The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:
A.
1
B.
2
C.
3
D.
4
Answer: Option B
Explanation:
Let the numbers 13a and 13b.
Then, 13a x 13b = 2028
ab = 12.
Now, the co-primes with product 12 are (1, 12) and (3, 4).
[Note: Two integers a and b are said to be coprime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ]
So, the required numbers are (13 x 1, 13 x 12) and (13 x 3, 13 x 4).
The difference between a two-digit number and the number obtained by interchanging the positions of its digits is 36. What is the difference between the two digits of that number?
A number consists of two digits. If the digits interchange places and the new number is added to the original number, then the resulting number will be divisible by:
A.
3
B.
5
C.
9
D.
11
Answer: Option D
Explanation:
Let the ten's digit be x and unit's digit be y.
Then, number = 10x + y.
Number obtained by interchanging the digits = 10y + x.
(10x + y) + (10y + x) = 11(x + y), which is divisible by 11.
A shopkeeper sells some toys at Rs. 250 each. What percent profit does he make? To find the answer, which of the following information given in Statements I and II is/are necessary?
I.
Number of toys sold.
II.
Cost price of each toy.
A.
Only I is necessary
B.
Only II is necessary
C.
Both I and II are necessary
D.
Either I or II ins necessary
E.
None of these
Answer: Option B
Explanation:
S.P. = Rs. 250 each.
To find gain percent, we must know the C.P. of each.
A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?
A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
10.
What is the length of a running train crossing another 180 metre long train running in the opposite direction?
I.
The relative speed of the two trains was 150 kmph.
II.
The trains took 9 seconds to cross each other.
A.
I alone sufficient while II alone not sufficient to answer
B.
II alone sufficient while I alone not sufficient to answer
C.
Either I or II alone sufficient to answer
D.
Both I and II are not sufficient to answer
E.
Both I and II are necessary to answer
Answer: Option E
Explanation:
Let the two trains of length a metres and b metres be moving in opposite directions at u m/s and v m/s.
The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?
A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
A.
2.91 m
B.
3 m
C.
5.82 m
D.
None of these
Answer: Option B
Explanation:
Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Loading Test...
ab = 12.
(10x + y) + (10y + x) = 11(x + y), which is divisible by 11.
m/sec
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log (2 x 3)