Online Aptitude Test - Aptitude Test - Random



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Instruction:

  • Total number of questions : 20.
  • Time alloted : 30 minutes.
  • Each question carry 1 mark, no negative marks.
  • DO NOT refresh the page.
  • All the best :-).

Direction (for Q.No. 1):

Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.

1.

What is the two-digit number?

I. 

Sum of the digits is 7.

II. 

Difference between the number and the number obtained by interchanging the digits is 9.

 III. 

Digit in the ten's place is bigger than the digit in the unit's place by 1.

A.
I and II only
B.
II and III only
C.
I and III only
D.
All I, II and III
E.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option E

Explanation:

Let the tens and units digit be x and y respectively.

  I. x + y = 7.

 II. (10x + y) - (10y + x) = 9       x - y = 1.

III. x - y = 1.

Thus, I and II as well as I and III give the answer.

Correct answer is (E).

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2.

The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

A.
101
B.
107
C.
111
D.
185

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Let the numbers be 37a and 37b.

Then, 37a x 37b = 4107

ab = 3.

Now, co-primes with product 3 are (1, 3).

So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).

Greater number = 111.

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3.

A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. The length of the train is:

A.
45 m
B.
50 m
C.
54 m
D.
72 m

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

2 kmph = ( 2 x 5 ( m/sec = 5 m/sec.
18 9

4 kmph = ( 4 x 5 ( m/sec = 10 m/sec.
18 9

Let the length of the train be x metres and its speed by y m/sec.

Then, ( x ( = 9 and ( x ( = 10.
y - 5
9
y - 10
9

Therefore 9y - 5 = x and 10(9y - 10) = 9x

=> 9y - x = 5 and 90y - 9x = 100.

On solving, we get: x = 50.

Therefore Length of the train is 50 m.

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4.

The cost of Type 1 rice is Rs. 15 per kg and Type 2 rice is Rs. 20 per kg. If both Type 1 and Type 2 are mixed in the ratio of 2 : 3, then the price per kg of the mixed variety of rice is:

A.
Rs. 18
B.
Rs. 18.50
C.
Rs. 19
D.
Rs. 19.50

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Let the price of the mixed variety be Rs. x per kg.

By rule of alligation, we have:

Cost of 1 kg of Type 1 rice Cost of 1 kg of Type 2 rice
Rs. 15 Mean Price
Rs. x
Rs. 20
(20 - x) (x - 15)

(20 - x) = 2
(x - 15) 3

60 - 3x = 2x - 30

5x = 90

x = 18.

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5.

In what ratio must a grocer mix two varieties of pulses costing Rs. 15 and Rs. 20 per kg respectively so as to get a mixture worth Rs. 16.50 kg?

A.
3 : 7
B.
5 : 7
C.
7 : 3
D.
7 : 5

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

By the rule of alligation:

Cost of 1 kg pulses of 1st kind Cost of 1 kg pulses of 2nd kind
Rs. 15 Mean Price
Rs. 16.50
Rs. 20
3.50 1.50

Required rate = 3.50 : 1.50 = 7 : 3.

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6.

What should come in place of both x in the equation x = 162 .
128 x

A.
12
B.
14
C.
144
D.
196

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Let x = 162
128 x

Then x2 = 128 x 162

   = 64 x 2 x 18 x 9

   = 82 x 62 x 32

   = 8 x 6 x 3

   = 144.

x = 144 = 12.

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7.

The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?

A.
23 years
B.
24 years
C.
25 years
D.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Let the average age of the whole team by x years.

11x - (26 + 29) = 9(x -1)

11x - 9x = 46

2x = 46

x = 23.

So, average age of the team is 23 years.

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8.

The average weight of 16 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class.

A.
47.55 kg
B.
48 kg
C.
48.55 kg
D.
49.25 kg

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Required average
= 50.25 x 16 + 45.15 x 8
16 + 8
= 804 + 361.20
24
= 1165.20
24
= 48.55

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9.

A library has an average of 510 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is:

A.
250
B.
276
C.
280
D.
285

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Since the month begins with a Sunday, to there will be five Sundays in the month.

Required average
= 510 x 5 + 240 x 25
30
= 8550
30
= 285

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10.

1 + 1 = ?
1 + a(n - m) 1 + a(m - n)

A.
0
B.
1
2
C.
1
D.
am + n

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

1 + 1 =
1  +  1
1 + an
am
1 + am
an
1 + a(n - m) 1 + a(m - n)

   = am + an
(am + an) (am + an)

   = (am + an)
(am + an)

   = 1.

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11.

(25)7.5 x (5)2.5 ÷ (125)1.5 = 5?

A.
8.5
B.
13
C.
16
D.
17.5
E.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Let (25)7.5 x (5)2.5 ÷ (125)1.5 = 5x.

Then, (52)7.5 x (5)2.5 = 5x
(53)1.5

5(2 x 7.5) x 52.5 = 5x
5(3 x 1.5)

515 x 52.5 = 5x
54.5

5x = 5(15 + 2.5 - 4.5)

5x = 513

x = 13.

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12.

A man rows to a place 48 km distant and come back in 14 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. The rate of the stream is:

A.
1 km/hr
B.
1.5 km/hr
C.
2 km/hr
D.
2.5 km/hr

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Suppose he move 4 km downstream in x hours. Then,

Speed downstream = 4 km/hr.
x

Speed upstream = 3 km/hr.
x

48 + 48 = 14 or x = 1 .
(4/x) (3/x) 2

So, Speed downstream = 8 km/hr, Speed upstream = 6 km/hr.

Rate of the stream = 1 (8 - 6) km/hr = 1 km/hr.
2

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13.

At what rate of compound interest per annum will a sum of Rs. 1200 become Rs. 1348.32 in 2 years?

A.
6%
B.
6.5%
C.
7%
D.
7.5%

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Let the rate be R% p.a.

Then, 1200 x 1 + R 2 = 1348.32
100

1 + R 2 = 134832 = 11236
100 120000 10000

1 + R 2 = 106 2
100 100

1 + R = 106
100 100

R = 6%

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14.

A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?

A.
7
B.
8
C.
9
D.
10
E.
11

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.

(2x + 2) + 2x + x = 27

5x = 25

x = 5.

Hence, B's age = 2x = 10 years.

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15.

A towel, when bleached, was found to have lost 20% of its length and 10% of its breadth. The percentage of decrease in area is:

A.
10%
B.
10.08%
C.
20%
D.
28%

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Let original length = x and original breadth = y.

Decrease in area
= xy - 80 x x 90 y
100 100
= xy - 18 xy
25
= 7 xy.
25

Decrease % = 7 xy x 1 x 100 % = 28%.
25 xy

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16.

In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was:

A.
2700
B.
2900
C.
3000
D.
3100

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Number of valid votes = 80% of 7500 = 6000.

Valid votes polled by other candidate = 45% of 6000

= 45 x 6000 = 2700.
100

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17.

The banker's discount on a bill due 4 months hence at 15% is Rs. 420. The true discount is:

A.
Rs. 400
B.
Rs. 360
C.
Rs. 480
D.
Rs. 320

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

T.D.
= B.D. x 100
100 + (R x T)
= Rs. 420 x 100
100 + 15 x 1
3
= Rs. 420 x 100
105
= Rs. 400.

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18.

If log10 5 + log10 (5x + 1) = log10 (x + 5) + 1, then x is equal to:

A.
1
B.
3
C.
5
D.
10

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

log10 5 + log10 (5x + 1) = log10 (x + 5) + 1

log10 5 + log10 (5x + 1) = log10 (x + 5) + log10 10

log10 [5 (5x + 1)] = log10 [10(x + 5)]

5(5x + 1) = 10(x + 5)

5x + 1 = 2x + 10

3x = 9

x = 3.

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19.

If logx y = 100 and log2 x = 10, then the value of y is:

A.
210
B.
2100
C.
21000
D.
210000

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

log 2 x = 10         x = 210.

logx y = 100

y = x100

y = (210)100     [put value of x]

y = 21000.

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Direction (for Q.No. 20):
Insert the missing number.
20.

7, 26, 63, 124, 215, 342, (....)

A.
481
B.
511
C.
391
D.
421

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Numbers are (23 - 1), (33 - 1), (43 - 1), (53 - 1), (63 - 1), (73 - 1) etc.

So, the next number is (83 - 1) = (512 - 1) = 511.

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