Online Aptitude Test - Aptitude Test - Random



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Instruction:

  • Total number of questions : 20.
  • Time alloted : 30 minutes.
  • Each question carry 1 mark, no negative marks.
  • DO NOT refresh the page.
  • All the best :-).


1.

A man invested Rs. 4455 in Rs. 10 shares quoted at Rs. 8.25. If the rate of dividend be 12%, his annual income is:

A.
Rs. 207.40
B.
Rs. 534.60
C.
Rs. 648
D.
Rs. 655.60

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Number of shares = 4455 = 540.
8.25

Face value = Rs. (540 x 10) = Rs. 5400.

Annual income = Rs. 12 x 5400 = Rs. 648.
100

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Direction (for Q.No. 2):

Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.

2.

What is the capacity of the cylindrical tank?

I. 

The area of the base is 61,600 sq. cm.

II. 

The height of the tank is 1.5 times the radius.

 III. 

The circumference of base is 880 cm.

A.
Only I and II
B.
Only II and III
C.
Only I and III
D.
Any two of the three
E.
Only II and either I or III

Your Answer: Option (Not Answered)

Correct Answer: Option E

Explanation:

Capacity = r2h.

I gives, r2 = 61600. This gives r.

II gives, h = 1.5 r.

Thus, I and II give the answer.

Again, III gives 2r = 880. This gives r.

So, II and III also give the answer.

Correct answer is (E).

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3.

A family consists of two grandparents, two parents and three grandchildren. The average age of the grandparents is 67 years, that of the parents is 35 years and that of the grandchildren is 6 years. What is the average age of the family?

A.
28  4 years
7
B.
31  5 years
7
C.
32  1 years
7
D.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Required average
= 67 x 2 + 35 x 2 + 6 x 3
2 + 2 + 3
= 134 + 70 + 18
7
= 222
7
= 31  5 years.
7

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4.

In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there?

A.
50
B.
100
C.
150
D.
200

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.

Then, sum of their values = Rs. 25x + 10 x 2x + 5 x 3x = Rs. 60x
100 100 100 100

60x = 30     x = 30 x 100 = 50.
100 60

Hence, the number of 5 p coins = (3 x 50) = 150.

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Direction (for Q.Nos. 5 - 6):
Find out the wrong number in the given sequence of numbers.
5.

5, 16, 6, 16, 7, 16, 9

A.
9
B.
7
C.
6
D.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Terms at odd places are 5, 6, 7, 8 etc. and each term at even place is 16.

So, 9 is wrong.

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6.

25, 36, 49, 81, 121, 169, 225

A.
36
B.
49
C.
121
D.
169

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

The numbers are squares of odd natural numbers, starting from 5 up to 15.

So, 36 is wrong.

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7.

A trader owes a merchant Rs. 10,028 due 1 year hence. The trader wants to settle the account after 3 months. If the rate of interest 12% per annum, how much cash should he pay?

A.
Rs. 9025.20
B.
Rs. 9200
C.
Rs. 9600
D.
Rs. 9560

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Required money = P.W. of Rs. 10028 due 9 months hence
= Rs. 10028 x 100
100 + 12 x 9
12
= Rs. 9200.

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8.

Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:

A.
4
B.
5
C.
6
D.
8

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)

  = H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

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Direction (for Q.No. 9):

Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and

  • Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
  • Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
  • Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
  • Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
  • Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
9.

A and B together can complete a task in 7 days. B alone can do it in 20 days. What part of the work was carried out by A?

I. 

A completed the job alone after A and B worked together for 5 days.

 II. 

Part of the work done by A could have been done by B and C together in 6 days.

A.
I alone sufficient while II alone not sufficient to answer
B.
II alone sufficient while I alone not sufficient to answer
C.
Either I or II alone sufficient to answer
D.
Both I and II are not sufficient to answer
E.
Both I and II are necessary to answer

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

B's 1 day's work = 1
20

(A+ B)'s 1 day's work = 1
7

 I. (A + B)'s 5 day's work = 5
7

Remaining work = 1 - 5 = 2 .
7 7

2 work was carried by A.
7

II. is irrelevant.

Correct answer is (A).

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10.

At what time between 4 and 5 o'clock will the hands of a watch point in opposite directions?

A.
45 min. past 4
B.
40 min. past 4
C.
50 4 min. past 4
11
D.
54 6 min. past 4
11

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

At 4 o'clock, the hands of the watch are 20 min. spaces apart.

To be in opposite directions, they must be 30 min. spaces apart.

Minute hand will have to gain 50 min. spaces.

55 min. spaces are gained in 60 min.

50 min. spaces are gained in 60 x 50 min. or 54 6 min.
55 11

Required time = 54 6 min. past 4.
11

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11.

8 litres are drawn from a cask full of wine and is then filled with water. This operation is performed three more times. The ratio of the quantity of wine now left in cask to that of water is 16 : 65. How much wine did the cask hold originally?

A.
18 litres
B.
24 litres
C.
32 litres
D.
42 litres

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Let the quantity of the wine in the cask originally be x litres.

Then, quantity of wine left in cask after 4 operations = x 1 - 8 4  litres.
x

x(1 - (8/x))4 = 16
x 81

1 - 8 4 = 2 4
x 3

x - 8 = 2
x 3

3x - 24 = 2x

x = 24.

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12.

Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.70 a kg to produce a mixture worth Rs. 6.30 a kg.

A.
1 : 3
B.
2 : 3
C.
3 : 4
D.
4 : 5

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

By the rule of alligation:

Cost of 1 kg of 1st kind Cost of 1 kg of 2nd kind
720 p Mean Price
630 p
570 p
60 90

Required ratio = 60 : 90 = 2 : 3.

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13.

Some articles were bought at 6 articles for Rs. 5 and sold at 5 articles for Rs. 6. Gain percent is:

A.
30%
B.
33 1 %
3
C.
35%
D.
44%

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Suppose, number of articles bought = L.C.M. of 6 and 5 = 30.

C.P. of 30 articles = Rs. 5 x 30 = Rs. 25.
6

S.P. of 30 articles = Rs. 6 x 30 = Rs. 36.
5

Gain % = 11 x 100 % = 44%.
25

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Direction (for Q.No. 14):
Insert the missing number.
14.

15, 31, 63, 127, 255, (....)

A.
513
B.
511
C.
517
D.
523

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Each number is double the preceding one plus 1.

So, the next number is (255 x 2) + 1 = 511.

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15.

The sum of the squares of three numbers is 138, while the sum of their products taken two at a time is 131. Their sum is:

A.
20
B.
30
C.
40
D.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Let the numbers be a, b and c.

Then, a2 + b2 + c2 = 138 and (ab + bc + ca) = 131.

(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) = 138 + 2 x 131 = 400.

(a + b + c) = 400 = 20.

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16.

Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is:

A.
3
20
B.
29
34
C.
47
100
D.
13
102

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Let S be the sample space.

Then, n(S) = 52C2 = (52 x 51) = 1326.
(2 x 1)

Let E = event of getting 1 spade and 1 heart.

n(E) = number of ways of choosing 1 spade out of 13 and 1 heart out of 13
= (13C1 x 13C1)
= (13 x 13)
= 169.

P(E) = n(E) = 169 = 13 .
n(S) 1326 102

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17.

A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream.

A.
2 hours
B.
3 hours
C.
4 hours
D.
5 hours

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Speed downstream = (13 + 4) km/hr = 17 km/hr.

Time taken to travel 68 km downstream = 68 hrs = 4 hrs.
17

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18.

A train travelling at a speed of 75 mph enters a tunnel 31/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?

A.
2.5 min
B.
3 min
C.
3.2 min
D.
3.5 min

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Total distance covered
= ( 7 + 1 ( miles
2 4
= 15 miles.
4

Therefore Time taken
= ( 15 ( hrs
4 x 75
= 1 hrs
20
= ( 1 x 60 ( min.
20
= 3 min.

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19.

The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?

A.
25% increase
B.
50% increase
C.
50% decrease
D.
75% decrease

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Let original length = x and original breadth = y.

Original area = xy.

New length = x .
2

New breadth = 3y.

New area = x x 3y = 3 xy.
2 2

Increase % = 1 xy x 1 x 100 % = 50%.
2 xy

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20.

Simple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on Rs. 4000 for 2 years at 10% per annum. The sum placed on simple interest is:

A.
Rs. 1550
B.
Rs. 1650
C.
Rs. 1750
D.
Rs. 2000

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

C.I.
= Rs. 4000 x 1 + 10 2 - 4000
100
= Rs. 4000 x 11 x 11 - 4000
10 10
= Rs. 840.

Sum = Rs. 420 x 100 = Rs. 1750.
3 x 8

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