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Instruction:

  • Total number of questions : 20.
  • Time alloted : 30 minutes.
  • Each question carry 1 mark, no negative marks.
  • DO NOT refresh the page.
  • All the best :-).

1.

How many kilogram of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per kg so that there may be a gain of 10% by selling the mixture at Rs. 9.24 per kg?

A.
36 kg
B.
42 kg
C.
54 kg
D.
63 kg

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

S.P. of 1 kg of mixture = Rs. 9.24, Gain 10%.

C.P. of 1 kg of mixture = Rs. 100 x 9.24 = Rs. 8.40
110

By the rule of allilation, we have:

C.P. of 1 kg sugar of 1st kind Cost of 1 kg sugar of 2nd kind
Rs. 9 Mean Price
Rs. 8.40
Rs. 7
1.40 0.60

Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3.

Let x kg of sugar of 1st be mixed with 27 kg of 2nd kind.

Then, 7 : 3 = x : 27

x = 7 x 27 = 63 kg.
3

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2.

In what ratio must water be mixed with milk to gain 16% on selling the mixture at cost price?

A.
1 : 6
B.
6 : 1
C.
2 : 3
D.
4 : 3

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Let C.P. of 1 litre milk be Re. 1.

S.P. of 1 litre of mixture = Re.1, Gain = 50 %.
3

C.P. of 1 litre of mixture = 100 x 3 x 1 = 6
350 7

By the rule of alligation, we have:

C.P. of 1 litre of water C.P. of 1 litre of milk
0 Mean Price
Re. 6
7
Re. 1
1
7
6
7

Ratio of water and milk = 1 : 6 = 1 : 6.
7 7

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3.

A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?

A.
34
B.
40
C.
68
D.
88

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

We have: l = 20 ft and lb = 680 sq. ft.

So, b = 34 ft.

Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft.

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4.

Aman started a business investing Rs. 70,000. Rakhi joined him after six months with an amount of Rs.. 1,05,000 and Sagar joined them with Rs. 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Aman, Rakhi and Sagar respectively, 3 years after Aman started the business?

A.
7 : 6 : 10
B.
12 : 15 : 16
C.
42 : 45 : 56
D.
Cannot be determined

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Aman : Rakhi : Sagar = (70,000 x 36) : (1,05,000 x 30) : (1,40,000 x 24) = 12 : 15 : 16.

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5.

The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?

A.
4 years
B.
8 years
C.
10 years
D.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.

Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

5x = 20

x = 4.

Age of the youngest child = x = 4 years.

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6.

There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:

A.
20
B.
80
C.
100
D.
200

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Let the number of students in rooms A and B be x and y respectively.

Then, x - 10 = y + 10      x - y = 20 .... (i)

     and x + 20 = 2(y - 20)      x - 2y = -60 .... (ii)

Solving (i) and (ii) we get: x = 100 , y = 80.

The required answer A = 100.

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7.

A shopkeeper expects a gain of 22.5% on his cost price. If in a week, his sale was of Rs. 392, what was his profit?

A.
Rs. 18.20
B.
Rs. 70
C.
Rs. 72
D.
Rs. 88.25

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

C.P. = Rs. 100 x 392 = Rs. 1000 x 392 = Rs. 320
122.5 1225

Profit = Rs. (392 - 320) = Rs. 72.

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8.

A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:

A.
50 m
B.
150 m
C.
200 m
D.
Data inadequate

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Let the length of the train be x metres and its speed by y m/sec.

Then, x = 15     =>     y = x .
y 15

Therefore x + 100 = x
25 15

=> 15(x + 100) = 25x

=> 15x + 1500 = 25x

=> 1500 = 10x

=> x = 150 m.

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Direction (for Q.No. 9):
Insert the missing number.
9.

4, -8, 16, -32, 64, (....)

A.
128
B.
-128
C.
192
D.
-192

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Each number is the proceeding number multiplied by -2.

So, the required number is -128.

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10.

The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:

A.
4.37%
B.
5%
C.
6%
D.
8.75%

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Increase in 10 years = (262500 - 175000) = 87500.

Increase% = 87500 x 100 % = 50%.
175000

Required average = 50 % = 5%.
10

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11.

Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get?

A.
57%
B.
60%
C.
65%
D.
90%

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Total number of votes polled = (1136 + 7636 + 11628) = 20400.

Required percentage = 11628 x 100 % = 57%.
20400

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12.

Two numbers A and B are such that the sum of 5% of A and 4% of B is two-third of the sum of 6% of A and 8% of B. Find the ratio of A : B.

A.
2 : 3
B.
1 : 1
C.
3 : 4
D.
4 : 3

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

5% of A + 4% of B = 2  (6% of A + 8% of B)
3

5  A + 4  B = 2 6  A + 8  B
100 100 3 100 100

1  A + 1  B = 1  A + 4  B
20 25 25 75

1 - 1  A =  4 - 1  B
20 25 75 25

1  A = 1  B
100 75

A = 100 = 4 .
B 75 3

Required ratio = 4 : 3

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13.

The last day of a century cannot be

A.
Monday
B.
Wednesday
C.
Tuesday
D.
Friday

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

100 years contain 5 odd days.

Last day of 1st century is Friday.

200 years contain (5 x 2) 3 odd days.

Last day of 2nd century is Wednesday.

300 years contain (5 x 3) = 15 1 odd day.

Last day of 3rd century is Monday.

400 years contain 0 odd day.

Last day of 4th century is Sunday.

This cycle is repeated.

Last day of a century cannot be Tuesday or Thursday or Saturday.

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14.

If 5a = 3125, then the value of 5(a - 3) is:

A.
25
B.
125
C.
625
D.
1625

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

5a = 3125       5a = 55

a = 5.

5(a - 3) = 5(5 - 3) = 52 = 25.

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Direction (for Q.No. 15):

Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and

  • Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
  • Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
  • Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
  • Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
  • Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
15.

What is Sonia's present age?

I. 

Sonia's present age is five times Deepak's present age.

 II. 

Five years ago her age was twenty-five times Deepak's age at that time.

A.
I alone sufficient while II alone not sufficient to answer
B.
II alone sufficient while I alone not sufficient to answer
C.
Either I or II alone sufficient to answer
D.
Both I and II are not sufficient to answer
E.
Both I and II are necessary to answer

Your Answer: Option (Not Answered)

Correct Answer: Option E

Explanation:

 I. S = 5D    D = S ....(i)
5

II. S - 5 = 25 (D - 5)    S = 25D - 120 ....(ii)

Using (i) in (ii), we get S = 25 x S - 120
5

4S = 120.

S = 30.

Thus, I and II both together give the answer. So, correct answer is (E).

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16.

The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2 ?

A.
4
B.
8
C.
16
D.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.

Let ten's and unit's digits be 2x and x respectively.

Then, (10 x 2x + x) - (10x + 2x) = 36

9x = 36

x = 4.

Required difference = (2x + x) - (2x - x) = 2x = 8.

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17.

The angle between the minute hand and the hour hand of a clock when the time is 4.20, is:

A.
0
B.
10
C.
5
D.
20

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Angle traced by hour hand in 13 hrs = 360 x 13 = 130.
3 12 3

Angle traced by min. hand in 20 min. = 360 x 20 = 120.
60

Required angle = (130 - 120) = 10.

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18.

If 144 = 14.4 , then the value of x is:
0.144 x

A.
0.0144
B.
1.44
C.
14.4
D.
144

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

144 = 14.4
0.144 x

144 x 1000 = 14.4
144 x

x = 14.4 = 0.0144
1000

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19.

4.2 x 4.2 - 1.9 x 1.9 is equal to:
2.3 x 6.1

A.
0.5
B.
1.0
C.
20
D.
22

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Given Expression = (a2 - b2) = (a2 - b2) = 1.
(a + b)(a - b) (a2 - b2)

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20.

A boat running upstream takes 8 hours 48 minutes to cover a certain distance, while it takes 4 hours to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively?

A.
2 : 1
B.
3 : 2
C.
8 : 3
D.
Cannot be determined
E.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Let the man's rate upstream be x kmph and that downstream be y kmph.

Then, distance covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs.

x x 8 4 = (y x 4)
5

44 x =4y
5

y = 11 x.
5

Required ratio = y + x : y - x
2 2

   = 16x x 1 : 6x x 1
5 2 5 2

   = 8 : 3
5 5

   = 8 : 3.

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