = 1950

x = 350 m.

7.

In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C:

A.
 18 m
B.
 20 m
C.
 27 m
D.
 9 m

Explanation:

A : B = 100 : 90.

A : C = 100 : 72.

 B : C = B x A = 90 x 100 = 90 . A C 100 72 72

When B runs 90 m, C runs 72 m.

 When B runs 100 m, C runs 72 x 100 m = 80 m. 90

B can give C 20 m.

8.

How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?

A.
 5
B.
 10
C.
 15
D.
 20

Explanation:

Since each desired number is divisible by 5, so we must have 5 at the unit place. So, there is 1 way of doing it.

The tens place can now be filled by any of the remaining 5 digits (2, 3, 6, 7, 9). So, there are 5 ways of filling the tens place.

The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.

Required number of numbers = (1 x 5 x 4) = 20.

9.

Find the highest common factor of 36 and 84.

A.
 4
B.
 6
C.
 12
D.
 18

Explanation:

36 = 22 x 32

84 = 22 x 3 x 7

H.C.F. = 22 x 3 = 12.

10.

The G.C.D. of 1.08, 0.36 and 0.9 is:

A.
 0.03
B.
 0.9
C.
 0.18
D.
 0.108

Explanation:

Given numbers are 1.08, 0.36 and 0.90.   H.C.F. of 108, 36 and 90 is 18,

H.C.F. of given numbers = 0.18.

11.

A man invested Rs. 4455 in Rs. 10 shares quoted at Rs. 8.25. If the rate of dividend be 12%, his annual income is:

A.
 Rs. 207.40
B.
 Rs. 534.60
C.
 Rs. 648
D.
 Rs. 655.60

Explanation:

 Number of shares = 4455 = 540. 8.25

Face value = Rs. (540 x 10) = Rs. 5400.

 Annual income = Rs. 12 x 5400 = Rs. 648. 100

12.

 If log a + log b = log (a + b), then: b a

A.
 a + b = 1
B.
 a - b = 1
C.
 a = b
D.
 a2 - b2 = 1

Explanation:

 log a + log b = log (a + b) b a

 log (a + b) = log a x b = log 1. b a

So, a + b = 1.

13.

 The value of 1 + 1 + 1 is: log3 60 log4 60 log5 60

A.
 0
B.
 1
C.
 5
D.
 60

Explanation:

 Given expression = log60 3 + log60 4 + log60 5 = log60 (3 x 4 x 5) = log60 60 = 1.

14.

If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 512 is:

A.
 2.87
B.
 2.967
C.
 3.876
D.
 3.912

Explanation:

log5 512
 = log 512 log 5
 = log 29 log (10/2)
 = 9 log 2 log 10 - log 2
 = (9 x 0.3010) 1 - 0.3010
 = 2.709 0.699
 = 2709 699
= 3.876

15.

Free notebooks were distributed equally among children of a class. The number of notebooks each child got was one-eighth of the number of children. Had the number of children been half, each child would have got 16 notebooks. Total how many notebooks were distributed ?

A.
 256
B.
 432
C.
 512
D.
 640
E.
 None of these

Explanation:

Let total number of children be x.

 Then, x x 1 x = x x 16     x = 64. 8 2

 Number of notebooks = 1 x2 = 1 x 64 x 64 = 512. 8 8

16.

If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:

A.
 4 days
B.
 5 days
C.
 6 days
D.
 7 days

Explanation:

Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.

 Then, 6x + 8y = 1 and 26x + 48y = 1 . 10 2

 Solving these two equations, we get : x = 1 and y = 1 . 100 200

 (15 men + 20 boy)'s 1 day's work = 15 + 20 = 1 . 100 200 4

15 men and 20 boys can do the work in 4 days.

17.

A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in:

A.
 5 days
B.
 6 days
C.
 10 days
D.
 10 1 days 2

Explanation:

 (B + C)'s 1 day's work = 1 + 1 = 7 . 9 12 36

 Work done by B and C in 3 days = 7 x 3 = 7 . 36 12

 Remaining work = 1 - 7 = 5 . 12 12

 Now, 1 work is done by A in 1 day. 24

 So, 5 work is done by A in 24 x 5 = 10 days. 12 12

18.

From a pack of 52 cards, two cards are drawn together at random. What is the probability of both the cards being kings?

A.
 1 15
B.
 25 57
C.
 35 256
D.
 1 221

Explanation:

Let S be the sample space.

 Then, n(S) = 52C2 = (52 x 51) = 1326. (2 x 1)

Let E = event of getting 2 kings out of 4.

 n(E) = 4C2 = (4 x 3) = 6. (2 x 1)

 P(E) = n(E) = 6 = 1 . n(S) 1326 221

19.

 If x = 3 + 22, then the value of x - 1 is: x

A.
 1
B.
 2
C.
 22
D.
 33

Explanation:

 x - 1 2 = x + 1 - 2 x x

 = (3 + 22) + 1 - 2 (3 + 22)

 = (3 + 22) + 1 x (3 - 22) - 2 (3 + 22) (3 - 22)

= (3 + 22) + (3 - 22) - 2

= 4.

 x - 1 = 2. x

20.

Some articles were bought at 6 articles for Rs. 5 and sold at 5 articles for Rs. 6. Gain percent is:

A.
 30%
B.
 33 1 % 3
C.
 35%
D.
 44%

Explanation:

Suppose, number of articles bought = L.C.M. of 6 and 5 = 30.

 C.P. of 30 articles = Rs. 5 x 30 = Rs. 25. 6

 S.P. of 30 articles = Rs. 6 x 30 = Rs. 36. 5

 Gain % = 11 x 100 % = 44%. 25