Online Aptitude Test - Aptitude Test - Random



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Instruction:

  • Total number of questions : 20.
  • Time alloted : 30 minutes.
  • Each question carry 1 mark, no negative marks.
  • DO NOT refresh the page.
  • All the best :-).


1.

A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream.

A.
2 hours
B.
3 hours
C.
4 hours
D.
5 hours

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Speed downstream = (13 + 4) km/hr = 17 km/hr.

Time taken to travel 68 km downstream = 68 hrs = 4 hrs.
17

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2.

How many times are the hands of a clock at right angle in a day?

A.
22
B.
24
C.
44
D.
48

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

In 12 hours, they are at right angles 22 times.

In 24 hours, they are at right angles 44 times.

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3.

Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.70 a kg to produce a mixture worth Rs. 6.30 a kg.

A.
1 : 3
B.
2 : 3
C.
3 : 4
D.
4 : 5

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

By the rule of alligation:

Cost of 1 kg of 1st kind Cost of 1 kg of 2nd kind
720 p Mean Price
630 p
570 p
60 90

Required ratio = 60 : 90 = 2 : 3.

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4.

How many kilogram of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per kg so that there may be a gain of 10% by selling the mixture at Rs. 9.24 per kg?

A.
36 kg
B.
42 kg
C.
54 kg
D.
63 kg

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

S.P. of 1 kg of mixture = Rs. 9.24, Gain 10%.

C.P. of 1 kg of mixture = Rs. 100 x 9.24 = Rs. 8.40
110

By the rule of allilation, we have:

C.P. of 1 kg sugar of 1st kind Cost of 1 kg sugar of 2nd kind
Rs. 9 Mean Price
Rs. 8.40
Rs. 7
1.40 0.60

Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3.

Let x kg of sugar of 1st be mixed with 27 kg of 2nd kind.

Then, 7 : 3 = x : 27

x = 7 x 27 = 63 kg.
3

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5.

Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?

A.
10
B.
12
C.
15
D.
20

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Speed of the first train = ( 120 ( m/sec = 12 m/sec.
10

Speed of the second train = ( 120 ( m/sec = 8 m/sec.
15

Relative speed = (12 + 8) = 20 m/sec.

Therefore Required time = [ (120 + 120) ] sec = 12 sec.
20

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Direction (for Q.No. 6):

In each of the following questions, a question is asked and is followed by three statements. While answering the question, you may or may not require the data provided in all the statements. You have to read the question and the three statements and then decide whether the question can be answered with any one or two of the statements or all the three statements are required to answer the question. The answer number bearing the statements, which can be dispensed with, if any, while answering the question is your answer.

6.

Mr. Gupta borrowed a sum of money on compound interest. What will be the amount to be repaid if he is repaying the entire amount at the end of 2 years?

I. 

The rate of interest is 5 p.c.p.a.

II. 

Simple interest fetched on the same amount in one year is Rs. 600.

 III. 

The amount borrowed is 10 times the simple interest in 2 years.

A.
I only
B.
III only
C.
I or II only
D.
II and Either I or III only
E.
All I, II and III are required

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

  I. gives, Rate = 5% p.a.

 II. gives, S.I. for 1 year = Rs. 600.

III. gives, sum = 10 x (S.I. for 2 years).

Now I, and II give the sum.

For this sum, C.I. and hence amount can be obtained.

Thus, III is redundant.

Again, II gives S.I. for 2 years = Rs. (600 x 2) = Rs. 1200.

Now, from III, Sum = Rs. (10 x 1200) = Rs . 12000.

Thus, Rate = 100 x 1200 = 5% p.a.
2 x 12000

Thus, C.I. for 2 years and therefore, amount can be obtained.

Thus, I is redundant.

Hence, I or III redundant.

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Direction (for Q.Nos. 7 - 8):
Find the odd man out.
7.

3, 5, 11, 14, 17, 21

A.
21
B.
17
C.
14
D.
3

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Each of the numbers except 14 is an odd number.

The number '14' is the only EVEN number.

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8.

331, 482, 551, 263, 383, 362, 284

A.
263
B.
383
C.
331
D.
551

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

In each number except 383, the product of first and third digits is the middle one.

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Direction (for Q.No. 9):

Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and

  • Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
  • Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
  • Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
  • Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
  • Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
9.

Rahul, Anurag and Vivek started a business together. In what proportion would the annual profit be distributed among them?

I. 

Rahul got one-fourth of the profit.

 II. 

Rahul and Vivek contributed 75% of the total investment.

A.
I alone sufficient while II alone not sufficient to answer
B.
II alone sufficient while I alone not sufficient to answer
C.
Either I or II alone sufficient to answer
D.
Both I and II are not sufficient to answer
E.
Both I and II are necessary to answer

Your Answer: Option (Not Answered)

Correct Answer: Option E

Explanation:

Let the total investment be Rs. x.

Then, R = x
4

R + V = 75 x x = 3x
100 4

V = 3x - x = x .
4 4 2

A = x - x + x = x
4 2 4

R : A : V = x : x : x = 1 : 1 : 2.
4 4 2

Thus, both I and II are needed to get the answer.

Correct answer is (E).

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10.

A man standing at a point P is watching the top of a tower, which makes an angle of elevation of 30 with the man's eye. The man walks some distance towards the tower to watch its top and the angle of the elevation becomes 60. What is the distance between the base of the tower and the point P?

A.
43 units
B.
8 units
C.
12 units
D.
Data inadequate
E.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

One of AB, AD and CD must have given.

So, the data is inadequate.

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11.

If log 27 = 1.431, then the value of log 9 is:

A.
0.934
B.
0.945
C.
0.954
D.
0.958

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

log 27 = 1.431

log (33 ) = 1.431

3 log 3 = 1.431

log 3 = 0.477

log 9 = log(32 ) = 2 log 3 = (2 x 0.477) = 0.954.

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12.

If log10 7 = a, then log10 1 is equal to:
70

A.
- (1 + a)
B.
(1 + a)-1
C.
a
10
D.
1
10a

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

log10 1
70
= log10 1 - log10 70
= - log10 (7 x 10)
= - (log10 7 + log10 10)
= - (a + 1).

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13.

If logx y = 100 and log2 x = 10, then the value of y is:

A.
210
B.
2100
C.
21000
D.
210000

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

log 2 x = 10         x = 210.

logx y = 100

y = x100

y = (210)100     [put value of x]

y = 21000.

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Direction (for Q.No. 14):
Find out the wrong number in the series.
14.

19, 26, 33, 46, 59, 74, 91

A.
26
B.
33
C.
46
D.
59
E.
74

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Go on adding 7, 9, 11, 13, 15, 17 respectively to obtain the next number.

So, 33 is wrong. It must be 35

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15.

Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 2400. Their H.C.F. is:

A.
40
B.
80
C.
120
D.
200

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Let the numbers be 3x, 4x and 5x.

Then, their L.C.M. = 60x.

So, 60x = 2400 or x = 40.

The numbers are (3 x 40), (4 x 40) and (5 x 40).

Hence, required H.C.F. = 40.

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Direction (for Q.Nos. 16 - 17):
Insert the missing number.
16.

2, 4, 12, 48, 240, (....)

A.
960
B.
1440
C.
1080
D.
1920

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Go on multiplying the given numbers by 2, 3, 4, 5, 6.

So, the correct next number is 1440.

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17.

11, 13, 17, 19, 23, 29, 31, 37, 41, (....)

A.
43
B.
47
C.
53
D.
51

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Numbers are all primes. The next prime is 43.

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18.

Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?

A.
9
B.
10
C.
12
D.
20

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Due to stoppages, it covers 9 km less.

Time taken to cover 9 km = 9 x 60 min = 10 min.
54

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19.

An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1 hours, it must travel at a speed of:

A.
300 kmph
B.
360 kmph
C.
600 kmph
D.
720 kmph

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Distance = (240 x 5) = 1200 km.

Speed = Distance/Time

Speed = 1200/(5/3) km/hr.     [We can write 1 hours as 5/3 hours]

Required speed = 1200 x 3 km/hr = 720 km/hr.
5

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20.

A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:

A.

9 1 days
5

B.

9 2 days
5

C.

9 3 days
5

D.
10

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

(A + B + C)'s 1 day's work = 1 ,
4

A's 1 day's work = 1 ,
16

B's 1 day's work = 1 .
12

Therefore C's 1 day's work = 1 - ( 1 + 1 ) = ( 1 - 7 ) = 5 .
4 16 12 4 48 48

So, C alone can do the work in 48 = 9 3 days.
5 5

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