Discussion :: Operators and Assignments - Finding the output (Q.No.12)
| Tulshiram said: (Apr 26, 2013) | |
| In start () method x is local variable so, when twice() function call it update only 's' as class variable not x and also twice as return type is void means as know every one, that the reason answer will be 7 14. | |
| Radistao said: (Dec 5, 2015) | |
| System.out.print(x + " "); Hey, there is no place for second variable output! So, only x is being printed. please, fix the task description. |
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| Jayashree said: (Jul 24, 2016) | |
| Anyone can explain it briefly. | |
| Akshay S Y said: (Nov 10, 2016) | |
| In the start() method, int x variable is different for compiler, in other words if we can declare twice(int z) and z = z*2; which is assigned to s=(7*2)=14; But print method local variable x is called so value 7. In simple words, the above program they have declared with same variable name x instead of some other variable name which is treated as a different variable by the compiler. |
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| Aashish Chugh said: (Nov 26, 2016) | |
| When I executing this code the output came as (7, 0), anyone please explain why this come? | |
| Msheliga said: (Jan 28, 2017) | |
| The solution states that s is an instance variable. It should be corrected to note that s is a class (static) variable. | |
| Sachin said: (Mar 3, 2017) | |
| The int x in the twice() method is not the same int x as in the start() method. Why? Explain. | |
| Kajal said: (Nov 24, 2017) | |
| The output after executing the code: false true 0 Why? Please explain. |
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| Rasmi Ranjan Choudhury said: (Jun 1, 2018) | |
| @ALL. When you call p.start() method, it go to start method create local variable x=7. When you call twice(x) then x value 7 go to twice(int x) method and create another local variable. which is x scope is within the twice method. x=x*2 means x=7*2=14 , x=14 ,and 14 store in twice method x variable nt start() method bcoz twice method scope with in twice (){ ..open to close bracket.} s=x, here 14 assign to s and s is a static variable so class level variable s value changes the default value to 14, then finally it print x=7 and s=14. So, x 7 because start() value of x is 7 and twice method() x value not change start() x. Because after twice () end x value destroyed. |
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| Raj Patel said: (Aug 9, 2018) | |
| A local variable is for only their function so, after twice method new x value destroys and then consider the original x value is 7. So x=7 and s=14. |
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| Deepak Bansal said: (Sep 19, 2018) | |
| As I know a static variable can call by static method only but here twice is not a static method so how can it call s? | |
| Nikhil Pattanaik said: (Mar 18, 2022) | |
| Here, s is static variable. And static variables can only used by static methods or static blocks. So how can a non static twice method update the value of a static variable s. The s should be a class variable only not static. | |
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