Online Aptitude Test - Aptitude Test - Random



Loading...  Loading Test...

Instruction:

  • Total number of questions : 20.
  • Time alloted : 30 minutes.
  • Each question carry 1 mark, no negative marks.
  • DO NOT refresh the page.
  • All the best :-).

1.

What will be the day of the week 15th August, 2010?

A.
Sunday
B.
Monday
C.
Tuesday
D.
Friday

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 4 odd days.

Jan.  Feb.   March    April    May  June  July  Aug. 
(31 +  28  +  31   +   30   +  31  + 30  + 31  + 15) = 227 days

227 days = (32 weeks + 3 days) 3 odd days.

Total number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.

Given day is Sunday.

Learn more problems on : Calendar

Discuss about this problem : Discuss in Forum

2.

There is 60% increase in an amount in 6 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate?

A.
Rs. 2160
B.
Rs. 3120
C.
Rs. 3972
D.
Rs. 6240
E.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.

R = 100 x 60 = 10% p.a.
100 x 6

Now, P = Rs. 12000. T = 3 years and R = 10% p.a.

C.I.
= Rs. 12000 x 1 + 10 3 - 1
100
= Rs. 12000 x 331
1000
= 3972.

Learn more problems on : Compound Interest

Discuss about this problem : Discuss in Forum

3.

The correct expression of 6.46 in the fractional form is:

A.
646
99
B.
64640
1000
C.
640
100
D.
640
99

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

6.46  = 6 + 0.46  = 6 + 46   = 594 + 46   = 640 .
99 99 99

Learn more problems on : Decimal Fraction

Discuss about this problem : Discuss in Forum

4.

A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paise per sq. m, is:

A.
Rs. 456
B.
Rs. 458
C.
Rs. 558
D.
Rs. 568

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Area to be plastered = [2(l + b) x h] + (l x b)
= {[2(25 + 12) x 6] + (25 x 12)} m2
= (444 + 300) m2
= 744 m2.

Cost of plastering = Rs. 744 x 75 = Rs. 558.
100

Learn more problems on : Area

Discuss about this problem : Discuss in Forum

5.

A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?

A.
20
B.
24
C.
30
D.
33

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Let the side of the square(ABCD) be x metres.

Then, AB + BC = 2x metres.

AC = 2x = (1.41x) m.

Saving on 2x metres = (0.59x) m.

Saving % = 0.59x x 100 % = 30% (approx.)
2x

Learn more problems on : Area

Discuss about this problem : Discuss in Forum

6.

At what time, in minutes, between 3 o'clock and 4 o'clock, both the needles will coincide each other?

A.
5 1 "
11
B.
12 4 "
11
C.
13 4 "
11
D.
16 4 "
11

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

At 3 o'clock, the minute hand is 15 min. spaces apart from the hour hand.

To be coincident, it must gain 15 min. spaces.

55 min. are gained in 60 min.

15 min. are gained in 60 x 15 min = 16 4 min.
55 11

The hands are coincident at 16 4 min. past 3.
11

Learn more problems on : Clock

Discuss about this problem : Discuss in Forum

7.

The square root of 64009 is:

A.
253
B.
347
C.
363
D.
803

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

   2|64009( 253
    |4
    |----------
  45|240
    |225
    |----------
 503|  1509
    |  1509
    |----------
    |     X
    |---------- 

64009 = 253.

Learn more problems on : Square Root and Cube Root

Discuss about this problem : Discuss in Forum

8.

Reduce 128352 to its lowest terms.
238368

A.
3
4
B.
5
13
C.
7
13
D.
9
13

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

 128352) 238368 ( 1
         128352
         ---------------
         110016 ) 128352 ( 1
                  110016
                 ------------------  
                   18336 ) 110016 ( 6       
                           110016
                           -------
                                x
                           -------
 So, H.C.F. of 128352 and 238368 = 18336.
 
             128352     128352  18336    7
 Therefore,  ------  =  -------------- =  --
             238368     238368  18336    13                    

Learn more problems on : Problems on H.C.F and L.C.M

Discuss about this problem : Discuss in Forum

9.

Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?

A.
1
2
B.
3
4
C.
3
8
D.
5
16

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.

Then, E = {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3, 4),
     (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1),
     (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

n(E) = 27.

P(E) = n(E) = 27 = 3 .
n(S) 36 4

Learn more problems on : Probability

Discuss about this problem : Discuss in Forum

10.

If log10 5 + log10 (5x + 1) = log10 (x + 5) + 1, then x is equal to:

A.
1
B.
3
C.
5
D.
10

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

log10 5 + log10 (5x + 1) = log10 (x + 5) + 1

log10 5 + log10 (5x + 1) = log10 (x + 5) + log10 10

log10 [5 (5x + 1)] = log10 [10(x + 5)]

5(5x + 1) = 10(x + 5)

5x + 1 = 2x + 10

3x = 9

x = 3.

Learn more problems on : Logarithm

Discuss about this problem : Discuss in Forum

11.

If logx 9 = - 1 , then x is equal to:
16 2

A.
- 3
4
B.
3
4
C.
81
256
D.
256
81

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

logx 9 = - 1
16 2

x-1/2 = 9
16

1 = 9
x 16

x = 16
9

x = 16 2
9

x = 256
81

Learn more problems on : Logarithm

Discuss about this problem : Discuss in Forum

12.

Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar's age at present?

A.
16 years
B.
18 years
C.
20 years
D.
Cannot be determined
E.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.

Then, (6x + 6) + 4 = 11
(5x + 6) + 4 10

10(6x + 10) = 11(5x + 10)

5x = 10

x = 2.

Sagar's present age = (5x + 6) = 16 years.

Learn more problems on : Problems on Ages

Discuss about this problem : Discuss in Forum

13.

A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.

A.
220 km
B.
224 km
C.
230 km
D.
234 km

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

(1/2)x + (1/2)x = 10
21 24

x + x = 20
21 24

15x = 168 x 20

x = 168 x 20 = 224 km.
15

Learn more problems on : Time and Distance

Discuss about this problem : Discuss in Forum

Direction (for Q.No. 14):

Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and

  • Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
  • Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
  • Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
  • Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
  • Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
14.

What is the speed of the boat in still water?

I. 

It takes 2 hours to cover the distance between A and B downstream.

 II. 

It takes 4 hours to cover the distance between A and B upstream.

A.
I alone sufficient while II alone not sufficient to answer
B.
II alone sufficient while I alone not sufficient to answer
C.
Either I or II alone sufficient to answer
D.
Both I and II are not sufficient to answer
E.
Both I and II are necessary to answer

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Let AB = x km.

 I. Speed downstream = x km/hr
2

II. Speed upstream = x km/hr.
4

Speed of boat in still water = 1 x + x km/hr.
2 2 4

Thus, I and II both even do not give the answer.

Correct answer is (D).

Learn more problems on : Boats and Streams

Discuss about this problem : Discuss in Forum

Direction (for Q.No. 15):

Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.

15.

What is the present age of Tanya?

I. 

The ratio between the present ages of Tanya and her brother Rahul is 3 : 4 respectively.

II. 

After 5 years the ratio between the ages of Tanya and Rahul will be 4 : 5.

 III. 

Rahul is 5 years older than Tanya.

A.
I and II only
B.
II and III only
C.
I and III only
D.
All I, II and III
E.
Any two of the three

Your Answer: Option (Not Answered)

Correct Answer: Option E

Explanation:

  I. Let the present ages of Tanya and Rahul be 3x years and 4x years.

 II. After 5 years, (Tanya's age) : (Rahul's age) = 4 : 5.

III. (Rahul's age) = (Tanya's age) + 5.


From I and II, we get 3x + 5 = 4 . This gives x.
4x + 5 5

Tanya's age = 3x can be found. Thus, I and II give the answer.


From I and III, we get 4x = 3x + 5. This gives x.

Tanya's age = 3x can be found. Thus, I and III give the answer.


From III : Let Tanya's present age be t years.

Then Rahul's present age = (t + 5) years.

Thus, from II and III, we get : t = 4 . This gives t.
t + 5 5

Thus, II and III give the answer.

Correct answer is (E).

Learn more problems on : Problems on Ages

Discuss about this problem : Discuss in Forum

Direction (for Q.No. 16):

Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.

16.

What is the two-digit number?

I. 

The difference between the two-digit number and the number formed by interchanging the digits is 27.

II. 

The difference between the two digits is 3.

 III. 

The digit at unit's place is less than that at ten's place by 3.

A.
I and II only
B.
I and III only
C.
All I, II and III
D.
I, and either II or III
E.
Even with all I, II and III, answer cannot be give.

Your Answer: Option (Not Answered)

Correct Answer: Option E

Explanation:

Let the tens and units digit be x and y respectively.

  I. (10x + y) - (10y + x)       x - y = 3.

 II. x - y = 3.

III. x - y = 3.

Thus, even all the given three statements together do not give the answer.

Correct answer is (E).

Learn more problems on : Problems on Numbers

Discuss about this problem : Discuss in Forum

Direction (for Q.No. 17):
Find the odd man out.
17.

6, 9, 15, 21, 24, 28, 30

A.
28
B.
21
C.
24
D.
30

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Each of the numbers except 28, is a multiple of 3.

Learn more problems on : Odd Man Out and Series

Discuss about this problem : Discuss in Forum

18.

If A = x% of y and B = y% of x, then which of the following is true?

A.
A is smaller than B.
B.
A is greater than B
C.
Relationship between A and B cannot be determined.
D.
If x is smaller than y, then A is greater than B.
E.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option E

Explanation:

x% of y = x x y = y x x = y% of x
100 100

A = B.

Learn more problems on : Percentage

Discuss about this problem : Discuss in Forum

19.

The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is Rs. 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P is:

A.
3500
B.
4000
C.
4050
D.
5000

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Let P, Q and R represent their respective monthly incomes. Then, we have:

P + Q = (5050 x 2) = 10100 .... (i)

Q + R = (6250 x 2) = 12500 .... (ii)

P + R = (5200 x 2) = 10400 .... (iii)

Adding (i), (ii) and (iii), we get:  2(P + Q + R) = 33000  or   P + Q + R = 16500 .... (iv)

Subtracting (ii) from (iv), we get P = 4000.

P's monthly income = Rs. 4000.

Learn more problems on : Average

Discuss about this problem : Discuss in Forum

20.

A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?

A.
Rs. 375
B.
Rs. 400
C.
Rs. 600
D.
Rs. 800

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

C's 1 day's work = 1 - 1 + 1 = 1 - 7 = 1 .
3 6 8 3 24 24

A's wages : B's wages : C's wages = 1 : 1 : 1 = 4 : 3 : 1.
6 8 24

C's share (for 3 days) = Rs. 3 x 1 x 3200 = Rs. 400.
24

Learn more problems on : Time and Work

Discuss about this problem : Discuss in Forum

Submit your test now to view the Results and Statistics with answer explanation.


Have a question?

Ask your question now !