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- Total number of questions :
**20**. - Time alloted :
**30**minutes. - Each question carry 1 mark, no negative marks.
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1. | Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is: |
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Your Answer: Option (Not Answered) Correct Answer: Option C Explanation:
Volume of whole = (3 x 40) gallons = 120 gallons. Learn more problems on : Pipes and Cistern Discuss about this problem : Discuss in Forum |

2. | It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010? |
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Your Answer: Option (Not Answered) Correct Answer: Option C Explanation: On 31 Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days. On 31 Thus, on 1 Learn more problems on : Calendar Discuss about this problem : Discuss in Forum |

3. |
On 8 |
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Your Answer: Option (Not Answered) Correct Answer: Option D Explanation: The year 2006 is an ordinary year. So, it has 1 odd day. So, the day on 8 But, 8 8 Learn more problems on : Calendar Discuss about this problem : Discuss in Forum |

4. | To fill a tank, 25 buckets of water is required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to two-fifth of its present ? |
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Your Answer: Option (Not Answered) Correct Answer: Option C Explanation: Let the capacity of 1 bucket = Then, the capacity of tank = 25
= 62.5 Learn more problems on : Simplification Discuss about this problem : Discuss in Forum |

Find the odd man out. | ||||||||||||||||||||

5. | 10, 25, 45, 54, 60, 75, 80 |
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Your Answer: Option (Not Answered) Correct Answer: Option C Explanation:
Each of the numbers except 54 is multiple of 5.
Learn more problems on : Odd Man Out and Series Discuss about this problem : Discuss in Forum |

6. | A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500? |
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Your Answer: Option (Not Answered) Correct Answer: Option A Explanation: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009. Required sale = Rs. [ (6500 x 6) - 34009 ] = Rs. (39000 - 34009) = Rs. 4991. Learn more problems on : Average Discuss about this problem : Discuss in Forum |

7. | A library has an average of 510 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is: |
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Your Answer: Option (Not Answered) Correct Answer: Option D Explanation: Since the month begins with a Sunday, to there will be five Sundays in the month.
Learn more problems on : Average Discuss about this problem : Discuss in Forum |

8. | A works twice as fast as B. If B can complete a work in 12 days independently, the number of days in which A and B can together finish the work in : |
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Your Answer: Option (Not Answered) Correct Answer: Option A Explanation: Ratio of rates of working of A and B = 2 : 1. So, ratio of times taken = 1 : 2.
So, A and B together can finish the work in 4 days. Learn more problems on : Time and Work Discuss about this problem : Discuss in Forum |

9. | In how many different ways can the letters of the word 'MATHEMATICS' be arranged so that the vowels always come together? |
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Your Answer: Option (Not Answered) Correct Answer: Option C Explanation: In the word 'MATHEMATICS', we treat the vowels AEAI as one letter. Thus, we have MTHMTCS (AEAI). Now, we have to arrange 8 letters, out of which M occurs twice, T occurs twice and the rest are different.
Now, AEAI has 4 letters in which A occurs 2 times and the rest are different.
Required number of words = (10080 x 12) = 120960. Learn more problems on : Permutation and Combination Discuss about this problem : Discuss in Forum |

10. | Rs. 20 is the true discount on Rs. 260 due after a certain time. What will be the true discount on the same sum due after half of the former time, the rate of interest being the same? |
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Your Answer: Option (Not Answered) Correct Answer: Option B Explanation: S.I. on Rs. (260 - 20) for a given time = Rs. 20. S.I. on Rs. 240 for half the time = Rs. 10. T.D. on Rs. 250 = Rs. 10.
Learn more problems on : True Discount Discuss about this problem : Discuss in Forum |

11. | If the true discount on s sum due 2 years hence at 14% per annum be Rs. 168, the sum due is: |
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Your Answer: Option (Not Answered) Correct Answer: Option A Explanation:
Sum = (P.W. + T.D.) = Rs. (600 + 168) = Rs. 768. Learn more problems on : True Discount Discuss about this problem : Discuss in Forum |

12. | A sum of Rs. 12,500 amounts to Rs. 15,500 in 4 years at the rate of simple interest. What is the rate of interest? |
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Your Answer: Option (Not Answered) Correct Answer: Option D Explanation: S.I. = Rs. (15500 - 12500) = Rs. 3000.
Learn more problems on : Simple Interest Discuss about this problem : Discuss in Forum |

Find out the wrong number in the series. | |||||||||||||||||||||||||

13. | 190, 166, 145, 128, 112, 100, 91 |
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Your Answer: Option (Not Answered) Correct Answer: Option D Explanation: Go on subtracting 24, 21, 18, 15, 12, 9 from the numbers to get the next number. 190 - 24 = 166 166 - 21 = 145 145 - 18 = 127 [Here, 128 is placed instead of 127] 127 - 15 = 112 112 - 12 = 100 ... and so on. Therefore, 128 is wrong. Learn more problems on : Odd Man Out and Series Discuss about this problem : Discuss in Forum |

14. | 3889 + 12.952 - ? = 3854.002 |
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Your Answer: Option (Not Answered) Correct Answer: Option D Explanation: Let 3889 + 12.952 - Then = 3901.952 - 3854.002 = 47.95. Learn more problems on : Decimal Fraction Discuss about this problem : Discuss in Forum |

15. | The sum of three numbers is 98. If the ratio of the first to second is 2 :3 and that of the second to the third is 5 : 8, then the second number is: |
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Your Answer: Option (Not Answered) Correct Answer: Option B Explanation: Let the three parts be A, B, C. Then,
Learn more problems on : Ratio and Proportion Discuss about this problem : Discuss in Forum |

16. | The ratio of the number of boys and girls in a college is 7 : 8. If the percentage increase in the number of boys and girls be 20% and 10% respectively, what will be the new ratio? |
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Your Answer: Option (Not Answered) Correct Answer: Option C Explanation: Originally, let the number of boys and girls in the college be 7 Their increased number is (120% of 7
Learn more problems on : Ratio and Proportion Discuss about this problem : Discuss in Forum |

17. | Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case. |
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Your Answer: Option (Not Answered) Correct Answer: Option A Explanation: Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43) = H.C.F. of 48, 92 and 140 = 4. Learn more problems on : Problems on H.C.F and L.C.M Discuss about this problem : Discuss in Forum |

18. | A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour? |
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Your Answer: Option (Not Answered) Correct Answer: Option B Explanation:
= 2 m/sec. Converting m/sec to km/hr (see important formulas section)
= 7.2 km/hr. Learn more problems on : Time and Distance Discuss about this problem : Discuss in Forum |

19. | The square root of 64009 is: |
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Your Answer: Option (Not Answered) Correct Answer: Option A Explanation: 2| 64009 = 253. Learn more problems on : Square Root and Cube Root Discuss about this problem : Discuss in Forum |

20. | A fort had provision of food for 150 men for 45 days. After 10 days, 25 men left the fort. The number of days for which the remaining food will last, is: |
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Your Answer: Option (Not Answered) Correct Answer: Option C Explanation: After 10 days : 150 men had food for 35 days. Suppose 125 men had food for Now, 125 : 150
Learn more problems on : Chain Rule Discuss about this problem : Discuss in Forum |

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